Is there an easy way to programmatically get the alphabet?

Question

I want an NSArray/NSMutableArray containing all the letters of the alphabet. There must be a quick and easy way, better than typing them all out. For example in PHP:

foreach(range('A','Z') as $i) $alphabet[]=$i;

Answer 1

There's no quicker way than typing them all out, unless you cut and paste my handy reference from below!

"abcdefghijklmnopqrstuvwxyz"

---

For the sake of it, here's a longer way.

for (char a = 'a'; a <= 'z'; a++)
{
  [myArray addObject:[NSString stringWithFormat:@"%c", a]];
}

Answer 2

The array generated for table index titles may also be used. It does not use a for loop and has multi-language support.

NSMutableArray *alphabets = [[NSMutableArray alloc] initWithArray:[[UILocalizedIndexedCollation currentCollation] sectionIndexTitles]];

//Remove the last object (extra), '#' from the array.
[alphabets removeLastObject];

Answer 3

Sometimes typing the letters out is the easiest. Here they are as an array:

NSArray *letters = [@"A B C D E F G H I J K L M N O P Q R S T U V W X Y Z" componentsSeparatedByString:@" "];

Answer 4

try with following code;

int a = 65;
for (; a < 91; a++) {
    [array addObject:[NSString stringWithFormat:@"%c", (char)a]];
}
NSLog(@"%@", array);

Answer 5

You could use a for-loop to generate them, but I think typing them out is easier. It is most certainly easier than posting a question here. ;)