chars

Turn NumPy Array of characters into a string

由 拟墨画扇 提交于 2020-12-05 11:16:26
问题 I have a numpy array of characters and when I write it to file it writes as: ['K' 'R' 'K' 'P' 'T' 'T' 'K' 'T' 'K' 'R' 'G' 'L'] I want it to write with just the letters and without the brackets or quotations i.e. as: KRKPTTKTKRGL I have looked at numpy documentation and from what I have gathered the solution is a chararray however it looks like this is not as functional as a normal array. Any help would be great. Thanks! 回答1: You can use tostring() method of numpy as: >>> st = np.array(['K' 'R

How can I create an efficient iterator of chars from stdin with Rust?

由 做~自己de王妃 提交于 2020-02-02 08:11:25
问题 Now that the Read::chars iterator has been officially deprecated, what is the the proper way to obtain an iterator over the chars coming from a Reader like stdin without reading the entire stream into memory? 回答1: The corresponding issue for deprecation nicely sums up the problems with Read::chars and offers suggestions: Code that does not care about processing data incrementally can use Read::read_to_string instead. Code that does care presumably also wants to control its buffering strategy

How can I create an efficient iterator of chars from stdin with Rust?

由 。_饼干妹妹 提交于 2020-02-02 08:09:13
问题 Now that the Read::chars iterator has been officially deprecated, what is the the proper way to obtain an iterator over the chars coming from a Reader like stdin without reading the entire stream into memory? 回答1: The corresponding issue for deprecation nicely sums up the problems with Read::chars and offers suggestions: Code that does not care about processing data incrementally can use Read::read_to_string instead. Code that does care presumably also wants to control its buffering strategy

String values look the same but don't “.equals()” each other

由 穿精又带淫゛_ 提交于 2020-01-15 05:30:08
问题 I'm making a log in screen. It doesn't work so I decided to display the password (saved to a file), and the inputted password to the screen for comparison. // filePassword is the password inputted from the file as a String. // password is the String value of the EditText on the screen. if (password.equals(filePassword)) { logIn(); } I compared Strings like this: else { scr.setText("." + filePassword + "." + '\n' + "." + password + "."); } This was the String comparison: I compared chars like

Are Java String Objects an Array of Chars?

由 喜你入骨 提交于 2019-12-20 12:45:07
问题 I am new to java and trying to understand the essentials and fundamentals of the language. Is it accurate to state that Java string objects are intrinsically a class defined as an immutable array of chars? I ask this as I'm a bit confused by the spec in comparison to char arrays and the string class... JLS 10.9 10.9 An Array of Characters is Not a String In the Java programming language, unlike C, an array of char is not a String, and neither a String nor an array of char is terminated by '

How do I scan into a 2d char array without scanning in the enter/space chars?

由 江枫思渺然 提交于 2019-12-12 02:59:33
问题 So I have to make a maze program, and to start I must scan in the maze to a 2d array. The problem arises when i go to put the chars into the array, when the enter char and the space char always take up the first slot in the array... Here is my code: int main(){ int row, col; int i,j,k,l; scanf("%d", &row); scanf("%d", &col); char** maze = (char**) calloc(row, sizeof(char*)); for ( k = 0; k < row; k++ ) { maze[k] = (char*) calloc(col, sizeof(char)); } for(i=0;i<row;i++){ for(j=0;j<col;j++){

How do I iterate over a list of chars while still being able to skip in the iteration?

由 若如初见. 提交于 2019-12-11 17:22:34
问题 I have the following piece of code: let mut lex_index = 0; let chars = expression.chars(); while lex_index < chars.count() { if(chars[lex_index] == "something") { lex_index += 2; } else { lex_index += 1; } } I use a while loop here since I sometimes need to skip a char in chars . However, this gives me the following error: error[E0382]: use of moved value: `chars` --> src/main.rs:23:15 | 23 | while i < chars.count() { | ^^^^^ value moved here in previous iteration of loop | = note: move

Need to read white space and other chars C++

由 人盡茶涼 提交于 2019-12-04 06:10:19
问题 I have been working on this all day with no luck. Its night now and don't know what to do. My assignment is to read number of vowels, number of white spaces, and number of other characters in a user inputted sentence. I know i need to use cin.get(ch) for whitespaces, but don't know how. I also need to output the sentence to a file. Heres what I have so far: //Get data from user cout << "Enter your sentence on one line followed by a # to end it: " << endl; while (cin >> noskipws >> character &

Are Java String Objects an Array of Chars?

由 对着背影说爱祢 提交于 2019-12-03 03:16:53
I am new to java and trying to understand the essentials and fundamentals of the language. Is it accurate to state that Java string objects are intrinsically a class defined as an immutable array of chars? I ask this as I'm a bit confused by the spec in comparison to char arrays and the string class... JLS 10.9 10.9 An Array of Characters is Not a String In the Java programming language, unlike C, an array of char is not a String, and neither a String nor an array of char is terminated by '\u0000' (the NUL character). A String object is immutable, that is, its contents never change, while an

Need to read white space and other chars C++

由 泪湿孤枕 提交于 2019-12-02 09:30:00
I have been working on this all day with no luck. Its night now and don't know what to do. My assignment is to read number of vowels, number of white spaces, and number of other characters in a user inputted sentence. I know i need to use cin.get(ch) for whitespaces, but don't know how. I also need to output the sentence to a file. Heres what I have so far: //Get data from user cout << "Enter your sentence on one line followed by a # to end it: " << endl; while (cin >> noskipws >> character && character != '#') { character = static_cast<char>(toupper(character)); if (character == 'A' ||
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