binaryfiles

I'm trying to write a struct to a binary file. I want my code to be cross platform, so I'm not sure about just writing the whole struct with a fwrite. If I did this, then the size of the struct will vary depending on the size of the primitive types for each platform(in platform A, an int won't have the same size as in platform B. So the struct won't be the same size either, and the file will end up being different). But I know nothing about this, so should I write each member of the struct individually, serialize the struct (how can I do this?) , or just write the struct whit a fwrite?

How do I resolve a binary file conflict resolution during a merge operation in git? Here's what I've done so far: git checkout master git fetch origin git merge working_branch ... [Conflicts] ... git status ... Unmerged paths: both modified: Path/file.dll ... I want to keep the version in the working_branch and discard the version in the master . How do I do this? Figured it out earlier today: git checkout --theirs Path/file.dll git add Path/file.dll git commit -m "Resolved merge conflict by checking out file from working_branch and adding it to the master" 来源： https://stackoverflow.com

I am trying to write the file in binary format. I have the following code with me, but it save the file in text format. #include <iostream> #include <fstream> using namespace std; int main(){ std::string ref = "Ecoli. 123"; unsigned int size = 124; std::ofstream supp_info_output("binary_file", std::ios::out | std::ios::binary); // saving file supp_info_output << ref << std::endl; supp_info_output << size << std::endl; supp_info_output.close(); std::ifstream supp_info_input("binary_file", std::ios::in | std::ios::binary); // loading file std::string supp_info_line; while( std::getline( supp

I have a binary output file from a FORTRAN code. Want to read it in python. (Reading with FORTRAN and outputting text to read for python is not an option. Long story.) I can read the first record in a simplistic manner: >>> binfile=open('myfile','rb') >>> pad1=struct.unpack('i',binfile.read(4))[0] >>> ver=struct.unpack('d',binfile.read(8))[0] >>> pad2=struct.unpack('i',binfile.read(4))[0] >>> pad1,ver,pad2 (8,3.13,8) Just fine. But this is a big file and I need to do this more efficiently. So I try: >>> (pad1,ver,pad2)=struct.unpack('idi',binfile.read(16)) This won't run. Gives me an error and

I am writing a piece of code to read in several GB of data that spans multiple files using C++ IOStreams, which I've chosen over the C API for a number of design reasons that I won't bore you with. Since the data is produced by a separate program on the same machine where my code will run, I am confident that issues such as those relating to endianess can, for the most part, be ignored. The files have a reasonably complicated structure. For example, there is a header that describes the number of records of a particular binary configuration. Later in the file, I must make the code conditionally

Form view: <form enctype="multipart/form-data" ng-submit="upload(file)"> <input type="file" ng-model="modal.file" accept="image/gif" app-filereader /><br /> <br> <textarea name="description" placeholder="Description" ng-model="description" id="" cols="30" rows="10"></textarea> <br> <input type="hidden" name="user" ng-model="user" value="{{ user }}" /> <br> <input type="submit" value="Submit" class="network-sensitive button button-block button" /> </form> Directive: .directive('appFilereader', function( $q ){ var slice = Array.prototype.slice; return { restrict: 'A' , require: '?ngModel' , link

I'm not used to binary files, and I'm trying to get the hang of it. I managed to store some integers and unsigned char, and read them without too much pain. Now, when I'm trying to save some booleans, I see that each of my bool takes exactly 1 octet in my file, which seems logical since a lone bool is stored in a char-sized data (correct me if I'm wrong!). But since I'm going to have 3 or 4 bools to serialize, I figure it is a waste to store them like this : 00000001 00000001 00000000, for instance, when I could have 00000110. I guess to obtain this I should use bitwise operation, but I'm not