cpu

I plan to replicate the statistics javascript from BBC News , but I'm intrigued by the CPU usage of that script (after you press the Start button). Can be an adding script so expensive? Can you tell me why that script is so CPU expensive? I'm new to javascript but i think that simple arithmetic operations are consuming too much client CPU. Is that ok? The sheer amount of numbers being increased are the source of the high CPU usage. On my AMD Phenom II X2, it runs up about 19% of CPU on Firefox when running it. The source of that page is actually http://www.realtimestatistics.org/ , and if you

armeabi、armeabi-v7a、mips、x86 、 arm64-v8a 如何理解？ ABI:指应用基于哪种指令集来进行编译，ABI以前总共有四种，分别是armeabi、armeabi-v7a、mips、x86，它们都是表示cpu的类型，现在又有了arm64-v8a。 （注意：以下所有讨论不包括mips） 先说以前对于so的平台兼容处理方式吧。 以前安卓都是32位系统，运行的进程都是32位，理论上armeabi的so可以被全平台兼容，所以，理论上我们可以只提供一个armeabi的so就能在所有cpu平台运行了。也就是说如果我们引入了A和B两个库，其中A提供了全平台的 armeabi、armeabi-v7a、x86三 个so，而B只有一个armeabi的so，那么我们可以把B的这个so复制到其他两个文件夹就可以被兼容了。 同时因为现在armeabi的设备比armeabi-v7的要少很多，所以有些应用直接提供了armeabi-v7的so。 现在有了arm64-v8a的CPU以及安卓64位系统，上面的方法就有点例外了。 在安卓64位系统上，同时运行着32位和64位的进程（这点和Windows很像，在64位Windows上也是能同时运行32位和63位的进程的）。 以下讨论是基于64位安卓系统上： 如果一个纯粹的java写的应用，没有使用任何的so，那么默认就应该以64位模式来运行；

I am using below programs on linux and windows to get cpu utilization of current processes. Linux: int main() { int ret; char *buf; int i=0; int who= RUSAGE_SELF; struct rusage usage; struct rusage *p=&usage; ret=getrusage(who,p); printf("user time used: %16lf %16lf\n",p->ru_utime.tv_sec,p->ru_utime.tv_usec); printf("system time used: %16lf %16lf\n",p->ru_stime.tv_sec,p->ru_stime.tv_usec); system("ls"); printf("user time used: %16lf %16lf\n",p->ru_utime.tv_sec,p->ru_utime.tv_usec); printf("system time used: %16lf %16lf\n", p->ru_stime.tv_sec,p->ru_stime.tv_usec); return 0; } Output on linux:

The wiki webpage( https://en.wikipedia.org/wiki/Sandy_Bridge ) mentioned that Data TLB has 64, 32 and 4 entries respectively for 4KB, 2MB and 1GB pages. I found these numbers hard to understand. Sandy Bridge has a virtual address of 48 bits, which means for 4K page, there can be 2^36 pages, and for 2MB and 1GB pages, there should be 2^27 and 2^18 pages. If TLB has 64 entries for 4K page, the size of each entry should be no less than 6+36 = 42 bits. Why are there only 32 entries for 2M page, instead of 2^15 (42-27) entries? I know in TLB entries there will be additional bits for control purpose

Is there a way to use HTML 5 to access local system hardware details? I'm looking specifically for attributes about CPU, RAM, Disk space, Video card information, Browsers available and plug-ins (with verson information). Ultimately, I am trying to determine if I can build a tool to check a machine for hardware requirements to run software but do so without needing to actually install anything on the machine. Any help is much appreciated! Thanks! Optimus Prime I don't know if HTML5 can help you but javascript can, more information on these websites. http://ajaxian.com/archives/jpu-javascript