comparison

问题 In Python 2, it was possible to compare objects of different types such as int to str by having an implicit comparison of the text string of types (that is, in lexicographic order, string 'int' is less than string 'str' and string 'list' is less than string 'tuple' ). Hence, in Python 2, 5 < 'hello' returns True . One can read more about why this was allowed in answer to Why is ''>0 True in Python?. In Python 3, this raises builtins.TypeError: unorderable types: int() < str() exception. This

问题 I want to compare two double value as follow: Double doubleValue = Double.valueOf(Long.MAX_VALUE); Double doubleValue2 = Double.valueOf(Long.MAX_VALUE+1d); Apparently doubleValue and doubleValu2 are not equal, 2nd is larger due to the 1d addition. but no matter I use compare() or equals() method, both methods return a equal result for two values. Is there any way I can compare and not losing accuracy here. thanks in advance. 回答1: This is because of the loss of precision while converting long

问题 I want to compare two double value as follow: Double doubleValue = Double.valueOf(Long.MAX_VALUE); Double doubleValue2 = Double.valueOf(Long.MAX_VALUE+1d); Apparently doubleValue and doubleValu2 are not equal, 2nd is larger due to the 1d addition. but no matter I use compare() or equals() method, both methods return a equal result for two values. Is there any way I can compare and not losing accuracy here. thanks in advance. 回答1: This is because of the loss of precision while converting long

问题 This question already has answers here : Hidden features of Python [closed] (191 answers) Why does the expression 0 < 0 == 0 return False in Python? (9 answers) Closed 1 year ago . >>> a = 2 >>> b = 3 >>> c = 2 >>> b > a == c True >>> Is this true that b > a == c is equal to a < b and c == a because it's a chained comparison? This doesn't make sense to me because of == comparison, I would expect that b > a == c is equal to (b > a) == c or b > (a == c) . 回答1: python is correcting your

问题 I'm trying to use a new R package called waldo (see at the tidyverse blog too) that is designed to compare data objects to find differences. The waldo::compare() function returns an object that is, according to the documentation: a character vector with class "waldo_compare" The main purpose of this function is to be used within the console, leveraging coloring features to highlight outstanding values that are not equal between data objects. However, while just examining in console is useful,

问题 Compare Array of Objects function compare (arr1, arr2){ //if object key value pair from arr2 exists in arr1 return modified array for (let obj of arr2) { if(obj.key === arr1.key){ return obj } } } // Should return [{key: 1, name : "Bob", {key: 2, name : "Bill"}] compare([{key: 1}, {key: 2}], [{key: 1, name : "Bob"}, {key: 3, name : "Joe"}, {key: 2, name : "Bill"}]) I am having a disconnect with looping arrays of objects with different lengths and properties. I have tried looping and IndexOf

问题 I have a lot of music and i want to rank them from least favorite to favorite (this will take many days). I would like to compare two music files at a time (2-way comparison). I saw some questions on algorithms with the fewest comparisons. But the catch is that (since it's a long process) i want to add new music to the collection and in that case i don't want to start over sorting everything (thus creating a lot more comparison steps). Which algorithm has the least amount of comparisons while

问题 I have a lot of music and i want to rank them from least favorite to favorite (this will take many days). I would like to compare two music files at a time (2-way comparison). I saw some questions on algorithms with the fewest comparisons. But the catch is that (since it's a long process) i want to add new music to the collection and in that case i don't want to start over sorting everything (thus creating a lot more comparison steps). Which algorithm has the least amount of comparisons while

问题 I have a web page that displays 10 images at a time from a directory. In the directory I have now 55,000 images. Once zz below hits 32,767 it stops. How do I make ZZ into a subtype LONG to get it to be 2,147,483,647 (the code below is not accurate, just quickly done to show you the loop I am achieving) pp = Request("pp") ' pp could be at 40000 filecount = 0 dim zz For Each file in filecoll zz = zz + 1 If ZZ > PP then response.write 'show image here end if Next 回答1: The actual problem got

问题 I am considering to start using Pexpect. On Pexpects homepage I find this: Q: Why not just use Expect? A: I love it. It's great. I has bailed me out of some real jams, but I wanted something that would do 90% of what I need from Expect; be 10% of the size; and allow me to write my code in Python instead of TCL. Pexpect is not nearly as big as Expect, but Pexpect does everything I have ever used Expect for. There is a 10% difference between Pexpect and Expect. So my question is what is this 10