anonymous-inner-class

What does the syntax mean in Java: new Stream<Integer>(){ … }?

只谈情不闲聊 提交于 2019-12-20 02:13:14
问题 I have encountered the following Java syntax that I don't recognize. This part is fine: public abstract class Stream<T> implements Iterator<T> { public boolean hasNext() { return true; } public void remove() { throw new RuntimeException("Unsupported Operation"); } } But this I don't get: Stream<Integer> ones = new Stream<Integer>() { public Integer next() { return 1; } }; while(true){ System.out.print(ones.next() + ", "); } What it is? 回答1: This is providing an inline (anonymous) subclass of

What does the syntax mean in Java: new Stream<Integer>(){ … }?

冷暖自知 提交于 2019-12-20 02:13:08
问题 I have encountered the following Java syntax that I don't recognize. This part is fine: public abstract class Stream<T> implements Iterator<T> { public boolean hasNext() { return true; } public void remove() { throw new RuntimeException("Unsupported Operation"); } } But this I don't get: Stream<Integer> ones = new Stream<Integer>() { public Integer next() { return 1; } }; while(true){ System.out.print(ones.next() + ", "); } What it is? 回答1: This is providing an inline (anonymous) subclass of

javafx Anonymous Application class

别来无恙 提交于 2019-12-19 11:27:11
问题 I'm used to Swing and am exploring javafx. In swing I'd create a class that extends Jpanel and then be able to test that class with a couple of lines of code in that class that created a JFrame. So in javafx I thought I could just extend Scene or Group, and then be able to create an anonymous Application class in main but that fails with: Exception in thread "main" java.lang.RuntimeException: Error: class test.Test is not a subclass of javafx.application.Application at javafx.application

javafx Anonymous Application class

帅比萌擦擦* 提交于 2019-12-19 11:27:07
问题 I'm used to Swing and am exploring javafx. In swing I'd create a class that extends Jpanel and then be able to test that class with a couple of lines of code in that class that created a JFrame. So in javafx I thought I could just extend Scene or Group, and then be able to create an anonymous Application class in main but that fails with: Exception in thread "main" java.lang.RuntimeException: Error: class test.Test is not a subclass of javafx.application.Application at javafx.application

The Anonymous Class Conundrum

ⅰ亾dé卋堺 提交于 2019-12-18 09:37:53
问题 I think I understand the basics of Anonymous classes but I'd like to clarify something. when I have a syntax such as this class A { class AnonymousClass1 Implements ActionListener{} } class A { public A() { JButton btn = new JButton(); btn.addActionListener( new ActionListener(){} ); } } If the anonymous class is actually an inner class of class A, as in the first example: in theory, is the semantics right? What happens exactly? I think when the java file is compiled, a .class file is created

Class Name for Java anonymous class [duplicate]

喜夏-厌秋 提交于 2019-12-13 05:22:48
问题 This question already has answers here : Why getClass returns the name of the class + $1 (or $*) (3 answers) Closed 6 years ago . Class A{ public void test(){ B b = new B(); System.out.println( "Class Name: " + b.createClassC().getClass() ); } } Class B{ public C createClassC(){ C c = new C(){ @Override public boolean equals( Object other ){ return true; } }; } } Class C{ int val = 8; } Output: Class Name: package.name.here .B Can some one tell me why anonymous class types gives the enclosing

Break out of a method from anonymous inner class

限于喜欢 提交于 2019-12-12 17:21:31
问题 I have a method: void someMethod(String someString) final String[] testAgainst = {...}; .... for(int i = 0; i < testAgainst.length; i++) { if (someString.equals(testAgainst[i])) { AlertDialog.Builder builder = new AlertDialog.Builder(this); builder.setMessage("Strings are the same! Overwrite?") .setTitle("Blah Blah Blah") .setCancelable(false) .setPositiveButton("Overwrite", new DialogInterface.OnClickListener() { public void onClick(DialogInterface di, int which) { someAction() } })

What does $$ in javac generated name mean?

☆樱花仙子☆ 提交于 2019-12-12 08:48:11
问题 When shifting through java call graph generated by libraries like DependencyFinder and java-callgraph, I found out that java compiler generate names for anonymous functions, inner classes, etc. I've found out the meaning of a couple of them (please correct if I'm wrong): org.example.Bar$Foo refers to Foo , which is an inner class of org.example.Bar . org.example.Bar$1 refers to an anonymous class declared inside one of the methods of org.example.Bar . org.example.Bar.lambda$spam$1() refers to

Aren't Anonymous Inner Classes actually subclasses?

别说谁变了你拦得住时间么 提交于 2019-12-11 21:15:19
问题 Assume that A is a custom class, and consider the following declaration of an anonymous inner class: A Obj = new A() { @Override public String toString() { return "Hello!"; } } In this scenario, Obj is an instance of an anonymous inner class whose toString method has been overridden. Since it was declared with type A, the anonymous class must be a subclass of A. So then, why isn't this class called an Anonymous Subclass instead of an anonymous inner class? Where does the 'inner' come from?

What is happening while instantiating an abstract class? What is an anonymous inner class?

纵然是瞬间 提交于 2019-12-11 06:38:18
问题 What is happening while instantiating class Person? What is an anonymous inner class? abstract class Person { abstract void eat(); } class TestAnonymousInner { public static void main(String args[]) { Person p = new Person() { void eat() { System.out.println("nice fruits"); } // what happens here? }; p.eat(); } } 回答1: Anonymous classes are really just syntactic sugar. Since Person is abstract, you can't directly create an instance of Person . You must create an instance of a class that