boto

I have my aws_access_key_id and aws_secret_access_key stored in ~/.boto and was wondering if there was a way for me to retrieve these values in my python code using Boto as I need to insert them in to my SQL statement to to copy a CSV file from S3. This should work: import boto access_key = boto.config.get_value('Credentials', 'aws_access_key_id') secret_key = boto.config.get_value('Credentials', 'aws_secret_access_key') Here's a helper that will look in ~/.aws/credentials if boto.config doesn't work. I didn't look into it in great detail, but it kind of appears that Boto 2 doesn't look in ~/

What I want to accomplish is to generate a link to view the file (ex.image or pdf). The item is not accessible by URL ( https://[bucket].s3.amazonaws.com/img_name.jpg ), I think because its private and not public? (I'm not the owner of the bucket, but he gave me the access_key and secret_key?) For now, all I can do is to download a file with this code. s3.Bucket('mybucket').download_file('upload/nocturnes.png', 'dropzone/static/pdf/download_nocturnes.png') I want to access an image on s3 so I can put it on an HTML, can I view it using the access and secret key?. Thank you for those who can

The code below work locally and uploads files from a directory to S3. It's using Boto3 with Python 3. s3 = boto3.resource('s3', aws_access_key_id=AWS_ACCESS_KEY_ID, aws_secret_access_key=AWS_ACCESS_KEY_SECRET) bucket = s3.Bucket(bucket_name) uploadFileNames = [] for (sourceDir, dirname, filenames) in os.walk(sourceDir): for filename in filenames: bucket.put_object(Key=filename, Body=open("{}{}".format(sourceDir, filename), "rb")) break My problem is what when I run the same code on my production server (Ubuntu) I get the following error, why? return self._make_api_call(operation_name, kwargs)

I am trying to execute a remote command on an ec2 instance that needs sudo. example code snippet conn = boto.ec2.connect_to_region(....) instance = conn.get_only_instances(instance_ids=instance_id)[0] ssh_client = sshclient_from_instance(instance, ssh_key_file='path.to.pem,user_name='ec2-user') chan = ssh_client.run_pty('sudo ls /root') Using just ssh_client.run() returns a tuple that was easy to deal with but doesn't allow sudo. run_pty is returning paramiko.channel.Channel and I can use recv() to get some output back but I am not clear how to get the entire stdout. 来源： https://stackoverflow