alphanumeric

I have a table that contain a field names as mgrs, the value that stored in mgrs fields is like '42SWC227821555' may contain more charachters, and may contain lower case letters. So now i want to search records between two mgrs, so how can i do that? can i convert mgrs value to integer first and then use in between clause? Instead of BETWEEN clause use STRCMP(expr1, expr2) function for string comparison operations: WHERE STRCMP(mgrs, '42SWC227821555') >= 0 AND STRCMP(mgrs, '42SWC227821570') <= 0 I will list some steps, instead of complete answer. Remove all alphabets from you value, means you

I am trying to use [:alnum:] as explained on ?regex Anyone knows why grepl("^([a-zA-Z0-9])+([;])", x="dj5sads;adsa") returns TRUE, but grepl("^([:alnum:])+([;])", x="dj5sads;adsa") returns FALSE? [:alnum:] is only the name of the class. As you want to put this named class into a character class, you have to enclose it with just another pair of [] : [[:alnum:]] In your example it'd be grepl("^([[:alnum:]])+([;])", x="dj5sads;adsa") //Output: TRUE demo @ ideone what you want is grepl("^([[:alnum:]])+([;])", x="dj5sads;adsa") remember we put the SearchPattern 来源： https://stackoverflow.com

I'm trying to code a user defined function under SQL Server 2005 that will increase integer part of alphanumeric value by one. For example, uf_AlphanumericIncrease ('A000299') should return 'A000300'. Here's what I've done so far; ALTER FUNCTION uf_AlphaNumericIncrement ( @ID varchar(10) ) RETURNS VARCHAR(10) AS BEGIN DECLARE @RES varchar(10); IF SUBSTRING(@ID,LEN(@ID),1)='9' SET @RES=SUBSTRING(@ID,1,LEN(@ID)-2)+CAST (CAST(SUBSTRING(@ID,LEN(@ID)-1,1) AS smallint)+1 AS VARCHAR(10))+'0'; ELSE SET @RES=SUBSTRING(@ID,1,LEN(@ID)-1)+CAST (CAST(SUBSTRING(@ID,LEN(@ID),1) AS smallint)+1 AS VARCHAR(10))

How I can sort array data alphanumerically in ruby? Suppose my array is a = [test_0_1, test_0_2, test_0_3, test_0_4, test_0_5, test_0_6, test_0_7, test_0_8, test_0_9, test_1_0, test_1_1, test_1_2, test_1_3, test_1_4, test_1_5, test_1_6, test_1_7, test_1_8, test_1_9, test_1_10, test_1_11, test_1_12, test_1_13, test_1_14, ...........test_1_121...............] I want my output to be: . . . test_1_121 . . . test_1_14 test_1_13 test_1_12 test_1_11 test_1_10 test_1_9 test_1_8 test_1_7 test_1_6 test_1_5 test_1_4 test_1_3 test_1_2 test_1_1 test_0_10 test_0_9 test_0_8 test_0_7 test_0_6 test_0_5 test_0

Sorting Alphanumeric field in SQL CE (Compact Edition) version 3.5 TreeNumber is a nvarchar field with a mix of numbers and strings for the values. I want to sort these records so that the records that contain alpha characters are at the top and the rest are sorted in numeric order. I want something similar to the following query which works in SQL Server: SELECT * FROM Tree ORDER BY (CASE WHEN TreeNumber LIKE '%[a-z]%' THEN 0 ELSE TreeNumber END), TreeNumber The above query doesn't seem to work because the [] range is not supported in CE. Another solution which works with SQL Server but doesn

I'm trying to remove everything that is not alphanumeric, or is a space with _: $filename = preg_replace("([^a-zA-Z0-9]|^\s)", "_", $filename); What am I doing wrong here, it doesn't seem to work. I've tried several regex combinations...(and I'm generally not very bright). Try this: $filename = preg_replace("/[^a-zA-Z0-9 ]/", "_", $filename); $filename = preg_replace('~[\W\s]~', '_', $filename); If I understand your question correctly, you want to replace any space (\s) or non-alphanumerical (\W) character with a '_'. This should do fine. Note the \W is uppercase, as opposed to lowercase \w

I am using SQL Server, the column is a VARCHAR(50) and I want to sort it like this: 1A 1B 2 2 3 4A 4B 4C 5A 5B 5C 5N 14 Draft 21 22A 22B 23A 23B 23C 23D 23E 25 26 FR01584 MISC What I have so far is: Select * From viewASD ORDER BY Case When IsNumeric(LEFT(asdNumNew,1)) = 1 Then CASE When IsNumeric(asdNumNew) = 1 Then Right(Replicate('0',20) + asdNumNew + '0', 20) Else Right(Replicate('0',20) + asdNumNew, 20) END When IsNumeric(LEFT(asdNumNew,1)) = 0 Then Left(asdNumNew + Replicate('',21), 20) End But this SQL statement puts '14 Draft' right after '26'. Could someone help? Thanks Your WHERE