clone

How do I get the seed from a Random in Java?

由 回眸只為那壹抹淺笑 提交于 2019-11-27 17:25:35
问题 I am creating a deep clone for some object. The object contains a Random . Is it good practice to retrieve the seed from the Random ? If so, how? There isn't a Random.getSeed() . 回答1: A Random is intended to be random. Usually you want two Random to produce different numbers rather than to produce the same numbers. You can copy a Random using serialisation/de-serialisation and get the "seed" field using reflection. (But I doubt you should be doing either) Unless the sequence is critical to

Proper way to deep copy with copy constructor instead of Object.clone

由 两盒软妹~` 提交于 2019-11-27 16:37:53
问题 I have some code that performs a deep copy using Object.clone, but I'm trying to rewrite it using the more "acceptable" copy constructor technique. Below are two simple examples of what I'm trying to do, the first using clone and the second using a copy constructor. Deep copy using clone import java.util.*; abstract class Person implements Cloneable { String name; public Object clone() throws CloneNotSupportedException { return super.clone(); } } class Teacher extends Person implements

C# Reflection Indexed Properties

由 ♀尐吖头ヾ 提交于 2019-11-27 15:41:43
问题 I am writing a Clone method using reflection. How do I detect that a property is an indexed property using reflection? For example: public string[] Items { get; set; } My method so far: public static T Clone<T>(T from, List<string> propertiesToIgnore) where T : new() { T to = new T(); Type myType = from.GetType(); PropertyInfo[] myProperties = myType.GetProperties(); for (int i = 0; i < myProperties.Length; i++) { if (myProperties[i].CanWrite && !propertiesToIgnore.Contains(myProperties[i]

How to clone object in Kotlin?

由 ε祈祈猫儿з 提交于 2019-11-27 15:37:03
问题 The question is that simple. Kotlin documentation describes cloning only in accessing Java and in enum class. In latter case clone is just throwing an exception. So, how would I / should I clone arbitrary Kotlin object? Should I just use clone() as in Java? 回答1: For a data class , you can use the compiler-generated copy() method. Note that it will perform a shallow copy. To create a copy of a collection, use the toList() or toSet() methods, depending on the collection type you need. These

How to clone as derived object in C++

由 流过昼夜 提交于 2019-11-27 15:36:03
I define two classes in C++. Ones is the base class, and one is a derived class class CBaseClass { … } class CDerivedClass : public CBaseClass { … } And want to implement a clone function as follows: CBaseClass *Clone(const CBaseClass *pObject) { } When an object of CDerivedClass is passed to Clone, then the function will also create a CDerivedClass object and return. When an object of CBaseClass is passed to Clone, then the function will also create a CBaseClass object and return. How to implement such a feature? The virtual clone pattern is often used to solve problems such as these. Classic

Gitolite: adding user not working, and DENIED by fallthru when cloning as root?

由 柔情痞子 提交于 2019-11-27 15:18:26
问题 I've managed to init an empty git repo on my NAS, and I attempted to add a new user by generating a new public key "foo.pub" and copying + pasting it into keydir/ and committing that and pushing it onto the NAS. First, the files: Here is my ~/.ssh/config file: Host root HostName iptonas User root Port 123 Host foo HostName iptonas User foo Port 123 identityfile ~/.ssh/foo Grabbed a copy of gitolite-admin from NAS: git clone ssh://root/gitolite-admin I get: Cloning into 'gitolite-admin'...

Clone form and increment

由 半世苍凉 提交于 2019-11-27 14:54:39
I have a form below that I want to clone, increment the id(att1) and it's inputs, textareas etc and append to the attendees div. Any help much appreciated. Been wrecking my head... All I have is... $(function () { var index = 1; $(".add").click(function () { index++; $("#att1").clone(true).removeAttr("id").attr("id", "att" + index).appendTo("#attendees"); alert(index); }); }); Html: <div id="attendees"> <div id="att1"> <fieldset> <legend><span class="legend">Attendee 1 Booking Details</span></legend> <p name="test"> <label for="A_Title_1">Title: <span class="req">*</span></label> <input name=

jquery clone div and append it after specific div

由 北战南征 提交于 2019-11-27 13:24:51
Hi guys, from the picture above, I want to clone the div with id #car2 and append it after the last div with id start with car, in this example id #car5. How i can do that? Thanks. This is my try code: $("div[id^='car']:last").after('put the clone div here'); You can use clone, and then since each div has a class of car_well you can use insertAfter to insert after the last div. $("#car2").clone().insertAfter("div.car_well:last"); try this out $("div[id^='car']:last").after($('#car2').clone()); You can do it using clone() function of jQuery, Accepted answer is ok but i am providing alternative

Why do we use the clone() method in Java?

由 允我心安 提交于 2019-11-27 12:40:19
Why do we use the clone() method in Java? (Please give the answer in respect of memory constraint.) Will that reduce memory usage? If yes, then how? Will that reduce the effect of memory leak? Apart from do not use clone, implement a copy constructor , you asked about memory constraints. The idea of cloning is to create an exact duplicate of the cloned object. So in worst case, you use twice the amount of memory afterwards. Practically - a bit less, because Strings are often interned and will (usually) not be cloned. Even though it's up to the implementor of the clone method/copy constructor.

deep copying a graph structure

由 試著忘記壹切 提交于 2019-11-27 12:33:11
问题 I have a graph class with Node's, where each Node can connect to others: public class Node { List<Node> connections; } I would like to make a deep copy of the entire graph. As a first attempt, I tried making a copy constructor like: public Node(Node other) { connections = new ArrayList<Node>(); for (Node n : other.connections) { connections.add(new Node(n)); } } So deep copying a graph would just be: public Graph deepCopy () { Graph g = new Graph(); g.nodes = new ArrayList<Node>(); for (Node
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