android-edittext

I have a series of EditText entries and would like it so when the user hits the enter key it will go to the next Editext. I know how do this one at a time but is there a way to tell all of the edittext controls to use the same function that checks the key entry and advances the cursor. It seems kind of crazy to have one function for each of the EditTexts Much simpler than sniffing keys: try setting android:singleLine="true" and android:imeOptions="actionNext" (at least for single-line entry textviews). Read more in the Android documentation for TextView. Update: singleLine is deprecated now,

Just noticed that android:password has been deprecated , and we should be using android:inputType. Was experimenting with it by setting in my xml android:inputType="textPassword" Indeed it behaves like android:password="true" for EditText, but it seems that if I use android:inputType, android:hint will not work. The EditText will be blank. There is no such issues when using android:password with android:hint. Am I missing something here about android:inputType? mango Hint is displayed correctly with android:inputType="textPassword" and android:gravity="center" if you set also android:ellipsize

Here is my layout: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical" > <EditText android:id="@+id/etTweetReview" android:layout_width="match_parent" android:layout_height="wrap_content" android:layout_marginBottom="10dp" android:layout_marginLeft="10dp" android:layout_marginRight="10dp" android:ems="10" android:hint="Discuss up to 140 characters" android:imeOptions="actionDone" android:inputType="textCapSentences" android:lines="2"

How can I remove the border with appears when focusing an EditText View? I need it cause this view has little space in the screen, but without the border it's enough. When running on Emulator an orange border appears, on Device a blue one. el-milligano Have you tried setting the background of the EditText to a transparent colour? <EditText android:layout_width="fill_parent" android:layout_height="wrap_content" android:hint="@string/hello" android:background="#00000000" /> <EditText android:id="@+id/edittext" android:layout_width="wrap_content" android:layout_height="wrap_content" android

After updating some of our devices to android 8.0 , upon focusing on a TextInputEditText field inside of a TextInputLayout , the app crashes with this Exception : Fatal Exception: java.lang.NullPointerException: Attempt to invoke virtual method 'void android.view.View.getBoundsOnScreen(android.graphics.Rect)' on a null object reference at android.app.assist.AssistStructure$WindowNode.(AssistStructure.java) at android.app.assist.AssistStructure.(AssistStructure.java) at android.app.ActivityThread.handleRequestAssistContextExtras(ActivityThread.java:3035) at android.app.ActivityThread$H

I'm trying to deactivate the soft keyboard when using a NumberPicker to enter numerical values (for aesthetic reasons). This is my layout-xml-code: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="vertical" > <LinearLayout android:id="@+id/linearLayout2" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_gravity="center_horizontal" android:layout_marginBottom="30dp" android:layout_marginTop="30dp" >

This question already has an answer here: How do I compare strings in Java? 23 answers Here is my code: if(editText.getText().toString() == ""){ editTextBenefaction.setText("0"); } Why he didn't work? Change it to if(editText.getText().toString().equals("")){ In Java .equals() is used to compare if they have the same value and "==" is used to determine if they reference the same object. An even better way is to use if("".equals(editText.getText().toString())){ because this will protect against a NPE . Java String Docs Do not use == with Strings use equals() if(editText.getText().toString()

I am trying to change the progress of a SeekBar based on the number entered in an EditText but for some reason the EditText value goes to the max and I can't slide the thumb in the SeekBar . What I am looking to achieve: If the value entered in the EditText anywhere between 70 and 190 (including both number) change the progress of the SeekBar to that value. Partial Java code: etOne = (EditText) findViewById(R.id.etSyst); etOne.addTextChangedListener(new TextWatcher() { public void afterTextChanged(Editable s) { String filtered_str = s.toString(); if (Integer.parseInt(filtered_str) >= 70 &&