arguments

Passing A Variable Number of Arguments into a Function

≯℡__Kan透↙ 提交于 2019-12-25 12:26:15
问题 In Matlab, I have a variable length cell of values: C={A1,...,An} How should I pass and distribute these values into a function able to receive a variable number of arguments? f(A1,...,An) Ultimately if not possible, how should I modify the beginning of this function for making this work? 回答1: You need to convert the cell array into a comma-separated list via curly-brace indexing, that is, use C{:} . Example with the reshape function: >> C = {ones(3,4), 2, 2, 3}; >> y = reshape(C{:}); >> size

Passing A Variable Number of Arguments into a Function

北城以北 提交于 2019-12-25 12:26:10
问题 In Matlab, I have a variable length cell of values: C={A1,...,An} How should I pass and distribute these values into a function able to receive a variable number of arguments? f(A1,...,An) Ultimately if not possible, how should I modify the beginning of this function for making this work? 回答1: You need to convert the cell array into a comma-separated list via curly-brace indexing, that is, use C{:} . Example with the reshape function: >> C = {ones(3,4), 2, 2, 3}; >> y = reshape(C{:}); >> size

Convert input of an anonymous function

邮差的信 提交于 2019-12-25 12:11:51
问题 I have an anonymous function A taking two arguments. I need to convert this function so it takes one argument, by changing the other argument to a constant. For example having a function: A = @(X, Y) X + Y; I would like now to have: B = @(Y) 3 + Y; This seems to be a normal thing to do in mathematics, so I guess there is a way to do such thing in MATLAB. I cannot find the solution though. The reason I need to do something like this is that I have a function that does some calculations on A ,

Using getopts to read one optional parameter placed as final place

拥有回忆 提交于 2019-12-25 10:31:20
问题 I wrote a bash script that takes flexible number of parameters and now I would like to add an optional argument ( -l ) to each of them. I am currently having difficulty getting the desired behavior. I want all of the following to execute correctly: ./Script.sh arg1 arg2 arg3 -l opt ./Script.sh arg1 arg2 arg3 ./Script.sh arg1 arg2 arg3 arg4 -l opt ./Script.sh arg1 arg2 arg3 arg4 arg5 The problem is that $OPTIND cannot be set. The following loop works if the -l opt is placed before first

How to pass arguments from the previous then statement to the next one

谁都会走 提交于 2019-12-25 09:26:11
问题 I am having fun with Promises and have one problem. Here is my code req.checkBody(BookManager.SCHEME); req.getValidationResult() .then(function (result) { if (!result.isEmpty()) { handler.onError('Invalid payload'); return; } return new BookModel({ author: data.author, name: data.name, year: data.year }); }) .then((book) => { book.save(); }) .then((saved) => { handler.onSuccess(saved); }) .catch((error) => { handler.onError(error.message); }); But for some reason this then statement .then(

Echo: Argument List too long

喜欢而已 提交于 2019-12-25 07:39:57
问题 I'm running into an issue where my argument list for echo is too long and would like some ideas on how to get around this issue, or at least test for the condition so I can properly handle it, and it won't kill my script for file in `cat filelist`; do PROTOCOLS1=`egrep -i 'rsh|rsync|remsh' "$file" | egrep -v '^[ | ]*#'` FIELDS=`echo $PROTOCOLS1|wc -l` if [[ $FIELDS -gt 1024 ]]; then echo $file >> $debuglog else set -A myarray $PROTOCOLS1 do stuff..... fi done So the problem is that when my

What is the best way to supply many arguments to an if statement?

梦想与她 提交于 2019-12-25 06:59:27
问题 I have created a form with several user inputs but have the tedious task of checking whether each individual input is not empty before submission. Is there a quicker way, (such as using arrays perhaps) of listing all arguments to the if statement? At the moment my code looks like this but if possible I would like it to be more efficient in future, like if I were to add more inputs. <form action="sign-up.php" method="post" autocomplete="off" > Name:<input type="text" name="name" /> Username:<

List as a function argument - modifications discarded

北慕城南 提交于 2019-12-25 06:54:20
问题 I have a following code def hidePasswords(L, password): for elem in L: if elem == password: elem = "*"*len(password) return L print(hidePasswords(["test","test1","test8"],"test")) It returns ['test', 'test1', 'test8'] instead of ['****', 'test1', 'test8'] . When I change my function to def hidePasswords(L, password): temp = [] for elem in L: if elem == password: elem = "*"*len(password) temp.append(elem) return temp it works correctly. Why does Python behaves in such a way? I perfectly

Rails 4 Error: ArgumentError - wrong number of arguments

懵懂的女人 提交于 2019-12-25 04:48:15
问题 I am pretty new to rails and currently coding my first application. I created a search to search through my Users (either usernames or tags - using acts_as_taggable_on gem). Following error appears: ArgumentError in UsersController#index wrong number of arguments (0 for 1) User Model # Search def self.search(search) if search where(["username LIKE ?", "%#{search}%"]) elsif searchtags none else all end end # Search Tags def self.searchtags(searchtags) if searchtags tagged_with(["#{searchtags}"

Too many arguments to method call, expected 1, have 2?(Xcode)

社会主义新天地 提交于 2019-12-25 04:46:21
问题 There are many other similar questions to this one, but there is a lack of answers and they vary for each project. I have this error 'Too many arguments to method call, expected 1, have 2?' But on the previous arrays that I used this error did not occur? it could be a problem with the code but i am unsure? I have went through searching for other errors that may influence it, but have had no luck. Below is my coding, #import "MenuViewController.h" #import "ECSlidingViewController.h" @interface