c++11

问题 This question already has answers here : What does iota of std::iota stand for? (5 answers) Closed 6 years ago . C++11 introduced a function called iota. Which "Assigns to every element in the range [first,last) successive values of val, as if incremented with ++val after each element is written." Can someone explain what "iota" means here though? I looked up "iota" and it seems to have nothing to do with generating a range. 回答1: Quoting this non-authoritative, but nonetheless correct, wiki:

问题 This question already has answers here : What does iota of std::iota stand for? (5 answers) Closed 6 years ago . C++11 introduced a function called iota. Which "Assigns to every element in the range [first,last) successive values of val, as if incremented with ++val after each element is written." Can someone explain what "iota" means here though? I looked up "iota" and it seems to have nothing to do with generating a range. 回答1: Quoting this non-authoritative, but nonetheless correct, wiki:

问题 This question already has answers here : What does iota of std::iota stand for? (5 answers) Closed 6 years ago . C++11 introduced a function called iota. Which "Assigns to every element in the range [first,last) successive values of val, as if incremented with ++val after each element is written." Can someone explain what "iota" means here though? I looked up "iota" and it seems to have nothing to do with generating a range. 回答1: Quoting this non-authoritative, but nonetheless correct, wiki:

问题 This question already has answers here : What does iota of std::iota stand for? (5 answers) Closed 6 years ago . C++11 introduced a function called iota. Which "Assigns to every element in the range [first,last) successive values of val, as if incremented with ++val after each element is written." Can someone explain what "iota" means here though? I looked up "iota" and it seems to have nothing to do with generating a range. 回答1: Quoting this non-authoritative, but nonetheless correct, wiki:

问题 This question already has answers here : What does iota of std::iota stand for? (5 answers) Closed 6 years ago . C++11 introduced a function called iota. Which "Assigns to every element in the range [first,last) successive values of val, as if incremented with ++val after each element is written." Can someone explain what "iota" means here though? I looked up "iota" and it seems to have nothing to do with generating a range. 回答1: Quoting this non-authoritative, but nonetheless correct, wiki:

问题 I am trying to create an object using placement new (I know to use smart pointers, this is just to learn). My code is as follows: #include <vector> #include <iostream> #include <memory> using namespace std; // please excuse this // if you change like 19 to arr1 (or any other var name) instead of arr and line 40 to arr1 then it works struct A { int in = 999; A() {cout << "A ctor\n";} ~A() {cout << "A dtor\n";} }; char arr[sizeof(A)]; class B { public: static char arr[sizeof(A)]; const static A

问题 I am trying to create an object using placement new (I know to use smart pointers, this is just to learn). My code is as follows: #include <vector> #include <iostream> #include <memory> using namespace std; // please excuse this // if you change like 19 to arr1 (or any other var name) instead of arr and line 40 to arr1 then it works struct A { int in = 999; A() {cout << "A ctor\n";} ~A() {cout << "A dtor\n";} }; char arr[sizeof(A)]; class B { public: static char arr[sizeof(A)]; const static A

问题 I am experiencing some issues with thread sanitizer (TSan) complaining about a data race in some production code where std::packaged_task are handed over to a dispatcher thread by wrapping them in a std::function. For this question I have simplified what it does in production, while triggering TSan. The implementation is similar to the answer given by Anthony Williams in this question (at least that is my understanding): Non-obvious lifetime issue with std::promise and std::future. Note that

问题 I am experiencing some issues with thread sanitizer (TSan) complaining about a data race in some production code where std::packaged_task are handed over to a dispatcher thread by wrapping them in a std::function. For this question I have simplified what it does in production, while triggering TSan. The implementation is similar to the answer given by Anthony Williams in this question (at least that is my understanding): Non-obvious lifetime issue with std::promise and std::future. Note that

问题 What is the correct way to replace this: std::ostringstream buf; std::for_each(bd.begin(), bd.end(), buf << boost::lambda::constant(" ") << boost::lambda::_1); With an implementation that doesn't use boost? This is what I've tried: std::string backspace("&nbps;"); std::ostringstream buf; std::for_each(bd.begin(), bd.end(), buf << backspace << std::placeholders::_1); The second '<<' is underlined in red and I get the error message: error C2679: binary '<<' : no operator found which takes a