ascii

问题 I have a scalar value function that returns a varchar of data containing the ASCII unit seperator Char(31). I am using this result as part of an Order By clause and attempting to sort in ascending order. My scalar value function returns results like the following (nonprintable character spelled out for reference) ABC ABC (CHAR(31)) DEF ABC (CHAR(31)) DEF (CHAR(31)) HIJ I would expect that when I order by ascending the results would be the following: ABC ABCDEF ABCDEFHIJ instead I am seeing

问题 I have a scalar value function that returns a varchar of data containing the ASCII unit seperator Char(31). I am using this result as part of an Order By clause and attempting to sort in ascending order. My scalar value function returns results like the following (nonprintable character spelled out for reference) ABC ABC (CHAR(31)) DEF ABC (CHAR(31)) DEF (CHAR(31)) HIJ I would expect that when I order by ascending the results would be the following: ABC ABCDEF ABCDEFHIJ instead I am seeing

问题 I've just started learning how to program in C and I'm trying to make a program that accepts a number and uses it as an ASCII value to return the ASCII character associated with that value. The program works when the parameters are predefined but when I introduce the scanf function it compiles but doesnt give me the same results. Here is my code : #include <stdio.h> int main(void) { question2(); return 0; } int question2(void) { int myInt = 65; scanf("%d", myInt); char ch = myInt; printf("%c"

问题 How can we show asian unicode values in UILabel \U2013\U00ee\U2013\U00e6\U2013\U2202\U2013\U220f\U2013\U03c0 \U2013\U00ee\U2013\U220f\U2013\U03c0\U2013\U00aa\U2013\U221e\U2014\U00c5 Thanks 回答1: I'm not sure what is particularly “Asian” about that text, U+2013 is an en-dash (–) U+00ee is a lowercase ‘i’ with a circumflex (î) U+00e6 is the old ligature for ae (æ) U+2202 is the character for a partial differential (∂). If your program is being localised [that is to say that the program will be

问题 I am printing receipts using Dot Matrix Printer in C#. The printer works perfectly, prints characters in bold, large size etc. The problem is dot matrix have ribbons in it (Black color, Red Color) How can i specify which text is to be printed in black or red. I am using BinaryWriter to pass string and ascii code to get desired output. Example: bw.Write((byte)0); byte[] bytes = Encoding.ASCII.GetBytes(text); foreach (var by in bytes) { bw.Write((byte)by); } Some Sample Code Reference: Sample

问题 Related Question I do have to show different Ascii character in TextView . Character are: ( `·´ ) (\\/)(°,,,°)(\\/) ( ⚆ _ ⚆ ) If I used above character and display on screen. I got this: But when you look at the first character . It's displaying the wrong image. It supposed to be like this: I have never worked on Ascii character like this. Question How can I handle these type of situations? Is there any libraries exist? Any help would be appreciable. Edit-1 layout file Layout file is a

问题 I'm trying to break down an integer with C on an 8-bit microcontroller (a PIC) into its ASCII equivalent characters. For example: convert 982 to '9','8','2' Everything I've come up with so far seems pretty brute force. This is the main idea of what I'm basically doing right now: if( (10 <= n) && (n < 100) ) { // isolate and update the first order of magnitude digit_0 = (n % 10); // isolate and update the second order of magnitude switch( n - (n % 10) ) { case 0: digit_1 = 0; break; case 10:

问题 is a better, shorter way to preform this code: /*Replace all letters by their respective ASCII code - 55*/ as_iban := REPLACE(as_iban, 'A', '10'); as_iban := REPLACE(as_iban, 'B', '11'); as_iban := REPLACE(as_iban, 'C', '12'); as_iban := REPLACE(as_iban, 'D', '13'); as_iban := REPLACE(as_iban, 'E', '14'); as_iban := REPLACE(as_iban, 'F', '15'); as_iban := REPLACE(as_iban, 'G', '16'); as_iban := REPLACE(as_iban, 'H', '17'); as_iban := REPLACE(as_iban, 'I', '18'); as_iban := REPLACE(as_iban, 'J

问题 So I wonder if it is possible to allow user to enter only ASCII as installation path? (warn him and make input path again) (problem is application we install is old and can not work with Cyrillic paths so we need to restrict user on installation stage) 回答1: To restrict the user input for the application directory for the Basic Latin character set you may use the following code. The code only checks if any char of the selected directory name doesn't exceed the Basic Latin character set range.

问题 I am able to convert an NSString of (ASCII) text to a NSString of binary numbers, but I am having troubles doing the opposite. For example: "Hi" becomes "01101000 01101001". I need: "01101000 01101001" to become "Hi". I'm looking for the most direct way to implement this. Note the space between every 8 bits of binary numbers. 回答1: Considering the format is always like that, this code should work: NSString * BinaryToAsciiString (NSString *string) { NSMutableString *result = [NSMutableString