bigdecimal

Is there a C++ equivalent to Java's BigDecimal?

江枫思渺然 提交于 2019-12-27 14:43:18
问题 I'm looking for a C++ class that can do decimal floating point arithmetic. Looking through http://speleotrove.com/decimal/ there are links to all sorts of classes that people have written and not maintained. Digging through the decNumber++ stuff led me to some emails showing that GCC will eventually support this functionality. (Formally known as ISO/IEC TR 24733) I'm looking for something I can use as a drop-in replacement for float or double, something that other people are using in their

BigInteger类和BigDecimal类

扶醉桌前 提交于 2019-12-27 13:51:18
BigInteger java中long型为最大整数类型,对于超过long型的数据如何去表示呢.在Java的世界中,超过long型的整数已经不能被称为整数了,它们被封装成BigInteger对象.在BigInteger类中,实现四则运算都是方法来实现,并不是采用运算符. BigInteger类的构造方法: BigInteger b = new BigInteger(str); 构造方法中,采用 字符串的形式给出整数 四则运算代码: public static void main(String[] args) { //大数据封装为BigInteger对象 BigInteger big1 = new BigInteger("12345678909876543210"); BigInteger big2 = new BigInteger("98765432101234567890"); //add实现加法运算 BigInteger bigAdd = big1.add(big2); //subtract实现减法运算 BigInteger bigSub = big1.subtract(big2); //multiply实现乘法运算 BigInteger bigMul = big1.multiply(big2); //divide实现除法运算 BigInteger bigDiv = big2

Java:Why should we use BigDecimal instead of Double in the real world? [duplicate]

[亡魂溺海] 提交于 2019-12-27 10:44:29
问题 This question already has answers here : Double vs. BigDecimal? (6 answers) Closed 4 years ago . When dealing with real world monetary values, I am advised to use BigDecimal instead of Double.But I have not got a convincing explanation except, "It is normally done that way". Can you please throw light on this question? 回答1: It's called loss of precision and is very noticeable when working with either very big numbers or very small numbers. The binary representation of decimal numbers with a

BigDecimal()------用于小数的精确运算(参数必须是字符串)

梦想的初衷 提交于 2019-12-26 23:52:02
package cn.tedu.math; import java.math.BigDecimal; public class BigDecimalDemo { //strictfp—把计算过程提高到80位,但是最后还是以64位进行存储 public strictfp static void main(String[] args) { /* // double d=2.1-1.93; //没有精确运算 System.out.println(d);*/ //参数变为字符串才能进行精确运算 BigDecimal bd1=new BigDecimal("2.1"); BigDecimal bd2=new BigDecimal("1.93"); //两个对象值进行相减 System.out.println(bd1.subtract(bd2)); } } 输出: 0.17 代码图: 来源: CSDN 作者: 佳乐一百 链接: https://blog.csdn.net/qq_45453185/article/details/103722125

ActiveRecord column decimal default value

耗尽温柔 提交于 2019-12-25 03:57:20
问题 I have a tableless class defined like this: class MyClass class MyClassRules < ActiveRecord::Base column :a, :integer column :b, :boolean column :c, :datetime column :d, :decimal, :precision => 10, :scale => 4 column :e, :string end end The object of type MyClassRules gets automatically built when I instantiate an object of type MyClass , and it is stored serialized in a single column in the my_class table called rules and accessible from my_obj.rules . So I can also make calls like my_obj

Replacing/Overriding Java “native” Classes?

老子叫甜甜 提交于 2019-12-25 03:10:55
问题 I'm working with BigDecimal s and I have the requirement that a division by 0 should not result in an ArithmeticException , but in returning 0 instead (weird business math). This is a rather new requirement and we already have quite a bit of code, which uses BigDecimal s in a lot of places. I don't want to go through all these places and implement zero checks. This also would not help me with 3rd party libraries, which might internally use BigDecimal s and will throw an ArithmeticException

Recover the original number from a float

冷暖自知 提交于 2019-12-24 12:43:24
问题 Numbers are being stored in a database (out of my control) as floats/doubles etc. When I pull them out they are damaged - for example 0.1 will come out (when formatted) as 0.100000001490116119384765625 . Is there a reliable way to recover these numbers? I have tried new BigDecimal(((Number) o).doubleValue()) and BigDecimal.valueOf(((Number) o).doubleValue()) but these do not work. I still get the damaged result. I am aware that I could make assumptions on the number of decimal places and

BigDecimal Rounding modes

此生再无相见时 提交于 2019-12-24 10:51:02
问题 We are replacing some sybase code to Java and having issue with Rounding BigDecimal to match what sybase returns 11.4443999999999999062083588796667754650115966796875 - Should return 11.44 and 35.9549999999999982946974341757595539093017578125 - should return 35.96 I have tried all different rounding options with scale set to 2, but none works for both. What is the best option? 回答1: You'll have to take a two-step approach. First round to scale 3, then to scale 2, using RoundingMode.HALF_UP :

了解Spring中常见的设计模式-------------------装饰者模式

早过忘川 提交于 2019-12-24 10:49:45
装饰者模式(Decorator Pattern) 是指在不改变原有对象的基础上,将功能附加到对象上,提供比继承更优弹性的替换方案(扩展原有对象的功能),属于结构型模式。 适用场景: 1、用于扩展一个类的功能或给一个类添加附加的职责。 2、动态的给一个对象添加功能,这些功能可以再动态的撤销。 不加装饰类示例: public class AssembleComputer { private BigDecimal bigDecimal = new BigDecimal("6000"); public String getMsg() { return "电脑组装"; } public BigDecimal getPrice() { return bigDecimal; } } public class AddScreen extends AssembleComputer { private BigDecimal bigDecimal = new BigDecimal("1500"); @Override public String getMsg() { return super.getMsg() + "_增加显示器"; } @Override public BigDecimal getPrice() { return super.getPrice().add(bigDecimal); }

Multiply two numbers precisely in Java [duplicate]

此生再无相见时 提交于 2019-12-24 08:10:31
问题 This question already has answers here : BigDecimal from Double incorrect value? (3 answers) Closed 2 years ago . I was searching for a precise way to multiply two floating point numbers in Java, and I read that I should use BigDecimal, however it doesn't work as expected. What am I doing wrong? My code: BigDecimal a = new BigDecimal(3.53); BigDecimal b = new BigDecimal(3.59); BigDecimal c = a.multiply(b); System.out.println(c); Result: 12