assign

Succinctly assign names and values simultaneously

拥有回忆 提交于 2019-12-04 22:50:57
问题 I find myself often writing the following two lines. Is there a succinct alternative? newObj <- vals names(newObj) <- nams # This works, but is ugly and not necessarily preferred 'names<-'(newObj <- vals, nams) I'm looking for something similar to this (which of course does not work): newObj <- c(nams = vals) Wrapping it up in a function is an option as well, but I am wondering if the functionality might already be present. sample data vals <- c(1, 2, 3) nams <- c("A", "B", "C") 回答1: You want

How to catch a particular name assignment?

▼魔方 西西 提交于 2019-12-04 22:24:32
(Based on this question ): One can override the __setattr__ magic method for an object to have additional instructions when an attribute of an object is set. As in: class MyClass(object): def __init__(self, attribute=None): object.__init__(self) self.attribute = attribute def __setattr__(self, name, value): self.__dict__[name] = value if name == 'attribute': print("attribute's value is modified to {}.".format( self.attribute)) if __name__ == '__main__': my_obj = MyClass(True) while True: my_obj.attribute = input() How can I catch a particular name assignment in the current script without using

Efficiency in assigning programmatically in R

耗尽温柔 提交于 2019-12-04 21:24:04
In summary, I have a script for importing lots of data stored in several txt files. In a sigle file not all the rows are to be put in the same table (DF now switching to DT), so for each file I select all the rows belonging to the same DF, get DF and assign to it the rows. The first time I create a DF named ,say, table1 I do: name <- "table1" # in my code the value of name will depend on different factors # and **not** known in advance assign(name, someRows) Then, during the execution my code may find (in other files) other lines to be put in the table1 data frame, so: name <- "table" assign

Assign MySQL database value to PHP variable

柔情痞子 提交于 2019-12-04 20:02:58
I have a MySQL Database Table containing products and prices. Though an html form I got the product name in a certain php file. For the operation in this file I want to do I also need the corresponding price. To me, the following looks clear enough to do it: $price = mysql_query("SELECT price FROM products WHERE product = '$product'"); However, its echo returns: Resource id #5 instead a value like like: 59.95 There seem to be other options like mysqli_fetch_assoc mysqli_fetch_array But I can't get them to output anything meaningful and I don't know which one to use. Thanks in advance. You will

Creating multiple plots in ggplot with different Y-axis values using a loop

不想你离开。 提交于 2019-12-04 16:38:00
I am trying to create multiple scatter plot graphs in ggplot that have the same structure but with a different Y-value. I need them to be separate (and therefore not use facet_wrap) because in a later step I use grid_arrange to arrange different combinations of the graphs onto a single layout. Because of this, I need to create new names for each plot that reflect the y-value being plotted. Below is sample code, where month is the variable on the x-axis and I want three separate plots of month vs. the three additional variables (lag1_var, lag3_var and lag9_var). df <- data.frame (month= c(1, 2,

How is allocator-aware container assignment implemented?

只愿长相守 提交于 2019-12-04 10:16:34
For example, from std::deque::operator = in C++ Reference: (1) Copy Assignment (const std::deque &other) Replaces the contents with a copy of the contents of other. If std::allocator_traits::propagate_on_container_copy_assignment() is true, the target allocator is replaced by a copy of the source allocator. If the target and the source allocators do not compare equal, the target (*this) allocator is used to deallocate the memory, then other's allocator is used to allocate it before copying the elements. If this->get_allocator() == other.get_allocator() , I can simply destroy and deallocate

Assign multiple values of a list

帅比萌擦擦* 提交于 2019-12-04 08:25:24
问题 I am curious to know if there is a "pythonic" way to assign the values in a list to elements? To be clearer, I am asking for something like this: myList = [3, 5, 7, 2] a, b, c, d = something(myList) So that: a = 3 b = 5 c = 7 d = 2 I am looking for any other, better option than doing this manually: a = myList[0] b = myList[1] c = myList[2] d = myList[3] 回答1: Simply type it out: >>> a,b,c,d = [1,2,3,4] >>> a 1 >>> b 2 >>> c 3 >>> d 4 Python employs assignment unpacking when you have an

Re-assign column values in a pandas df

為{幸葍}努か 提交于 2019-12-04 08:11:31
问题 This question is related to rostering or staffing. I'm trying to assign various jobs to individuals (employees). Using the df below, `[Person]` = Individuals (employees) `[Area]` and `[Place]` = unique jobs `[On]` = How many unique jobs are occurring at each point in time So [Area] and [Place] together will make up unique values that are different jobs. These values will be assigned to individuals with the overall aim to use the least amount of individuals possible. The most unique values

OK to retain ASIHTTPRequest delegate?

让人想犯罪 __ 提交于 2019-12-04 05:41:35
问题 Is it OK to retain a delegate of a subclass of ASIHTTPRequest ? I made a subclass of ASIHTTPRequest called JSONRequest . Each instance of JSONRequest is its own delegate, handles the callbacks, and passes them on to jsonDelegate , which is a private property of JSONRequest , and responds to requestFinished:withResult: , where result is an NSDictionary representation of the JSON response. To do this, I overloaded setDelegate: in JSONRequest to do super.delegate = self; self.jsonDelegate =

different results for standard form and functional form of data.table assigne-by-reference `:=`

百般思念 提交于 2019-12-04 04:37:53
There seems to be a minor difference between data.tabel's assignment by reference := in the standard to the functinal form. Standard form coerces RHS to vector, the functional form does not. A detail, but not documented as I believe. library(data.table) dt <- data.table(a = c('a','b','c')) v <- c('A','B','C') l <- list(v) all.equal(copy(dt)[, new := v], copy(dt)[, `:=` (new = v)]) # [1] TRUE all.equal(copy(dt)[, new := l], copy(dt)[, `:=` (new = l)]) # [1] "Datasets have different column modes. First 3: new(character!=list)" copy(dt)[, new := l][] # a new # 1: a A # 2: b B # 3: c C copy(dt)[,