count

问题 I have a table, let's call them SUMMARYDATA NIP NAME DEPARTMENT STATUSIN STATUSOUT LATECOME ------------------------------------------------------------------------------------------------ A1 ARIA BB 2020-01-21 08:06:23 2020-01-21 11:58:36 00:06:23 A1 ARIA BB 2020-01-22 07:34:27 2020-01-22 17:19:47 00:00:00 A1 ARIA BB 2020-01-23 08:30:00 2020-01-23 11:00:00 00:30:00 A1 ARIA BB 2020-01-24 08:05:00 2020-01-24 10:30:00 00:05:00 A2 BELLE BB 2020-01-21 07:06:20 2020-01-21 13:58:31 00:00:00 A2

问题 I would like to count all issues on my gitlab project using api. Below the command that I'm using: curl --header "PRIVATE-TOKEN:xxxxxxx" https://gitlab.myapp.com/api/v4/groups/xx/issues?scope=all I've also tried to replace groups with project. We would like to bypass the pagination problem: the displayed results are always 100 (the max number). How can we could get more than 100 ? I would like to have as result only the total number of issue on my project. 回答1: for anyone interestered I fixed

问题 I have the following query select main_cat_name,cat_url from mf_main order by main_cat_name This returns whole data of my table.Now i want to have count of the total rows of this table.I can do it using another query but how can i use them in one single query??? I want two data ONE :- the rows of the table TWO:- the count how can i have that in one single query I tried this but it gives correct count but displays only first row of the table : select count(cat_id),main_cat_name,cat_url from mf

问题 I have the following query select main_cat_name,cat_url from mf_main order by main_cat_name This returns whole data of my table.Now i want to have count of the total rows of this table.I can do it using another query but how can i use them in one single query??? I want two data ONE :- the rows of the table TWO:- the count how can i have that in one single query I tried this but it gives correct count but displays only first row of the table : select count(cat_id),main_cat_name,cat_url from mf

问题 Is there a simple way to retrieve a list of all unique values in a column, along with how many times that value appeared? Example dataset: A A A B B C ... Would return: A | 3 B | 2 C | 1 回答1: Use GROUP BY: select value, count(*) from table group by value Use HAVING to further reduce the results, e.g. only values that occur more than 3 times: select value, count(*) from table group by value having count(*) > 3 回答2: SELECT id,COUNT(*) FROM file GROUP BY id 来源： https://stackoverflow.com

问题 I have the following table pet in the database menagerie : +--------+-------------+---------+------+------------+------------+ | name | owner | species | sex | birth | death | +--------+-------------+---------+------+------------+------------+ | Tommy | Salman Khan | Lebre | NULL | 1999-01-13 | 0000-00-00 | | Bowser | Diane | dog | m | 1981-08-31 | 1995-07-29 | +--------+-------------+---------+------+------------+------------+ Now If I run the following query: select owner, curdate() from

问题 I have a dataframe (called df), where there is a time series with a time stamp (first column) and several integer data columns. TimeStamp Country 1 Country 2 12:00:00 10.05 21.60 11:59:00 11.12 22.33 11:58:00 12.18 21.70 11:57:00 11.70 21.60 11:56:00 11.65 22.33 11:55:00 11.70 21.60 11:54:00 11.50 22.33 11:53:00 11.80 21.80 ... ... ... Problem: I'd like to count the number of occurrences of a the maximum in a specific range (not the whole axis!). E.g. In column Country 2, I'd like to count

问题 I have a dataframe (called df), where there is a time series with a time stamp (first column) and several integer data columns. TimeStamp Country 1 Country 2 12:00:00 10.05 21.60 11:59:00 11.12 22.33 11:58:00 12.18 21.70 11:57:00 11.70 21.60 11:56:00 11.65 22.33 11:55:00 11.70 21.60 11:54:00 11.50 22.33 11:53:00 11.80 21.80 ... ... ... Problem: I'd like to count the number of occurrences of a the maximum in a specific range (not the whole axis!). E.g. In column Country 2, I'd like to count

问题 I have created a code which basically generates a random 20 digit number. Code below: import random from random import randint n=20 def digit(n): range_start = 10**(n-1) range_end = (10**n)-1 return randint(range_start, range_end+1) print(digit(n)) The output of this code for example is: 49690101904335902069 Now given this code I'm just wondering how I can go about to counting the number of zeros in the output, so essentially I'm trying to create a new function called count_zero(): , but I

问题 This question already has answers here : python count duplicate in list (6 answers) Closed 2 years ago . I am trying to construct this function but I can't work out how to stop the function counting the same duplicate more than once. Can someone help me please? def count_duplicates(seq): '''takes as argument a sequence and returns the number of duplicate elements''' fir = 0 sec = 1 count = 0 while fir < len(seq): while sec < len(seq): if seq[fir] == seq[sec]: count = count + 1 sec = sec + 1