color-blending

I have an three.js object which is a given colour. I want to animate it smoothly to another colour. During the animation, it should only show a direct gradation between the start and end. That is, it should not perform the tween linearly in RGB colour space. I'm not even sure that a linear tween within HSV space would look good either. How can I get this kind of colour tween on a three.js object? I have a version of this that makes a tween in HSV space. It's not perfect, as many different hues can appear along the way. Three.js doesn't include a method for getting the HSV values from a THREE

Basically, I have a context where I can't programatically tint an image, though I can change it's alpha value. With some experimentation, I've found that I can layer a red, blue, and green version of the image, with specific alpha values, to produce a wide range of colors. However, I am wondering if it's possible to achieve a true RGB representation through this method? If so, what is the formula for converting an RGB value into different alpha values for the red, blue, and green layers. The basic "equation" of alpha combination is: alpha * (R1,G1,B1) + (1-alpha) * (R2,G2,B2) When you have

I saw this Java code that does a perfect 50% blend between two RGB888 colors extremely efficiently: public static int blendRGB(int a, int b) { return (a + b - ((a ^ b) & 0x00010101)) >> 1; } That's apparently equivalent to extracting and averaging the channels individually. Something like this: public static int blendRGB_(int a, int b) { int aR = a >> 16; int bR = b >> 16; int aG = (a >> 8) & 0xFF; int bG = (b >> 8) & 0xFF; int aB = a & 0xFF; int bB = b & 0xFF; int cR = (aR + bR) >> 1; int cG = (aG + bG) >> 1; int cB = (aB + bB) >> 1; return (cR << 16) | (cG << 8) | cB; } But the first way is

I have two SKSpriteNode and their colors are defined like this: colorNode[0].color = UIColor(red: 255, green: 0, blue: 0, alpha: 1) colorNode[1].color = UIColor(red: 0, green: 255, blue: 0, alpha: 1) and I want to have a third SKSpriteNode colorized with a blend of the two first ones, the result should be like this : colorNode[2].color = UIColor(red: 255, green: 255, blue: 0, alpha: 1) but is there a way to addition two UIColors ? Like this : colorNode[2].color = colorNode[0].color + colorNode[1].color How about something like this: func addColor(_ color1: UIColor, with color2: UIColor) ->

In digital imaging, when overlaying two visual layers there are multiple ways you can calculate the image that results when light from a lower layer shines through an obstructing layer in some way. This can offer effects that do not occur as natural phenomenon, such as multiplying colours. Here's an example of the layer blending mode menu provided in Photoshop: (source: psdtop.com ) I recommend visiting the article Understanding Blending Modes if this topic isn't something you're familiar with. It provides a great showcase of the results of each option against two layers. As far as I can tell,