command-line-interface

问题 I'm calling a bunch of command-line interface (CLI) tools (such as texi2pdf or pdf2svg from an R script, and I'd like to capture the output file of these tools directly as an R object, without touching the file system . This is the opposite concern of the more frequent "how-do-I-redirect-stdout-to-file"-question. (Perhaps that implies that I'm "using it wrong"). Example : Say, I have a simple latex reprex.tex file that I'd like to compile: \documentclass{article} \begin{document} Foo. \end

问题 I would like to retrieve some application's logs. I found that the command cf file was not available anymore and the plugin cf-download doesn't work on Diego Architecture. Is there a way to retrieve files from the cloud foundry by CLI other another method? 回答1: The solution is to use SSH without cf CLI When you are at the step 4) you can use WinSCP (for Windows) to have a graphical interface to navigate in the folders. 来源： https://stackoverflow.com/questions/48499625/how-to-pull-files-from

问题 So i'm trying to build an CLI with the following pattern: cli.py api new --config config.json or cli.py api del [api_name] To achieve the api i've added it as sup parser if __name__ == '__main__': parser = argparse.ArgumentParser(prog='my prog') subparsers = parser.add_subparsers(title='api', help='available actions') api_parser = subparsers.add_parser('api') from here i thought that we might want to add two new subparsers to handle the new and del subcommands: if __name__ == '__main__':

问题 I am running a simple test script from the command line on CentOS 5.6 with the PHP package installed from PHP 5.3 on CentOS/RHEL 5.6. PHP runs fine in all other cases but when I hit mysql_connect() it fails without error. If I run $ php -m I am not seeing MySQL as an installed module. However I have added extension=mysql.so to my php.ini and rebooted. Output of 'rpm -qa | grep php' php-common-5.3.10-1.w5 php-5.3.10-1.w5 php-cli-5.3.10-1.w5 Output of 'yum install php-mysql' --> Missing

问题 So I create the dotfiles directory and then cd to dotfiles. However, cucumber aruba is giving me an error that says dotfiles is not a directory. I can't figure out why this is? the code in pry results in the correct behavior. @creation Scenario: Create a dotfiles git repository Given the directory dotfiles does not exist in the home directory When I successfully run `dotfiles init dotfile_one dotfile_two dotfile_three` Then a dotfiles directory should exist in the home directory When I change

问题 I followed all the instructions. I am on Ubuntu 10.10. using Zend Server Ce. In my .bashrc I have ld_library_path, zend framework library, etc. I can run zf, but its giving an error: Fatal error: Uncaught exception 'Zend_Exception' with message 'Security check: Illegal character in filename' in /usr/local/zend/share/ZendFramework/library/Zend/Loader.php:303 Stack trace: #0 /usr/local/zend/share/ZendFramework/library/Zend/Loader.php(128): Zend_Loader::_securityCheck('Zend/Tool/Proje...') #1

问题 Let's say I have a private function addUser() in function.php that takes $username as an input variable and does some stuff: function addUser($username) { //do some stuff } Now I want to call this function and pass the value $username, if possible with PHP CLI. I guess that won't work from outside function.php since it's private, but how could I do this then? 回答1: php -r 'include("/absolute/path/to/function.php"); addUser("some user");' This should work. Because you are basically executing

问题 I'm trying to tail apache error logs through a few filters. This works perfectly: tail -fn0 /var/log/apache2/error.log | egrep -v "PHP Notice|File does not exist" but there are some literal "\n" in the output which I want to replace with an actual new line so I pipe into perl: tail -fn0 /var/log/apache2/error.log | egrep -v "PHP Notice|File does not exist" | perl -ne 's/\\n/\n/g; print"$_"' This seems to have some caching issue (first page hit produces nothing, second page hit and two loads

问题 For example: ~ echo foo bar baz foo bar baz ~ echo catz ratz batz catz ratz batz ~ echo !!:2 #=> ratz In this case the !!:2 accesses the second argument of the last command. Is it possible to get the second argument of the second to last command which in this case would expand to bar ? 回答1: As illustrated by @Jahid in a previous post: Second argument of the second to last command: ~ $ echo foo bar baz # This one is the target foo bar baz ~ $ echo catz ratz batz catz ratz batz ~ $ echo !-2:2

问题 I cannot get an auto_prepend_file run on my mac: # cat /opt/local/lib/php/test.php <?php function test() { return 'foo'; } # php --ini | grep php.ini Configuration File (php.ini) Path: /opt/local/etc/php5 Loaded Configuration File: /opt/local/etc/php5/php.ini # cat /opt/local/etc/php5/php.ini | grep auto_prepend_file auto_prepend_file = "/opt/local/lib/php/test.php" # ls -la /opt/local/etc/php5/php.ini -rw-r--r-- 1 root admin 68630 Jul 27 13:53 /opt/local/etc/php5/php.ini # php -r "echo ini