bufferedinputstream

问题 I am trying to upload huge files to S3 using BufferedInputStream and providing it with a Buffer size of 5MB but the performance of the application is hindered because of the network speed/amount the available data to read is limited like mentioned in this answer link (limited to 1MB). This makes me upload 1MB as part size at a time to s3 using UploadPartRequest which increases my time to upload. So, is there any other better and fast way to upload to S3 using FileInputStream as a source. Is

问题 I am trying to upload huge files to S3 using BufferedInputStream and providing it with a Buffer size of 5MB but the performance of the application is hindered because of the network speed/amount the available data to read is limited like mentioned in this answer link (limited to 1MB). This makes me upload 1MB as part size at a time to s3 using UploadPartRequest which increases my time to upload. So, is there any other better and fast way to upload to S3 using FileInputStream as a source. Is

问题 I am trying to read a very large file (~2GB). Content is a continuous string with sentences (I would like to split them based on a '.'). No matter how I try, I end up with an Outofmemoryerror. BufferedReader in = new BufferedReader(new FileReader("a.txt")); String read = null; int i = 0; while((read = in.readLine())!=null) { String[] splitted = read.split("\\."); for (String part: splitted) { i+=1; users.add(new User(i,part)); repository.saveAll(users); } } also, inputStream = new

问题 I am trying to read a very large file (~2GB). Content is a continuous string with sentences (I would like to split them based on a '.'). No matter how I try, I end up with an Outofmemoryerror. BufferedReader in = new BufferedReader(new FileReader("a.txt")); String read = null; int i = 0; while((read = in.readLine())!=null) { String[] splitted = read.split("\\."); for (String part: splitted) { i+=1; users.add(new User(i,part)); repository.saveAll(users); } } also, inputStream = new

问题 Is it ever possible for BufferedInputStream(byte[] b, int off, int len) to return 0? READER'S DIGEST VERSION (you can read the rest below, for context, but I think it boils down to this:) Are there InputStreams (i.e. SocketInputStream, CipherInputStream, etc. in the JDK or in commonly used libraries (i.e. Apache Commons, Guava), that don't correctly honor the contract of InputStream.read(byte[],off,len) and might return '0' even if len != 0? (Note 1: my interest is whether it can really

问题 I have been given a task of copying data from a server. I am using BufferedInputStream and output stream to copy the data and I am doing it byte by byte. Even though it is running but It is taking ages to copy the data as some of them are in 100's MBs, so definitely it is not gonna work. Can anyone suggest me any alternate of Byte by Byte copy so that my code can copy file that are in few Hundred MBs. Buffer is 2048. Here is how my code look like: static void copyFiles(SmbFile[] files, String

问题 I have been given a task of copying data from a server. I am using BufferedInputStream and output stream to copy the data and I am doing it byte by byte. Even though it is running but It is taking ages to copy the data as some of them are in 100's MBs, so definitely it is not gonna work. Can anyone suggest me any alternate of Byte by Byte copy so that my code can copy file that are in few Hundred MBs. Buffer is 2048. Here is how my code look like: static void copyFiles(SmbFile[] files, String

问题 I have lots of PDF files that I need to get its content encoded using base64. I have an Akka app which fetch the files as stream and distributes to many workers to encode these files and returns the string base64 for each file. I got a basic solution for encoding: org.apache.commons.codec.binary.Base64InputStream; ... Base64InputStream b64IStream = null; InputStreamReader reader = null; BufferedReader br = null; StringBuilder sb = new StringBuilder(); try { b64IStream = new Base64InputStream

问题 Should be pretty simple: I have an InputStream where I want to peek at (not read) the first two bytes, i.e. I want the "current position" of the InputStream to stil be at 0 after my peeking. What is the best and safest way to do this? Answer - As I had suspected, the solution was to wrap it in a BufferedInputStream which offers markability. Thanks Rasmus. 回答1: For a general InputStream, I would wrap it in a BufferedInputStream and do something like this: BufferedInputStream bis = new

问题 I am sequentially processing a large file and I'd like to keep a large chunk of it in memory, 16gb ram available on a 64 bit system. A quick and dirty way is to do this, is simply wrap the input stream into a buffered input stream, unfortunately, this only gives me a 2gb buffer. I'd like to have more of it in memory, what alternatives do I have? 回答1: How about letting the OS deal with the buffering of the file? Have you checked what the performance impact of not copying the whole file into