argparse

python中关于传递参数模块argprase的一些小坑

由 ▼魔方 西西 提交于 2019-12-08 17:52:27
今天在写代码的时候遇到了一个关于parser的一些小坑，记录在此备用。 我们知道在python中可以用argprase来传递一些参数给代码执行，来看下面的例子，假设现在有一个test文件夹，下面有3个python文件，分别用a.py；b.py；c.py来表示，目录树如下。 每一个的初始代码为一个简单的print函数。 1 #a.py 2 def out_a(): 3 print("I am a.py") 4 5 6 if __name__ == '__main__': 7 out_a() 1 #b.py 2 def out_b(): 3 print("I am b.py") 4 5 6 if __name__ == '__main__': 7 out_b() 1 #c.py 2 def out_c(): 3 print("I am c.py") 4 5 6 if __name__ == '__main__': 7 out_c() 现在在a.py中引入模块argprase，并定义一些简单的参数，代码如下 1 import argparse 2 parser = argparse.ArgumentParser() 3 parser.add_argument('--first_parameter', default='first') 4 parser.add_argument('-

Python argparse: metavar and action=store_true together

由 不羁的心 提交于 2019-12-08 15:55:36
问题 I'm using argparse module in Python to parse parameters typed in a command line interface. I have the following add_argument call to a subparser object: submit_parser.add_argument('-pv','--provision',metavar='PROVISION', dest='PROVISION', help='provision system', action='store_true', default=False, required=False) I get this error: Traceback (most recent call last): File "./scripts/tp4", line 94, in <module> main() File "./scripts/tp4", line 74, in main modloader.loadModules(sub_parsers) File

Python - Pass Arguments to Different Methods from Argparse

由 陌路散爱 提交于 2019-12-08 15:09:57
问题 I'm writing a relatively simple Python script which supports a couple of different commands. The different commands support different options and I want to be able to pass the options parsed by argparse to the correct method for the specified command. The usage string looks like so: usage: script.py [-h] {a, b, c} ... script.py: error: too few arguments I can easily call the appropriate method: def a(): ... def b(): ... def c(): ... if __name__ == "__main__": parser = argparse.ArgumentParser(

argparse accept everything

由 回眸只為那壹抹淺笑 提交于 2019-12-08 15:02:38
问题 Is there a way to have an argparse.ArgumentParser not raise an exception upon reading an unknown option, but rather put all the unknown options with values in a dictionary, and those without a value in a list? For example, say no arguments were defined in the parser for prog.py , and I pass two arguments: ./prog.py --foo bar --baz I would like the following: parsed = parser.parse_args() vals = parsed.unknown_with_vals novals = parsed.unknown_without_vals print(vals) #{'foo' : 'bar'} print

Python Argparse 'following arguments are required' error

由 元气小坏坏 提交于 2019-12-08 13:56:04
问题 I'm trying to use a github repo and having some issues with the argparse part of the project. The repo starts like this: import markdown, sys, csv, getpass, smtplib, argparse from email.mime.text import MIMEText from jinja2 import Template parser = argparse.ArgumentParser() parser.add_argument('-m', '--markdown', help='Path to Markdown Template', required=True) parser.add_argument('-c', '--csv', help='Path to CSV file', required=True) parser.add_argument('-v', '--verbose', help='Write out

Syntax error when trying to parse arguments Python shell

由 空扰寡人 提交于 2019-12-08 11:33:15
问题 I have some code that I am trying to run in a Python shell (IDLE) but there seems to be a problem with the way I am parsing arguments in the Python shell. Here is the code: # import the necessary packages from skimage.segmentation import slic from skimage.segmentation import mark_boundaries from skimage.util import img_as_float from skimage import io import matplotlib.pyplot as plt import argparse # construct the argument parser and parse the arguments ap = argparse.ArgumentParser() ap.add

debugging argpars in python

由 血红的双手。 提交于 2019-12-08 07:19:23
问题 May I know what is the best practice to debug an argpars function. Say I have a py file test_file.py with the following lines # Script start import argparse import os parser = argparse.ArgumentParser() parser.add_argument(“–output_dir”, type=str, default=”/data/xx”) args = parser.parse_args() os.makedirs(args.output_dir) # Script stop The above script can be executed from terminal by: python test_file.py –output_dir data/xx However, for debugging process, I would like to avoid using terminal.

Simple command line application in python - parse user input?

由 人盡茶涼 提交于 2019-12-08 06:33:40
问题 New to python here - I want to make a command line application where the user will type input I will parse it and execute some command - something in the lines of: try: while True: input = raw_input('> ') # parse here except KeyboardInterrupt: pass The user is supposed to type commands like init /path/to/dir . Can I use argparse to parse those ? Is my way too crude ? 回答1: arparse is a perfect solution for what you propose. The docs are well written and show dozens of example of how to invoke

Using positional arguments from argparse as function name

由 可紊 提交于 2019-12-08 06:26:21
问题 I have set up a script with argparse that gives me the following NameSpace: Namespace(action='list', input='all', target='domain') I have made a few functions which are called according to the positionals, and at the moment I have a working situation by calling them with blurbs of code like this one: if args.action == 'list': if len(sys.argv) == 2: parser.print_help() sys.exit(0) elif args.target == 'domain': domain_list() elif args.target == 'forwarding': forwarding_list() elif args.target =

Python: read command line args with argparse in addition to those coming from an external function

由 岁酱吖の 提交于 2019-12-08 06:15:38
问题 I have two modules in the same package, module1.py and module2.py . In module1.py I have a function reading command-line args with argparse : import argparse def parse_arguments_module1(): parser = argparse.ArgumentParser() optional = parser._action_groups.pop() required = parser.add_argument_group('required arguments') required.add_argument('--argA', help='argA', required=True) required.add_argument('--argB', help='argB', required=True) optional.add_argument('--argC', help='argC') optional
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