children

PHP MySQL Delete parent and child rows

由 馋奶兔 提交于 2019-12-07 06:01:01
问题 I have 1 MySQL Table. It looks like this: +---------+-------------+--------+ | item_id | parent_id | Name | +---------+-------------+--------+ | 1 | 0 | Home | +---------+-------------+--------+ | 2 | 1 | Sub | +---------+-------------+--------+ | 3 | 2 | SubSub | +---------+-------------+--------+ If I DELETE item_id 1, I want to delete the rest of the sub also but how can I do it? I have tried the Foreign Key but it works only if you have 2 tables?? I hope someone can help me in MySQL maybe

check if a component is a child or ancestor of another component ReactJS

由 旧街凉风 提交于 2019-12-07 04:53:28
I am creating a ReactJS Component with an unknown number of children and ancestors, and when a certain event occurs on one of the ancestors I the parent component should know of it. my first approach is to use redux and send the child component with a redux action, and then main parent componetnts will be alerted and will check if the Componetnt sent was one of its ancestors. but, can a parent reactJS component know in someway if another component is one of its ancestors? The parent can define a function in the context, Children can then call this function: Parent: childContextTypes: {

Java Dom parser reports wrong number of child nodes

由 随声附和 提交于 2019-12-07 03:04:13
问题 I have the following xml file: <?xml version="1.0" encoding="UTF-8"?> <users> <user id="0" firstname="John"/> </users> Then I'm trying to parse it with java, but getchildnodes reports wrong number of child nodes. Java code: DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = factory.newDocumentBuilder(); Document document = builder.parse(this.file); document.getDocumentElement().normalize(); Element root = document.getDocumentElement(); NodeList

Vue+element 动态生成导航栏方法（全）

由 十年热恋 提交于 2019-12-06 20:36:42
动态生成的思路 1.通过对标签的循环遍历生成导航栏 2.通过导航栏自身的递归调用形成 1.循环遍历生成的方法 先判断是否有对应的二级菜单再进行对应的循环 <el-menu class="first-navigation" :default-active="this.$route.path" router mode="horizontal" @select="handleSelect" > <el-submenu v-for="item in nav" :key="item.menuName" v-if="item.children" :index="item.code"> <template slot="title">{{ item.menuName }}</template> <el-menu-item v-for="children in item.children" : key="children.menuName" :index="children.code" >{{ children.menuName }}</el-menu-item> </el-submenu> <el-menu-item v-for="item in nav" :key="item.menuName" v-if="!item.children" :index="item.code"> {{ item

List children API doesn't give all the children of the drive/folder

由 江枫思渺然 提交于 2019-12-06 15:03:35
I am facing the following issue while getting files/folders for OneDrive of a user. On hitting https://graph.microsoft.com/v1.0/users/ {user-id}/drive I get this in the response: "quota": { "deleted": 0, "remaining": 0, "total": 0, "used": 0 } which denotes that the drive isn't being used or is empty. On hitting https://graph.microsoft.com/v1.0/users/{user-id}/drive/root I get the response - "folder": { "childCount": 21 }, "root": {}, "size": 281236319 Here, it denotes that there are 21 files/folders in the drive's root folder and they occupy 281.23 MB of space. Now, on hitting https://graph

jQuery's multiple selector + find() vs children()

由 我是研究僧i 提交于 2019-12-06 11:43:34
<select id="select1"> <option value="11">11</option> <option value="12">12</option> </select> <select id="select2"> <option value="21">21</option> <option value="22">22</option> </select>​ Behavior of the find() and the children() methods: find() : $('#select1, #select2').find('option:not(:first)').remove();​​​​​​ Works as expected: select1 has only option 11 and select2 has only option 21 children() : $('#select1, #select2').children('option:not(:first)').remove(); Works weirdly: select1 has only option 11 but select2 has no option anymore... Why? Demo From what I see $('#select1, #select2')

转

由 旧街凉风 提交于 2019-12-06 11:42:59
一个根结点let arr = [ { menuId: 1, name: '系统1', parentMenu: null }, { menuId: 2, name: '系统1_0', parentMenu: 1 }, { menuId: 3, name: '系统1_1', parentMenu: 1 } ] function turnToTreeOfOneRoot(arr) { if (!Array.isArray(arr)) { throw new Error('is not array') } else { return arr.reduce((cur, item) => { if (item.parentMenu == null) { cur = { children: [], ...item } } else if (item.parentMenu == cur.menuId) { cur.children.push(item) } return cur }, {}) } } turnToTreeOfOneRoot(arr) 　　 var arr1 = [ { menuId: 1, name: '系统管理1', parentMenu: null }, { menuId: 2, name: '系统管理1_0', parentMenu: 1 }, { menuId: 3,

jsTree - render all nodes before they are expanded?

由 折月煮酒 提交于 2019-12-06 11:11:18
I'm trying to display the titles of all descendants of a jsTree parent in a separate div (.childNodes) when an item is selected in the tree. My issue is that the descendants are seemingly being lazy loaded, and are only rendered in the DOM when a node is expanded, not when it is selected. Is there a way to disable this to render all nodes before the parent is expanded? This is how I'm creating the tree: container.jstree({ 'core': { 'data': { 'url': nodesContent, } }}); And this is how I'm handling the selected event: container.on("changed.jstree", function (e, data) { var i, list = "<ul>"; var

C#/mono: get list of child processes on Windows and Linux

由 自闭症网瘾萝莉.ら 提交于 2019-12-06 07:59:07
问题 I have the code below for getting a list of child processes on windows by interop'ing with ntdll. Is there an equivalent to 'NtQueryInformationProcess' on Linux, which get's me the process id of the parent of a specified process (like pbi.InheritedFromUniqueProcessId)? I need the code to run on Linux through Mono so hopefully I am hoping I need to change only the part where I get the parent process ID so the code stays mostly the same as on Windows. public IList< Process > GetChildren(

Android Development: How To Get All EditText Children of a ViewGroup?

由 安稳与你 提交于 2019-12-06 07:54:41
Basically, I have a LinearLayout that holds a random amount of horizontal LinearLayouts, and in each of the horizontal LinearLayouts there's a TextView and an EditText. I want to be able to get the value of each EditText children of the master LinearLayout. Sorry if it's confusing, I'm no good at explaining things! Could I just set the same ID for each of the EditTexts then use findViewById, or would that only return the first instance of an EditText? Thanks, Alex. You would need to call findViewById on each of the LinearLayouts. If you do this, you can set the same ID for each EditText.
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