count

问题 For example, if we have a table Books, how would we count total number of book records with hibernate? 回答1: For older versions of Hibernate (<5.2): Assuming the class name is Book: return (Number) session.createCriteria("Book") .setProjection(Projections.rowCount()) .uniqueResult(); It is at least a Number , most likely a Long . 回答2: In Java i usually need to return int and use this form: int count = ((Long)getSession().createQuery("select count(*) from Book").uniqueResult()).intValue(); 回答3:

问题 i was assigned to make some changes to a C program written by someone else...i want to understand it first to work on it properly...i came upon a function that generates the histogram of ASCII values from a given long string of data. it is something like this. //load the symbols the old data for(int k = 0;k < 256;++k) { sym[k].Symbol = k; sym[k].Count = 0; } //Creating the probability distribution for each of the source symbols. for(int k = size;k;--k) { sym[*in ++].Count ++; } here 'in' is

问题 i was assigned to make some changes to a C program written by someone else...i want to understand it first to work on it properly...i came upon a function that generates the histogram of ASCII values from a given long string of data. it is something like this. //load the symbols the old data for(int k = 0;k < 256;++k) { sym[k].Symbol = k; sym[k].Count = 0; } //Creating the probability distribution for each of the source symbols. for(int k = size;k;--k) { sym[*in ++].Count ++; } here 'in' is

问题 Given the following list or tuple: list: [UURRUULLLRRDDDBBBUUU] Step 1: Count how many times an "U" character repeats before a new "unknown2 (R or D or B or L?)" character appears and records (number of repetitions + letter of the respective "U" character) Step2: Continued from Step 1: Count how many times the "unknown2" character repeats until a new character other than "unknown2" appears. or equal to the "U" character and record (number of repetitions + letter of the respective "unknown2"

问题 I looked over PHPDelusions website few times before asking this, as well as used Google but I still can't seem to get the code to work, or find a solution that remotely mirrors my question in general. I made a super simple PHP7 script for managing Receipts. The fields are simple. id (int 12), amount (varchar 8), category (int 2), date (date) The problem I'm facing is I'm trying to Count the Total Amount of money based on Categories . So let's say Category = 1 would count all Amounts with that

问题 I want to get a data.frame like the one below, but including all years per topic. This one I made counts the number of items by year for each topic but when there is no item in some year, it just doesn't create that row for that particular topic, and it's blank in the final graph. Could anyone please tell me how to add the missing year with Count == 0 for the topics that have no value? dtd2 <- structure(list(Topic = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,

问题 I want to get a data.frame like the one below, but including all years per topic. This one I made counts the number of items by year for each topic but when there is no item in some year, it just doesn't create that row for that particular topic, and it's blank in the final graph. Could anyone please tell me how to add the missing year with Count == 0 for the topics that have no value? dtd2 <- structure(list(Topic = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,

问题 fieldnames = ['first_name', 'last_name', 'address'] with open('names.csv') as csvfile: reader = csv.DictReader(csvfile, fieldnames=fieldnames) for row in reader: print(row['first_name'], "'s number", row['last_name'], "address", row['adres']) This is my code to print my CSV file. If the CSV file is empty, I want to print that it's empty. I thought that if i can get the row count of the file, I can check if it's empty. 回答1: just do len(list(reader)) it iterates through the reader object to

问题 Using a batch script (.bat file) in windows xp, how would I go about reading a text file and finding how many instances of a character exists? For example, I have a string with the following: ""OIJEFJ"JOIEJKAJF"""LKAJFKLJEIJ""JKLFJALKJF"LKJLKFA""""LKJKLFJLKADJF I want it to count how many " there are in the file and return the count. 回答1: Let's start counting the characters in a line. First the slow and clear method: set i=-1 set n=0 :nextChar set /A i+=1 set c=!theLine:~%i%,1! if "!c!" == ""

问题 I have a data frame that looks like this: dat <- structure(list(Geocode = c("1100015", "1100023", "1100031", "1100049", "1100056", "1100064", "1100072", "1100080", "1100098", "1100106", "1100114", "1100122", "1100130", "1100148", "1100155", "1100189", "1100205", "1100254", "1100262", "1100288", "1100296", "1100304", "1100320", "1100338", "1100346", "1100379", "1100403", "1100452", "1100502", "1100601"), Location = c("Alta Floresta D'oeste, RO", "Ariquemes, RO", "Cabixi, RO", "Cacoal, RO",