alphabet

In Python, could I simply ++ a char? What is an efficient way of doing this? I want to iterate through URLs that have the www.website.com/term/#, www.website.com/term/a, www.website.com/term/b, www.website.com/term/c, www.website.com/term/d ... www.website.com/term/z format. You can use string.ascii_lowercase which is simply a convenience string of lowercase letters, >>> from string import ascii_lowercase >>> for c in ascii_lowercase: ... # append to your url In addition to string.ascii_lowercase you should also take a look at the ord and chr built-ins. ord('a') will give you the ascii value

I want an NSArray/NSMutableArray containing all the letters of the alphabet. There must be a quick and easy way, better than typing them all out. For example in PHP: foreach(range('A','Z') as $i) $alphabet[]=$i; Alex Brown There's no quicker way than typing them all out, unless you cut and paste my handy reference from below! "abcdefghijklmnopqrstuvwxyz" For the sake of it, here's a longer way. for (char a = 'a'; a <= 'z'; a++) { [myArray addObject:[NSString stringWithFormat:@"%c", a]]; } The array generated for table index titles may also be used. It does not use a for loop and has multi

I have a capital letter defined in a variable string, and I want to output the next and previous letters in the alphabet. For example, if the variable was equal to 'C' , I would want to output 'B' and 'D' . One way: String value = "C"; int charValue = value.charAt(0); String next = String.valueOf( (char) (charValue + 1)); System.out.println(next); TacB0sS Well if you mean the 'ABC' then they split into two sequences a-z and A-Z, the simplest way I think would be to use a char variable and to increment the index by one. char letter='c'; letter++; // (letter=='d') same goes for decrement: char

I want to generate a dict with the letters of the alphabet as the keys, something like letter_count = {'a': 0, 'b': 0, 'c': 0} what would be a fast way of generating that dict, rather than me having to type it in? Thanks for your help. EDIT Thanks everyone for your solutions :) nosklo's solution is probably the shortest Also, thanks for reminding me about the Python string module. I find this solution more elegant: import string d = dict.fromkeys(string.ascii_lowercase, 0) import string letter_count = dict(zip(string.ascii_lowercase, [0]*26)) or maybe: import string import itertools letter

Say you have the string "Hi" . How do you get a value of 8 , 9 ( "H" is the 8th letter of the alphabet, and "i" is the 9th letter). Then say, add 1 to those integers and make it 9 , 10 which can then be made back into the string "Ij" ? Is it possible? use ord to get the ASCII index, and chr to bring it back. 'Hi'.chars.map{|x| (x.ord+1).chr}.join Note Cary Swoveland had already given a same answer in a comment to the question. It is impossible to do that through the numbers 8 and 9 because these numbers do not contain information about the case of the letters. But if you do not insist on

I'm new to Java and I'm trying to arrange an arrayList of terms in alphabetical order. (A term is defined as a char and an int) (e.g. {Term('Z',4),Term('C',3),Term('Q',2) ...} ) My code is as follows: public Term nextElement() { Term max = terms.get(0); char maxtest = max.getElement(); for (int i = 1; i < terms.size(); i++){ Term tester = terms.get(i); char maxtest2 = tester.getElement(); if (maxtest2 > maxtest) { tester = max; } } return max; } Why isn't this working? and how do I accomplish this? My arrayList is called term filled with type Term Your problem with this line of Code. Your

I would like to be able to create a sequence of letters in R (to assist in importing data from a SPSS file) It's quite easy to create a sequence of numbers, for example: seq(1,1000) [1] 1 2 3 4 5 6 ... 1000 paste("something_",1:12,sep="") [1] something1 something2 ... something12 But is there any functionality for appending, pasting, or creating sequences of letters like this? paste("This_",a:z,sep="") [1]This_a This_b This_c ... This_4z Thanks in advance! Christopher DuBois This is what you're looking for: > paste("This_", letters, sep="") > [1] "This_a" "This_b" "This_c" "This_d" "This_e"

I am trying to cycle through the entire alphabet using Swift. The only problem is that I would like to assign values to each letter. For Example: a = 1, b = 2, c = 3 and so on until I get to z which would = 26. How do I go through each letter in the text field that the user typed while using the values previously assigned to the letters in the alphabet? After this is done, how would I add up all the letters values to get a sum for the entire word. I am looking for the simplest possible way to accomplish this but works the way I would like it to. Any suggestions? Thanks in Advance. edit/update: