arraylist

select mongodb aray element in a single field in pentaho PDI

天大地大妈咪最大 提交于 2020-12-15 06:32:27
问题 Following is the structure of the document i have in a collection in MongoDB { "_id": { "$oid": "5f48e358d43721376c397f53" }, "heading": "this is heading", "tags": ["tag1","tag2","tag3"], "categories": ["projA", "projectA2"], "content": ["This", "is", "the", "content", "of", "the", "document"], "timestamp": 1598612312.506219, "lang": "en" } When i am importing data in PDI using the mongodb input step the system is putting each array of the "content" element in a different field I want to

Converting each line from a list of integers into an array of integers?

淺唱寂寞╮ 提交于 2020-12-15 06:16:34
问题 I'm new to Java, so apologies if any of this is unclear - I want to convert a list of four-digit integers into a list of integer arrays - i.e if I have an integer that is 4567, I want to convert that into an array of four separate integers [4, 5, 6, 7]. So I want to convert each line/index of the list into it's own array (rather than converting the entire list into an array). I'm currently reading a file that has four-digit integers (each on a new line) and adding them to a list, which is

Converting each line from a list of integers into an array of integers?

我的未来我决定 提交于 2020-12-15 06:13:51
问题 I'm new to Java, so apologies if any of this is unclear - I want to convert a list of four-digit integers into a list of integer arrays - i.e if I have an integer that is 4567, I want to convert that into an array of four separate integers [4, 5, 6, 7]. So I want to convert each line/index of the list into it's own array (rather than converting the entire list into an array). I'm currently reading a file that has four-digit integers (each on a new line) and adding them to a list, which is

Converting each line from a list of integers into an array of integers?

随声附和 提交于 2020-12-15 06:12:02
问题 I'm new to Java, so apologies if any of this is unclear - I want to convert a list of four-digit integers into a list of integer arrays - i.e if I have an integer that is 4567, I want to convert that into an array of four separate integers [4, 5, 6, 7]. So I want to convert each line/index of the list into it's own array (rather than converting the entire list into an array). I'm currently reading a file that has four-digit integers (each on a new line) and adding them to a list, which is

How to implement hashCode and equals method to remove duplicates from ArrayList

故事扮演 提交于 2020-12-13 02:57:07
问题 I'm getting data from database model Income. This is how it looks @Table(name = "Income") public class Income extends Model { @Column(name = "AmountDate") public String amountDate; @Column(name = "Amount") public Double amount; @Column(name = "Day") public int day; @Column(name = "Month") public int month; @Column(name = "Year") public int year; } In my fragment I'm getting all Income data from database. In my BaseAdapter I would like to create ArrayList with month and year in it. It would

How to pass arraylist from servlet to javascript?

微笑、不失礼 提交于 2020-12-12 02:07:22
问题 I'm passing an arraylist from servlet by setting it in the attribute and forwarding it to the jsp Servlet: ArrayList <String> mylist = new ArrayList <String>(); mylist.add("Superman"); mylist.add("batman"); mylist.add("flash"); request.setAttribute("mylist", mylist); request.getRequestDispatcher("Welcome.jsp").forward(request, response); response.sendRedirect("Index.jsp"); Index.jsp function doPopulateList(obj) { alert("HELLO"+obj.id +obj.name+obj.value); var select = document

Initialize ArrayList<Long>

旧巷老猫 提交于 2020-12-02 10:46:18
问题 Why I can initialize ArrayList, like this: ArrayList<Integer> x = new ArrayList<Integer>(Arrays.asList(1,2)); But got Error when using: ArrayList<Long> x = new ArrayList<Long>(Arrays.asList(1,2)); 回答1: Explanation Java automatically transforms int to long if needed. However, Java does not do the same if a transformation from Integer to Long is needed. The function Arrays.asList(...) returns a List<E> with E being the type used as parameters. As you use 1, 2, 3 the type is int . However the

Initialize ArrayList<Long>

China☆狼群 提交于 2020-12-02 10:43:23
问题 Why I can initialize ArrayList, like this: ArrayList<Integer> x = new ArrayList<Integer>(Arrays.asList(1,2)); But got Error when using: ArrayList<Long> x = new ArrayList<Long>(Arrays.asList(1,2)); 回答1: Explanation Java automatically transforms int to long if needed. However, Java does not do the same if a transformation from Integer to Long is needed. The function Arrays.asList(...) returns a List<E> with E being the type used as parameters. As you use 1, 2, 3 the type is int . However the

Java initialize 2d arraylist

大憨熊 提交于 2020-11-30 14:58:21
问题 I want to do 2D dynamic ArrayList example: [1][2][3] [4][5][6] [7][8][9] and i used this code: ArrayList<ArrayList<Integer>> group = new ArrayList<ArrayList<Integer>>(); group.add(new ArrayList<Integer>(1, 2, 3)); how should i initialize this arraylist? 回答1: If it is not necessary for the inner lists to be specifically ArrayList s, one way of doing such initialization in Java 7 would be as follows: ArrayList<List<Integer>> group = new ArrayList<List<Integer>>(); group.add(Arrays.asList(1, 2,

Java initialize 2d arraylist

佐手、 提交于 2020-11-30 14:55:33
问题 I want to do 2D dynamic ArrayList example: [1][2][3] [4][5][6] [7][8][9] and i used this code: ArrayList<ArrayList<Integer>> group = new ArrayList<ArrayList<Integer>>(); group.add(new ArrayList<Integer>(1, 2, 3)); how should i initialize this arraylist? 回答1: If it is not necessary for the inner lists to be specifically ArrayList s, one way of doing such initialization in Java 7 would be as follows: ArrayList<List<Integer>> group = new ArrayList<List<Integer>>(); group.add(Arrays.asList(1, 2,