auto-generate

Add a web reference to a project but make the auto-generated proxy classes internal (i.e. not public)

由 岁酱吖の 提交于 2019-12-12 13:16:16
问题 I'm building a class library that uses a web reference in its data access layer, but much to my dismay, there doesn't seem to be an acceptable way to set the access for the auto-generated proxy classes. By default, they're public , but I don't want to expose the proxy classes outside the library. I've found this on MSDN, but all the answers indicate manually altering the proxy classes to set the access modifiers. Not surprisingly, the proxy classes all have this at the top: //----------------

Auto Class Generator

由 天大地大妈咪最大 提交于 2019-12-11 17:48:51
问题 I had originally asked this question here: Former Question It appears that what I was asking for was misunderstood. I will try to make this as clear and as brief as possible: I'm working on a parser that will automatically generate a c++ class and if the names of the header and cpp files are present the parser will write out those files respectively. If they are omitted then the parser will not write any files where it will generate a class automatically based on the information that is

How are ids autogenerated in spring data couchbase?

由 冷暖自知 提交于 2019-12-11 06:58:38
问题 I want to create autogeneration of IDs to my documents in spring data couchbase. Spring docs has steps for this: https://docs.spring.io/spring-data/couchbase/docs/current/reference/html/#couchbase.autokeygeneration Here is my code: @Document public class User { @Id @GeneratedValue(strategy = GenerationStrategy.USE_ATTRIBUTES, delimiter = ".") private String id; @IdPrefix(order=0) private String userPrefix; @IdSuffix(order=0) private String userSuffix; ... } I've a repository created for this:

Generate Unique Long ID for a view in MySql

由 ＊爱你＆永不变心＊ 提交于 2019-12-11 04:45:38
问题 I have a view over three tables. It has 6 columns as follows: ID | NAME | PRINCIPAL_ID | DESCRIPTION | GROUP_ID | TYPE As I'm using hibernate to retrieve data from database, I had to put the ID column in this view. The problem is, I cannot generate a unique ID which seems to be necessary for hibernate to correctly load the data. How can I have a unique ID for every row in this view? Maybe this can help, I'm not sure : The combination of PRINCIPAL_ID and GROUP_ID can make a unique ID. All

How can I generate the database from .edmx file in Entity Framework?

由 核能气质少年 提交于 2019-12-10 12:59:55
问题 I have had to suddenly switch to working on Code First Entity Framework 4.1. I started off not knowing anything about this framework but in the last 8 hrs I am now much more comfortable having read blogs and articles. This blog in particular is one of the best blogs I have seen so far on the topic but the steps given do not match with my experience. In particular, I need more focus on the 3rd and 4th steps ('Create the Model' and 'Swap to DbContext Code Generation', respectively). I am unable

Creating a single random Magento coupon

由 断了今生、忘了曾经 提交于 2019-12-09 13:42:25
问题 I'm having some trouble. What I want to do is automatically generate a single random coupon code in Magento each time someone subscribes to our newsletter. The coupon is 10 dollars off anything and will have an exp. date of two weeks after subscription. So, I'm trying to write a simple script that trips when the "subscribe to our newsletter" form is submitted that will talk to Magento, ask Magento for a single random coupon code, set a few basic price rules (10 bucks off anything, one use per

Freeze asp.net grid view column

由 回眸只為那壹抹淺笑 提交于 2019-12-09 00:08:12
问题 How can i freeze initial 2 -3 leftmost column in asp.net grid view? so that while horizontal scrolling initial 2 - 3 columns that got freezes will always be display. Any answers?? 回答1: Yes, it seems to be possible with some css magic, with the pinned and scrollable columns on different z-indexes to keep the pinned on top. This comes with the caveat that overflow:scroll may not be 100% portable (I've tested on IE 8/9 and Chrome FWIW). Take a look at this jsFiddle here The ASPX I used to

Force WPF DataGrid to regenerate itself

由 随声附和 提交于 2019-12-08 18:05:31
问题 I have a custom control which inherits from DataGrid and is basically a 2D DataGrid (accepts an ItemsSource with two dimensions, such as double[,] ). I added a specific DependencyProperty which is ColumnHeaders and RowHeaders so I can define them. Here is how it works right now: I bind a 2D ItemsSource to the DataGrid A wrapper method will take this source to transform it to a classic IEnumerable bindable to the actual datagrid's ItemsSource Each row / column auto-generated is done using the

Auto Generate String Primary Key with Annotation in Hibernate

由 人走茶凉 提交于 2019-12-08 08:24:31
问题 I'm pretty new to Spring Boot and in the model there's an Id (primary key) which is String and I need to auto-generate it when saving new entity. @Id @GeneratedValue(strategy = GenerationType.AUTO) private String id; private String name; private String description; But, I get this error when saving a new entity. "message": "Unknown integral data type for ids : java.lang.String; nested exception is org.hibernate.id.IdentifierGenerationException: How to avoid this error and do the auto

Inheriting from a UserControl abstract subclass

由 情到浓时终转凉″ 提交于 2019-12-06 12:25:09
I have a set of UserControls that need to have a few similar properties. Thus I have defined an abstract subclass of UserControl that defines these properties and updated the .xaml.cs and .g.cs files to inherit from this base class. All compiles well and runs well. Great! But.... .g.cs files are generated and will be regenerated, so how do I tell Blend or Visual Studio to keep inheriting from my base class rather than UserControl? You need to change the XAML a bit to prefix the UserControl declaration with a namespace: <local:MyBaseControl x:Class="MyNameSpace.MyControl" xmlns:local="clr
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