calloc

Using calloc() to set up char array, also “freeing” array when done

不羁的心 提交于 2019-12-13 00:12:16
问题 I'm trying to set up an array of strings (in C, using Linux). The array will hold 11 strings (static length). I initially had the array set up as: char Answers[10][100]; but in my code I have a portion that calls fgets(input,sizeof(input),stdin). When this fgets() portion is called, the final element of my Answers array was being overwritten with the value of input (something about Answers' location on the stack?). So now I'm trying to "lock-in" the memory I use for my Answers array. Would I

Why does calloc allocate 1 byte if nelem or elsize == zero?

梦想的初衷 提交于 2019-12-12 21:16:57
问题 I am working to develop debug implementations of the four basic memory allocation routines malloc , realloc , calloc , and free (similar in operation to Electric Fence) to debug heap corruption on embedded systems which do not have the resources to run other memory debugging tools, or for which other tools do not exist (for instance, LynxOS 7.0 for PowerPC ships with GCC 4.6.3, and a proprietary implementation of glibc and libstdc++ which does not include the mtrace family of functions). The

Allocating contiguous memory for a 3D array in C

微笑、不失礼 提交于 2019-12-12 09:27:15
问题 I need to allocate contiguous space for a 3D array. (EDIT:) I GUESS I SHOULD HAVE MADE THIS CLEAR IN THE FIRST PLACE but in the actual production code, I will not know the dimensions of the array until run time. I provided them as constants in my toy code below just to keep things simple. I know the potential problems of insisting on contiguous space, but I just have to have it. I have seen how to do this for a 2D array, but apparently I don't understand how to extend the pattern to 3D. When

How much memory does calloc actually allocate?

。_饼干妹妹 提交于 2019-12-12 02:10:08
问题 The following code when tested, gives output as 1 0 0 2 0 which is amazing because ptr[3], ptr[4] did not have any memory allocation. Although they stored value in them and prints it. I tried the same code for few larger i's in ptr[i] which again compiled successfully and gives result but for very large value of i, of the order of 100000,program get crashed. if calloc() allocates such a large memory on single call then it is not worth effective. So how calloc() works? Where is this

Why calloc wasn't intended to assign arbitrary values?

南笙酒味 提交于 2019-12-11 22:18:24
问题 As per Why malloc+memset is slower than calloc? malloc + memset is slower than calloc under certain conditions. Why wasn't calloc written in such a way that it can take an extra value argument ( like memset ) to override default assignment by zero? What would have been the effect of that if it were done? 回答1: These calloc or memset initializations operate on a byte level, so even memset with a value different from 0 is not that usefull. At least I don't remember having it used with different

Some calls to “calloc” are suspiciously fast [duplicate]

送分小仙女□ 提交于 2019-12-07 14:24:46
问题 This question already has answers here : Why malloc+memset is slower than calloc? (3 answers) Closed 4 years ago . I'm benchmarking with “Perf” (Linux, gcc). When allocating memory: point_1 = calloc (100000000, 16); //this takes nearly 1 second and perf find 27M transfers from RAM->CACHE and 1M from CACHE->RAM This is OK. But when trying to allocate two arrays: point_1 = calloc (100000000, 16); point_2 = calloc (100000000, 16); //again, program takes nearly 1 second, 27M transfers RAM-CACAHE,

C语言动态内存

ε祈祈猫儿з 提交于 2019-12-07 12:08:03
malloc 原型: void *malloc(size_t size) size :请求内存的总字节数 返回值 : 内存地址 NULL #include<stdio.h> #include<stdlib.h> #define LEN 3 int main(void) { //定义指向堆空间指针 int* p = (int*)malloc(LEN*sizeof(int)); if(NULL==p) { printf("内存申请失败\n"); return -1; } //类数组方式赋值 for(int i=0;i<LEN;i++) { printf("输入:"); scanf("%d",p+i); } //遍历 for(int i=0;i<LEN;i++) { printf("%d\t",*(p+i)); } //换行 printf("\n"); //释放内存 if(NULL!=p) { free(p); p = NULL; } return 0; } 总结 malloc 申请的内存在申请已后如同数组一样 暂时性 不可变,同时申请的内存是 连续内存 所以可以如 同 数组一样通过 下标 访问到 元素 ,同时用 malloc 申请的内存空间系统不会进行初始化操作,内部处于随机状态 calloc 原型: void *calloc(size_t nitems, size_t size)

Qt Creator - calloc fails with large memory

拟墨画扇 提交于 2019-12-07 11:17:19
问题 I have a problem with Qt Creator, or one of its components. I have a program which needs lots of memory (about 4 GBytes) and I use calloc to allocate it. If I compile the C code with mingw/gcc (without using the Qt-framework) it works, but if I compile it within the Qt Creator (with the C code embedded in the Qt framework using C++), using the mingw/gcc toolchain, calloc returns a null-pointer. I already searched and found the qt-pro option QMAKE_LFLAGS += -Wl,--large-address-aware , which

C语言重要函数 memcpy与memmove,memset

江枫思渺然 提交于 2019-12-07 09:15:05
包含头文件: #include <stdlib.h> 1>:malloc calloc realloc free函数 //动态内存分配函数 三个函数的声明分别是: void* malloc(unsigned size); malloc()函数有一个参数,即要分配的内存空间的大小: void* calloc(size_t nelem, size_t elsize); calloc()函数有两个参数,分别为元素的数目和每个元素的大小,这两个参数的乘积就是要分配的内存空间的大小。 如果调用成功,函数malloc()和函数calloc()都将返回所分配的内存空间的首地址。 malloc和calloc都可以分配内存区,但malloc一次只能申请一个内存区,calloc一次可以申请多个内存区.另外calloc会把分配来的内存区初试化为0,malloc不会进行初始化. void* realloc(void* ptr, unsigned newsize); realloc是给一个已经分配了地址的指针重新分配空间,参数ptr为原有的空间地址,newsize是重新申请的地址长度 free的调用形式为free(void*ptr):释放ptr所指向的一块内存空间。 #i nclude <stdio.h> #i nclude <stdlib.h> main() { int *p=NULL; p=(int *

C博客作业05--指针

回眸只為那壹抹淺笑 提交于 2019-12-06 06:41:05
0.展示PTA总分 1.本章学习总结 1.1学习内容总结 1.指针做循环变量做法 基本做法如下: int a[10]; int *p; p=a;//指针指向a数组的首地址 fgets(a,10,stdin); for(p=a;*p!='0'&&*p!='\n',p++) { 循环结构; } 2.字符指针如何表示字符串 基本做法如下: char str[]="abc"; char *p; for(p=str;*p!='0'&&*p!='\n',p++) { 循环结构; } 3.动态内存分配 1.动态内存分配的步骤 (1)了解需要多少内存空间。 (2)利用C语言提供的动态分配函数来分配所需要的储存空间。 (3)使指针指向获得的内存空间,以便用指针在该空间内实施运算或操作。 (4)当使用完毕内存后,释放这一空间。 2.动态存储分配函数 1.malloc() 函数原型是 : void * malloc(unsigned size) 2.calloc() 函数原型是 : void * calloc(unsigned n,unsigned size) 两者的区别仅在于calloc函数在分配后还把存储块里全部初始化为0,而malloc函数不会。 3.动态存储释放函数free() 函数原型为 : void free (void * ptr) 这个函数十分关键却又经常被人遗忘