arguments

Is there a limit to the number of arguments passed to a fortran function?

只愿长相守 提交于 2020-01-10 05:27:28
问题 I came across some Fortran 90 code where 68 arguments are passed to a function. Upon searching the web I only found something about a limit of passing 256 bytes for some CUDA Fortran related stuff (http://www.pgroup.com/userforum/viewtopic.php?t=2235&sid=f241ca3fd406ef89d0ba08a361acd962). So I wonder: is there a limit to the number of arguments that may be passed to a function for Intel/Visual/GNU fortran compilers? 回答1: I came across this discussion of the Fortran 90 standards: http://www

passing one list of values instead of mutiple arguments to a function?

筅森魡賤 提交于 2020-01-10 02:05:48
问题 Lets say there's a function func() which takes two arguments, a and b . Is there some kind of technique in Python to pass a single list mylist which has both values to the function instead? def myfunc(a, b): return a+b myfunc([1, 2]) If one was completely sure that he was always calling the same function and knew how many arguments it takes, one could do something like this: mylist = [1, 2] a, b = mylist myfunc(a, b) But what if you have lists you need to feed to certain functions, and each

ES6 destructuring function parameter - naming root object

≡放荡痞女 提交于 2020-01-09 11:39:29
问题 Is there a way to retain the name of a destructured function argument? I.e., the name of the root object? In ES5, I might do this (using inheritance as a metaphor to make the point): // ES5: var setupParentClass5 = function(options) { textEditor.setup(options.rows, options.columns); }; var setupChildClass5 = function(options) { rangeSlider.setup(options.minVal, options.maxVal); setupParentClass5(options); // <= we pass the options object UP }; I'm using the same options object to hold

ES6 destructuring function parameter - naming root object

不打扰是莪最后的温柔 提交于 2020-01-09 11:39:11
问题 Is there a way to retain the name of a destructured function argument? I.e., the name of the root object? In ES5, I might do this (using inheritance as a metaphor to make the point): // ES5: var setupParentClass5 = function(options) { textEditor.setup(options.rows, options.columns); }; var setupChildClass5 = function(options) { rangeSlider.setup(options.minVal, options.maxVal); setupParentClass5(options); // <= we pass the options object UP }; I'm using the same options object to hold

Is there a way to use C++ preprocessor stringification on variadic macro arguments?

喜欢而已 提交于 2020-01-09 07:35:49
问题 My guess is the answer to this question is no, but it would be awesome if there was a way. To clarify, assume I have the following macro: #define MY_VARIADIC_MACRO(X...) // Does some stuff here in the macro definition What I would like to do is somehow perform stringification on all the variables of X before passing it to a variadic function; the keyword here is before. I realize there's no way to really access the individual arguments from within the macro definition, but is there a way to

Is there a way to use C++ preprocessor stringification on variadic macro arguments?

六月ゝ 毕业季﹏ 提交于 2020-01-09 07:35:30
问题 My guess is the answer to this question is no, but it would be awesome if there was a way. To clarify, assume I have the following macro: #define MY_VARIADIC_MACRO(X...) // Does some stuff here in the macro definition What I would like to do is somehow perform stringification on all the variables of X before passing it to a variadic function; the keyword here is before. I realize there's no way to really access the individual arguments from within the macro definition, but is there a way to

Is it safe to rely on Python function arguments evaluation order? [duplicate]

☆樱花仙子☆ 提交于 2020-01-09 03:43:10
问题 This question already has answers here : Is Python's order of evaluation of function arguments and operands deterministic (+ where is it documented)? (2 answers) Closed 2 years ago . Is it safe to assume that function arguments are evaluated from left to right in Python? Reference states that it happens that way but perhaps there is some way to change this order which may break my code. What I want to do is to add time stamp for function call: l = [] l.append(f(), time.time()) I understand

error in if() argument is of length zero in R

寵の児 提交于 2020-01-07 08:26:08
问题 This is the code ` region<-"ARLINGTON" data<-read.csv("city_markets.csv") for(i in 1:length(data[[1]])){ if(grep(region,as.character(data[[3]][i]),ignore.case=TRUE)==1){ for(j in 1:length(data)){ write(data[[j]][i],"analyzed.txt",append=TRUE) } } } ` now what i'm trying to do here is I'm accessing the csv's column(3rd one) and comparing it with the region specified! i keep getting the error Error in if (grep(region, as.character(data[[3]][i]), ignore.case = TRUE) == : argument is of length

Declare dummy (unused) parameters for Clojure anonymous function

て烟熏妆下的殇ゞ 提交于 2020-01-07 02:37:05
问题 As also explained in the answers of this question, Clojure determines the number of parameters of an anonymous function (defined through #() ), by the maximal parameter index referenced in the body (e.g. if the maximal referenced parameter is %4 , then that anonymous function has 4 parameters). Question: is there some syntax to tell the Clojure compiler that an anonymous function expects one parameter, even not referencing that parameter? Or, in this case, the only "clean way"* is to use the

Passing a function as argument to other function

一笑奈何 提交于 2020-01-06 05:57:45
问题 I have been reading about this theme. I have readed a lot of possible solutions, so please, dont mark my question as duplicated, only need a puntual solution of this problem. I have a function which calculate time of execution of some code. This code will be sent as argument (will be a function). This is the function which calculate the time: double executionTime( /* HERE I WANNA PASS THE FUNCTION TO CALCULATE EXECTIME*/ ) { LARGE_INTEGER frequency; LARGE_INTEGER start; LARGE_INTEGER end;