counter

问题 I wanted to know if there is an effective way to create a counting mechanism on vba using a Worksheet_SelectionChange event? I want to count how many times a specific cell is selected. If the cell is selected then the variable will go up by one, otherwise no change is made to the variable. Dim S As String Dim count As Integer count = 0 S = "$" & "D" & "$" & ActiveCell.Row If ActiveCell.Address = S Then count = count + 1 Else count = count End If 回答1: This should work for you. Place this code

问题 I often come across the following common problem when cleaning the data there are some more common categories (let's say top 10 movie genres) and lots and lots of others which are sparse. Usual practice here would be to combine sparse genres into "Other" for example. Easily done when there are not many sparse categories: # Join bungalows as they are sparse classes into 1 df.property_type.replace(['Terraced bungalow','Detached bungalow', 'Semi-detached bungalow'], 'Bungalow', inplace=True) but

问题 I often come across the following common problem when cleaning the data there are some more common categories (let's say top 10 movie genres) and lots and lots of others which are sparse. Usual practice here would be to combine sparse genres into "Other" for example. Easily done when there are not many sparse categories: # Join bungalows as they are sparse classes into 1 df.property_type.replace(['Terraced bungalow','Detached bungalow', 'Semi-detached bungalow'], 'Bungalow', inplace=True) but

问题 Python 2.7/3.1 introduced the awesome collections.Counter . My question: How do I count how many "element appearances" a counter has? I want this: len(list(counter.elements())) But shorter. 回答1: sum(counter.itervalues()) 来源： https://stackoverflow.com/questions/5506359/checking-number-of-elements-in-pythons-counter

问题 Trying to have a counter on a web page that does not restart on each different page view within the same user session. Currently using this code (thanks to Praveen Kumar Purushothaman) but this counter resets every time a different page is viewed. setTimeout(start, 0); var i = 0; var num = document.getElementById("number"); function start() { increase(); setInterval(increase, 1000); } function increase() { if (i < 100000) { i += 10.41; num.innerText = i.toFixed(2); } } <span id="number"><

问题 Trying to have a counter on a web page that does not restart on each different page view within the same user session. Currently using this code (thanks to Praveen Kumar Purushothaman) but this counter resets every time a different page is viewed. setTimeout(start, 0); var i = 0; var num = document.getElementById("number"); function start() { increase(); setInterval(increase, 1000); } function increase() { if (i < 100000) { i += 10.41; num.innerText = i.toFixed(2); } } <span id="number"><

问题 Trying to have a counter on a web page that does not restart on each different page view within the same user session. Currently using this code (thanks to Praveen Kumar Purushothaman) but this counter resets every time a different page is viewed. setTimeout(start, 0); var i = 0; var num = document.getElementById("number"); function start() { increase(); setInterval(increase, 1000); } function increase() { if (i < 100000) { i += 10.41; num.innerText = i.toFixed(2); } } <span id="number"><

问题 Basically what I'm looking for is the PHP version of this thread: Find, replace, and increment at each occurence of string I would like to replace the keyword following > at the start of rach line with an incrementing counter. If my input is: >num, blah, blah, blah ATCGACTGAATCGA >num, blah, blah, blah ATCGATCGATCGATCG >num, blah, blah, blah ATCGATCGATCGATCG I would like it to be... >0, blah, blah, blah ATCGACTGAATCGA >1, blah, blah, blah ATCGATCGATCGATCG >2, blah, blah, blah ATCGATCGATCGATCG

问题 So first off, I'm completely brand new to Java and I know this is probably really easy for most of you. But right now I'm stuck with an exercise. I have googled almost frantically, but I can't find any helpful tips to this particular problem. That or I don't really know what to search for. I have a piece of code that looks like this: import java.util.Scanner; public class Week { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println("Type a number:

问题 This question already has answers here : Add column with order counts (2 answers) Count number of rows within each group (15 answers) Closed 5 years ago . What is the easiest way to count the occurrences of a an element on a vector or data.frame at every grouop? I don't mean just counting the total (as other stackoverflow questions ask) but giving a different number to every succesive occurence. for example for this simple dataframe: (but I will work with dataframes with more columns) mydata