base | 易学教程

Convert base-27 (or base-X) to base-10 in c#?

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Is there a ready made function to be able to do base conversions in c#? I am looking to convert from base 26 and base base 27 numbers to base 10. I can do it on paper but i am not a very experienced programmer and would rather not do it from scratch if possible. Thanks! There is a ready-made function to convert numbers from base 2, 8 or 16 to base 10 ( Convert.ToInt32 ). If you want to convert numbers from base 26 or base 27 to base 10, you'll have to do it yourself. Now, I've never heard of base 26 numbers, so I'm just going to assume the 'digits' are A to Z (A having a value of 0, and Z

Base91, how is it calculated?

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问题 I've been looking online to find out how basE91 is calculated. I have found resources such as this one which specifies the characters used for a specific value but nowhere have I found how I get that value. I have tried changing the input values into binary and taking chunks of both 6 and 7 bits but these do not work and I get the incorrect output. I do not want code that will do this for me as I which to write that myself, I only want to know the process needed to encode a string into basE91

C++学习(四)_继承

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1.继承的三大分类继承分为三类: 公共继承保护继承私有继承他们的特点如下图所示: 2.继承基本语法继承的好处: 减少重复代码语法: class 子类 : 继承方式父类子类也称派生类父类也称基类例1:不使用继承 #include <iostream> using namespace std; //Java页面 class Java { public: void header(){ cout << "header" << endl; } void footer(){ cout << "footer" << endl; } void left(){ cout << "left" << endl; } void content(){ cout << "***Java***" << endl; } }; class Python { public: void header(){ cout << "header" << endl; } void footer(){ cout << "footer" << endl; } void left(){ cout << "left" << endl; } void content(){ cout << "***Python***" << endl; } }; class Cpp{ public: void header(){

【题解】P4838 P哥破解密码

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P4838 P哥破解密码矩乘优化递推 (hint:N<=10e9,线性的都没法了) f[i][j](i ∈[ 1,n], j ∈ [0,2])，表示 n==i 时，一个数末尾有j个A的方案数。由于末尾有A的可能性只与上一状态中一个状态有关（1个A与0个A有关，2个A与1个A有关）。而末尾有0个AA的情况，只要塞一个B就行了。所以是上一状态中所有状态方案数之和。初始化： f[1][0]=1,f[1][1]=1,f[1][2]=0; 转移方程： f[i][0] = f[i - 1][2] + f[i - 1][1] + f[i - 1][0] f[i][1] = f[i - 1][0] f[i][2] = f[i - 1][1] 下文中坐标+了1 //1 1 0 /* 1 1 0 1 0 1 1 0 0 */ #define mod 19260817 struct Matrix{ int m[4][4]; Matrix(){mem(m,0);} friend Matrix operator *(Matrix a,Matrix b){ Matrix c; rep(i,1,3) rep(j,1,3) rep(k,1,3) c.m[i][j]=(c.m[i][j]+a.m[i][k]*b.m[k][j])%mod; return c; } friend Matrix operator

IE doesn't support relative paths in the base element when referencing CSS files

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I have a site that uses a base tag to set an absolute path for relative URLs. It works fine in all the browsers I tested it in, except IE (big surprise). Based on the request that IE is making for the CSS file, it seems not to notice the base tag. It does acknowledge the base tag with everything else on the page. Why is this happening? Can anything be done about it, besides using an absolute path to reference the CSS file? Here is my code: <!DOCTYPE html> <html><head> <title>base test</title> <base href="/baseTest/"> <link rel="stylesheet" type="text/css" href="style.css"> </head> <body> <div

R: rownames, colnames, dimnames and names in apply

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I would like to use apply to run across the rows of a matrix, and I would like to use the rowname of the current row in my function. It seems you can't use rownames , colnames , dimnames or names directly inside the function. I am aware that I can probably create a workaround based on information in this question . But my question is how does apply handle row and column names of the array in it's first argument, and the assignment of names to objects created inside the function called by apply ? It seems a bit inconsistent, as I hope to show by the following example. Is there a reason why it

个人项目WC

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---恢复内容开始--- 个人项目：WC 一，GitHub地址： https://github.com/Cercis-chinensis/wc 二， PSP表格 PSP2.1 Personal Software Process Stages 预估耗时（分钟）实际耗时（分钟）耗时占比 Planning 计划 30 20 1 Estimate · 估计这个任务需要多少时间 30 20 1 Development 开发 890 1710 92 Analysis · 需求分析 30 20 1 Design Spec · 生成设计文档 30 20 1 Design Review · 设计复审 40 20 1 Coding Standard · 代码规范 50 10 0.5 Design · 具体设计 60 170 10 Coding · 具体编码 600 1500 80 Code Review · 代码复审 20 60 3 Test · 测试（自我测试，修改代码，提交修改） 60 80 4 Reporting 报告 110 130 7 Test Report · 测试报告 60 80 4 Size Measurement · 计算工作量 40 30 1.5 Postmortem & Process Improvement Plan · 事后总结, 并提出过程改进计划 10 20 1

Make sure base method gets called in C#

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Can I somehow force a derived class to always call the overridden methods base? public class BaseClass { public virtual void Update() { if(condition) { throw new Exception("..."); // Prevent derived method to be called } } } And then in a derived class : public override void Update() { base.Update(); // Forced call // Do any work } I've searched and found a suggestion to use a non-virtual Update() but also a protected virtual UpdateEx(). It just doesn't feel very neat, isn't there any better way? I hope you get the question and I am sorry for any bad English. Use the template method pattern -

分布式CAP BASE理论

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分布式CAP理论( 来源 ) 一个分布式系统最多只能同时满足一致性（Consistency）、可用性（Availability）和分区容错性（Partition tolerance）这三项中的两项。对于关系型数据库，要求更新过的数据能被后续的访问都能看到，这是强一致性。如果能容忍后续的部分或者全部访问不到，则是弱一致性。如果经过一段时间后要求能访问到更新后的数据，则是最终一致性。 CAP中说，不可能同时满足的这个一致性指的是强一致性。 CA without P 分布式环境下，分区是必然的，所以如果舍弃P，意味着要舍弃分布式系统 CP without A 如果一个分布式系统不要求强的可用性，即容许系统停机或者长时间无响应的话，就可以在CAP三者中保障CP而舍弃A。 AP wihtout C 要高可用并允许分区，则需放弃一致性。一旦网络问题发生，节点之间可能会失去联系。为了保证高可用，需要在用户访问时可以马上得到返回，则每个节点只能用本地数据提供服务，而这样会导致全局数据的不一致性。孰优孰略，没有定论，只能根据场景定夺，适合的才是最好的。对于涉及到钱财这样不能有一丝让步的场景，C必须保证。网络发生故障宁可停止服务，这是保证CP，舍弃A。比如前几年支付宝光缆被挖断的事件，在网络出现故障的时候，支付宝就在可用性和数据一致性之间选择了数据一致性，用户感受到的是支付宝系统长时间宕机

x86 SWAPGS

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在中断或异常处理的entry代码处, 会执行SWAPGS切换到kernel GS, GS.base 是存储了中断stack 的地址。 1、关于swapgs指令，手册描述如下： When FS and GS segment overrides are used in 64-bit mode, their respective base addresses are used in the linear address calculation: (FS or GS).base + index + displacement. FS.base and GS.base are then expanded to the full linear-address size supported by the implementation. The resulting effective address calculation can wrap across positive and negative addresses; the resulting linear address must be canonical. 1）The SWAPGS instruction is available only in 64-bit mode. It swaps the contents of two

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