beautifulsoup

问题 Using beautiful soup and python, I have undertaken some webscraping of the shown website to isolate: the rank, company name and revenue. I would like to show, in an html table that I am rendering using flask and jinja2, the results of the top ten companies in the table, however, the code I have written is just displaying the first record five times. Code in file: webscraper.py url = 'https://en.m.wikipedia.org/wiki/List_of_largest_Internet_companies' req = requests.get(url) bsObj =

问题 Using beautiful soup and python, I have undertaken some webscraping of the shown website to isolate: the rank, company name and revenue. I would like to show, in an html table that I am rendering using flask and jinja2, the results of the top ten companies in the table, however, the code I have written is just displaying the first record five times. Code in file: webscraper.py url = 'https://en.m.wikipedia.org/wiki/List_of_largest_Internet_companies' req = requests.get(url) bsObj =

问题 Using beautiful soup and python, I have undertaken some webscraping of the shown website to isolate: the rank, company name and revenue. I would like to show, in an html table that I am rendering using flask and jinja2, the results of the top ten companies in the table, however, the code I have written is just displaying the first record five times. Code in file: webscraper.py url = 'https://en.m.wikipedia.org/wiki/List_of_largest_Internet_companies' req = requests.get(url) bsObj =

问题 I have written the following code to get me information from a webpage that displays some products, and then on clciking 'load more', more products are displayed. On running the code below, I only get information for the first few products. I think the code is correct, there is a small error somewhere that I am not able to catch. Would be great if someone could help me resolve this. Thanks! from selenium import webdriver import time from bs4 import BeautifulSoup import requests import

问题 I have written the following code to get me information from a webpage that displays some products, and then on clciking 'load more', more products are displayed. On running the code below, I only get information for the first few products. I think the code is correct, there is a small error somewhere that I am not able to catch. Would be great if someone could help me resolve this. Thanks! from selenium import webdriver import time from bs4 import BeautifulSoup import requests import

问题 from bs4 import BeautifulSoup import urllib.request urls = [ "https://archillect.com/1", "https://archillect.com/2", "https://archillect.com/3", ] soup = BeautifulSoup(urllib.request.urlopen(urls)) for u in urls: for img in soup.find_all("img", src=True): print(img["src"]) AttributeError: 'list' object has no attribute 'timeout' 回答1: @krishna has given you the answer. I'll give you another solution for reference only. from simplified_scrapy import Spider, SimplifiedDoc, SimplifiedMain, utils

问题 from bs4 import BeautifulSoup import urllib.request urls = [ "https://archillect.com/1", "https://archillect.com/2", "https://archillect.com/3", ] soup = BeautifulSoup(urllib.request.urlopen(urls)) for u in urls: for img in soup.find_all("img", src=True): print(img["src"]) AttributeError: 'list' object has no attribute 'timeout' 回答1: @krishna has given you the answer. I'll give you another solution for reference only. from simplified_scrapy import Spider, SimplifiedDoc, SimplifiedMain, utils

问题 from bs4 import BeautifulSoup import urllib.request urls = [ "https://archillect.com/1", "https://archillect.com/2", "https://archillect.com/3", ] soup = BeautifulSoup(urllib.request.urlopen(urls)) for u in urls: for img in soup.find_all("img", src=True): print(img["src"]) AttributeError: 'list' object has no attribute 'timeout' 回答1: @krishna has given you the answer. I'll give you another solution for reference only. from simplified_scrapy import Spider, SimplifiedDoc, SimplifiedMain, utils

问题 I've tried to scrape yt-formatted strings with BeautifulSoup, but it always gives me an error. Here is my code: import requests import bs4 from bs4 import BeautifulSoup r = requests.get('https://www.youtube.com/channel/UCPyMcv4yIDfETZXoJms1XFA') soup = bs4.BeautifulSoup(r.text, "html.parser") def onoroff(): onoroff = soup.find('yt-formatted-string',{'id','subscriber-count'}).text return onoroff print("Subscribers: "+str(onoroff().strip())) This is the error I get AttributeError: 'NoneType'

问题 The below code provide information from all the numeric tags in the page. Can I use a filter to extract once for each region For example : https://opensignal.com/reports/2019/04/uk/mobile-network-experience , I am interested in numbers only under the regional analysis tab and for all regions. import requests from bs4 import BeautifulSoup html=requests.get("https://opensignal.com/reports/2019/04/uk/mobile-network-experience").text soup=BeautifulSoup(html,'html.parser') items=soup.find_all('div