character

问题 I'm getting the message: >>> import some_module Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/home/david/.local/lib/python3.6/site-packages/some_module.py", line 1 ​def​ some_func(): ^ SyntaxError: invalid character in identifier When I am trying to import a local module from a package I installed with pip. The structure of the package is as follows: modules_and_packages ├── modules_and_packages │ ├── __init__.py │ └── some_module.py ├── setup.py └── bin └──

问题 Aim: to insert a character every x characters in a string in Golang Input: helloworldhelloworldhelloworld Expected Output: hello-world-hello-world-hello-world Attempts Attempt one package main import ( "fmt" "strings" ) func main() { s := "helloworldhelloworldhelloworld" s = strings.Replace(s, "world", ",", -1) fmt.Println(s) } results in: hello,hello,hello, Attempt two Count number of characters For loop If X=5 then insert a - Attempt three Scan combined with join Problem The reason that

问题 I am new to r and I have problems with removing duplicated characters. Here is my code: library(RCurl) x <- getURL("https://raw.githubusercontent.com/eparker12/nCoV_tracker/master/input_data/coronavirus.csv") y <- read.csv(text = x) z <- duplicated(y$jhuID) I tried something like z <- ... but it did not work. For the column jhuID in the dataframe it is the class character but there are many name of countries that repeat multiple times and my goal is to delete those duplicated name of country

问题 Below is my string in C# which I am converting it to Character array & in need to get the ASCII value of each character in the string. static void Main(string[] args) { string s = "Test"; var arr = s.ToCharArray(); foreach(var a in arr) { var n = Encoding.ASCII.GetByteCount(a.ToString()); Console.WriteLine(a); Console.WriteLine(n); } } This outputs as T 1 e 1 s 1 t 1 On googling I got number of links but none of them suffice my need. How to get ASCII value of string in C# https://www

问题 How can I print a character multiple times in a single line? This means I cannot use a loop. I'm trying to print " _" multiple times. I tried this method but it's not working: System.out.println (" _" , s); s is the variable. 回答1: You can print in the same line with System.out.print(" _"); so you can use a loop. print instead of println does not append a new line character. for (int i=0; i<5; i++){ System.out.print(" _"); } Will print: _ _ _ _ _ . 回答2: If you can use external libraries,

问题 s ['64.0', '2'] a ['63.0', '2'] b ['63.0', '1'] How to convert it into data frame as follows : s 64.0 a 63.0 b 63.0 回答1: We could use parse_number library(dplyr) library(readr) df2 <- df1 %>% mutate(col2 = parse_number(as.character(col2))) df2 # col1 col2 #1 s 64 #2 a 63 #3 b 63 Or using base R with sub as.numeric( sub("\\D+([0-9.]+)[^0-9]+.*", "\\1", df1$col2)) data df1 <- structure(list(col1 = c("s", "a", "b"), col2 = structure(3:1, .Label = c("['63.0', '1']", "['63.0', '2']", "['64.0', '2'

问题 I have data imported from a .csv file. The first column contains character strings that contain text within parentheses. The data look like: symbol ___________________________________________ 1 | Apollo Senior Floating Rate Fund Inc. (AFT) 2 | Apollo Tactical Income Fund Inc. (AIF) 3 | Altra Industrial Motion Corp. (AIMC) 4 | Allegion plc (ALLE) 5 | Amphenol Corporation (APH) 6 | Ares Management Corporation (ARES) 7 | ARMOUR Residential REIT, Inc. (ARR) 8 | Banc of California, Inc. (BANC) 9 |

问题 I want my program to read one character from an input of random string, but when there is a space in the string, I want it to read the next two characters. For example, if I type H He , I want it to return the value for H , then detect a space then return He . How do I do this? This code is a small part in school assignment (calculating the molecular mass of random compounds). string=input('enter:') pos=0 start=None for a in string: if a == 'H': print(string[start:1]) elif a == ' ': pos=int

问题 The C programming language says that the functions from <ctype.h> follow a common requirement: ISO C99, 7.4p1: In all cases the argument is an int , the value of which shall be representable as an unsigned char or shall equal the value of the macro EOF . If the argument has any other value, the behavoir is undefined. This means that the following code is unsafe: int upper(const char *s, size_t index) { return toupper(s[index]); } If this code is executed on an implementation where char has

问题 This question already has answers here : Split date time (6 answers) Closed 18 days ago . I have a character string in a column of a tibble that looks like Nov 01, 2019 8:00:41 AM CDT . I would like to create new columns of the mentioned column, Date and Time. What is the best approaches into doing this? Lubridate? Time <- tibble(Call = 1, Date_Time = 'Nov 01, 2019 8:00:41 AM CDT') Time %>% mutate(Date_Time = mdy(`Contact Start Date/Time`)) I tried the code above but, my new column had