calloc

Is there a call I can make to new to have it zero out memory like calloc ? Contrary what some are saying in their answers, it is possible. char * c = new char[N](); Will zero initialize all the characters (in reality, it's called value-initialization. But value-initialization is going to be zero-initialization for all its members of an array of scalar type). If that's what you are after. Worth to note that it does also work for (arrays of) class-types without user declared constructor in which case any member of them is value initialized: struct T { int a; }; T *t = new T[1](); assert(t[0].a =

I want to calloc 25 bytes of memory exactly. In this case, msg_len = 5 bytes, since that is what the input is. This is the code I have: int full_msg_size = 20 + msg_len; printf("full_msg_size: %d\n", full_msg_size); void *full_msg = calloc(full_msg_size, sizeof(char)); printf("size of full_msg: %d\n", (int*)sizeof(full_msg)); This is what prints out: full_msg_size: 25 size of full_msg: 8 But I want size of full_msg to equal 25 bytes just like full_msg_size. I also want all the memory spaces initialized to zero. Can anyone tell me how to calloc/malloc this properly? Thanks In the context of

The question is in the title... I searched but couldn't find anything. Edit: I don't really see any need to explain this, but because people think that what I'm saying makes no sense (and that I'm asking the wrong questions), here's the problem: Since people seem to be very interested in the "root" cause of all the problem rather than the actual question asked (since that apparently helps things get solved better, let's see if it does), here's the problem: I'm trying to make a D runtime library based on NTDLL.dll, so that I can use that library for subsystems other than the Win32 subsystem. So

Possible Duplicate: Do I cast the result of malloc? I was googling to find out the reason for type-casting of malloc and calloc . But, i only found type-casting of malloc is not necessary since it return void pointer but, what about calloc . This is the same reason for calloc too ??? Now, if we move back to first point, about return value of malloc and calloc . Then, i found that, both are returning the allocated spaces . So, i'm little bit confused here. So, my questions are What is the return value of malloc and calloc Is it necessary to type-cast malloc and calloc . And why ? What is the

1、calloc 表头文件　　#include <stdlib.h> 定义函数　　void *calloc(size_t nmemb，size_t size); 函数说明　　calloc()用来配置nmemb 个相邻的内存单位，每一单位的大小为size，并返回指向第一个元素的指针。这和使用下列的方式效果相同：malloc(nmemb* size);不过，在利用calloc()配置内存时会将内存内容初始化为0。 返回值　　 若配置成功则返回一指针，失败则返回NULL。 2、free 表头文件　　#include <stdlib.h> 定义函数　　void free(void *ptr); 函数说明　　参数ptr 为指向先前由malloc（）、calloc()或realloc()所返回的内存指针。调用free()后ptr 所指的内存空间便会被收回。假若参数ptr所指的内存空间已被收回或是未知的内存地址，则调用free()可能会有无法预期的情况发生。 若参数ptr 为NULL，则free()不会有任何作用。 3、getpagesize 表头文件　　#include<unistd.h> 定义函数　　size_t getpagesize(void); 函数说明　　返回一分页的大小，单位为字节（byte）。此为系统的分页大小，不一定会和硬件分页大小相同。 返回值　　 内存分页大小。 4