composite-key

Database Design: Composite key vs one column primary key

Deadly 提交于 2019-12-01 09:38:56
问题 A web application I am working on has encountered an unexpected 'bug' - The database of the app has two tables (among many others) called 'States' and 'Cities'. ' States ' table fields: ------------------------------------------- idStates | State | Lat | Long ------------------------------------------- ' idStates ' is an auto-incrementing primary key. ' Cities ' table fields: ---------------------------------------------------------- idAreaCode | idStates | City | Lat | Long -----------------

composite key in web2py

无人久伴 提交于 2019-12-01 00:30:29
I have a table defined in web2py db.define_table( 'pairing', Field('user',writable=True,readable=True), Field('uid', writable=True , readable=True) ) This table needs to have user and uid combination being unique. I have looked through the web2py documentation , but there isn't direct way to define composite key . How do we define composite way in web2py It depends on what you are trying to do. By default, web2py automatically creates an auto-incrementing id field to serve as the primary key for each table, and that is the recommended approach whenever possible. If you are dealing with a

composite key in web2py

天涯浪子 提交于 2019-11-30 20:16:47
问题 I have a table defined in web2py db.define_table( 'pairing', Field('user',writable=True,readable=True), Field('uid', writable=True , readable=True) ) This table needs to have user and uid combination being unique. I have looked through the web2py documentation , but there isn't direct way to define composite key . How do we define composite way in web2py 回答1: It depends on what you are trying to do. By default, web2py automatically creates an auto-incrementing id field to serve as the primary

MySQL only insert new row if combination of columns (which allow duplicates) is unique

江枫思渺然 提交于 2019-11-30 16:57:07
Since IF EXISTS isn't supported by MySQL I am struggling to think of the syntax for doing something like the following pseudo in MySQL: IF ((select count(*) from table where col1='var1' AND col2='var2' AND col3='var3' AND col4='var4' AND col5='var5')>0) then combination of vars exist in record - do a thing; ELSE combination of vars does not exist in record - insert record; END IF; I should have thought CASE would suit this but for life of me I'm unable to think of the correct syntax. I'd use unique indexes but every one of the columns needs to allow duplicates, it's only a matching combination

Misunderstanding on Composite Key for Cassandra

烂漫一生 提交于 2019-11-30 09:28:53
I've to test different datamodels for Cassandra. I'm thinking about to use a composite key made by key1:key2 for the row key. With this configuration on Cassandra, for example, I can query to have all the rows having a specific key1 value and any key2 value but It's impossible otherwise (obtain all the rows having a specific key2's value and any key1). Is it right? thanks in advance Cesare libjack If you use Order Preserving Partitioning (OPP), then yes, the keys will be stored sorted, and then you can get slices over a range of keys e.g. A:A to A:Z -- but not necessarily any:A to any:Z. But,

Hadoop - composite key

岁酱吖の 提交于 2019-11-30 06:46:54
问题 Suppose I have a tab delimited file containing user activity data formatted like this: timestamp user_id page_id action_id I want to write a hadoop job to count user actions on each page, so the output file should look like this: user_id page_id number_of_actions I need something like composite key here - it would contain user_id and page_id. Is there any generic way to do this with hadoop? I couldn't find anything helpful. So far I'm emitting key like this in mapper: context.write(new Text

JPA table with 2 primary key fields

纵然是瞬间 提交于 2019-11-30 03:54:14
I have a table which contains only 2 fields. The table has a composite PK formed by these two fields. When using Netbeans for creating entity beans from database, the entity bean is not created automatically like other tables that have more than 2 fields. So I guess I need to create the entity bean myself. What is the best practice for creating this entity bean? Does it have to contain COMPOSITE KEY object or not? Xavi López I don't use NetBeans so I can't really say anything about its mapping tools. For mapping a composite key, there are a couple of options. You can Define a separate

MySQL only insert new row if combination of columns (which allow duplicates) is unique

假装没事ソ 提交于 2019-11-29 23:48:54
问题 Since IF EXISTS isn't supported by MySQL I am struggling to think of the syntax for doing something like the following pseudo in MySQL: IF ((select count(*) from table where col1='var1' AND col2='var2' AND col3='var3' AND col4='var4' AND col5='var5')>0) then combination of vars exist in record - do a thing; ELSE combination of vars does not exist in record - insert record; END IF; I should have thought CASE would suit this but for life of me I'm unable to think of the correct syntax. I'd use

How to define @OneToMany in parent entity when child has composite PK?

☆樱花仙子☆ 提交于 2019-11-29 16:48:45
My Parent class has two child classes: Child and ParentHobby . The Child class has a singular PK and the @OneToMany mapping on it works. The problem is that I don't know how to map it on the ParentHobby class, which has a composite PK. Parent: //this works @OneToMany(cascade = CascadeType.ALL, mappedBy = "parent", fetch = FetchType.EAGER) private List<Child> childList; //this DOES NOT work @OneToMany(cascade = CascadeType.ALL, mappedBy = "parent", fetch = FetchType.EAGER) private List<ParentHobby> hobbyList; Child: @Entity @Table(name="CHILD") public class Child { @Id @SequenceGenerator(name=

Misunderstanding on Composite Key for Cassandra

只谈情不闲聊 提交于 2019-11-29 14:22:32
问题 I've to test different datamodels for Cassandra. I'm thinking about to use a composite key made by key1:key2 for the row key. With this configuration on Cassandra, for example, I can query to have all the rows having a specific key1 value and any key2 value but It's impossible otherwise (obtain all the rows having a specific key2's value and any key1). Is it right? thanks in advance Cesare 回答1: If you use Order Preserving Partitioning (OPP), then yes, the keys will be stored sorted, and then