character

问题 I'm trying to use str_replace_all to replace many different values (i.e. "Mod", "M2", "M3", "Interviewer") with one the consistent string (i.e. "Moderator:"). I'm doing this with multiple different categories, and I want avoid having to write each unique value out as there are a lot. So I made a tibble consisting of all the unique values that I want to make standardized and read it in and then pulled out each column (there are 5 but only 2 shown for simplicity) to make them into vectors:

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 5 years ago . Improve this question Is a string containing a single character same as a char ? It seems java treats a single character string as a string itself, but I am not sure. 回答1: No. Infact String can contain nothing at all. Example : String s="" is still a String. 回答2: A char is a primitive type, while a

问题 Would it be possible to take a string and set a different variable for every character of the string? In other words.. string='Hello' #Do some thing to split up the string here letter_1= #The first character of the variable 'string' letter_2= #The second character of the variable 'string' #... letter_5= #The fifth character of the variable 'string' 回答1: In Python, strings are immutable, so you can't change their characters in-place. However if you try to access by index then you get:

问题 I just started tinkering with Ruby earlier this week and I've run into something that I don't quite know how to code. I'm converting a scanner that was written in Java into Ruby for a class assignment, and I've gotten down to this section: if (Character.isLetter(lookAhead)) { return id(); } if (Character.isDigit(lookAhead)) { return number(); } lookAhead is a single character picked out of the string (moving by one space each time it loops through) and these two methods determine if it is a

问题 Unicode categorizes characters as belonging to a script, such as the Latin script. How do I test whether a particular character (code point) is in a particular script? 回答1: Java represents the various Unicode scripts in the Character.UnicodeScript enum, including for example Character.UnicodeScript.LATIN. These match the Unicode Script Properties. You can test a character by submitting its code point integer number to the of method on that enum. int codePoint = "a".codePointAt( 0 ) ;

问题 I have a problem with encoding and Jetty. All my files are encoded in UTF-8 and include the correct HTML meta tag to specify UTF-8. Until now all my UTF-8 files had a BOM and I had no problem. But now I am using a different text editor and I noticed that my UTF-8 files are now generated without a BOM which from what I read is rather a good thing so I decided to go without BOM from now. But the problem is that it seems that Jetty converts all my JSP files to ISO8859-1 before sending them to

问题 I'm trying to convert a list into a single character value, or basically go from this: test <- data.frame(a = c(1,1,1,2,2,2), b = c("a", "b", "c", "d", "e", "f" )) %>% group_by(a) %>% summarise(b = list(b)) to this: test <- data.frame(a = c(1,2), b = c("a, b, c", "d, e, f" )) 回答1: Here you go: test %>% mutate(b = sapply(b, toString)) ## A tibble: 2 x 2 # a b # <dbl> <chr> #1 1. a, b, c #2 2. d, e, f 回答2: As suggested by the OP, I post my comment as an answer for future reference. Starting

问题 I'm trying to convert a list into a single character value, or basically go from this: test <- data.frame(a = c(1,1,1,2,2,2), b = c("a", "b", "c", "d", "e", "f" )) %>% group_by(a) %>% summarise(b = list(b)) to this: test <- data.frame(a = c(1,2), b = c("a, b, c", "d, e, f" )) 回答1: Here you go: test %>% mutate(b = sapply(b, toString)) ## A tibble: 2 x 2 # a b # <dbl> <chr> #1 1. a, b, c #2 2. d, e, f 回答2: As suggested by the OP, I post my comment as an answer for future reference. Starting

问题 I'm trying to convert a list into a single character value, or basically go from this: test <- data.frame(a = c(1,1,1,2,2,2), b = c("a", "b", "c", "d", "e", "f" )) %>% group_by(a) %>% summarise(b = list(b)) to this: test <- data.frame(a = c(1,2), b = c("a, b, c", "d, e, f" )) 回答1: Here you go: test %>% mutate(b = sapply(b, toString)) ## A tibble: 2 x 2 # a b # <dbl> <chr> #1 1. a, b, c #2 2. d, e, f 回答2: As suggested by the OP, I post my comment as an answer for future reference. Starting

问题 I'm trying to write a character device driver in linux. Unfortunately it's not working for any numbers greater than 255. I want this driver specifically to work with value of type long . Anytime I input a value greater than 255, the numbers wrong. 256 goes to 0 etc. I've written a simple character device driver that shows the problem, there might be a lot of unused include statements as I copied my full driver and deleted almost everything: chartest.c #include <linux/init.h> #include <linux