alphabet

问题 I'm trying a way that when given a string of names which are first and last names, where names are split by ; and first name split to last name by : -> "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill" I want to return a string which is sorted out all the names as uppercase and sorted alphabetically according to the last name and the ones that share the same last name then sort again (secondary sort) between the first names of the

问题 I'm trying a way that when given a string of names which are first and last names, where names are split by ; and first name split to last name by : -> "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill" I want to return a string which is sorted out all the names as uppercase and sorted alphabetically according to the last name and the ones that share the same last name then sort again (secondary sort) between the first names of the

问题 I've almost the same problem like this one: How to make a continuous alphabetic list python (from a-z then from aa, ab, ac etc) But, I am doing a list in gui like excel, where on the vertical header should be letters ...aa,ab,ac....dg,dh,di... To do it, I have to declare every place on my list to certain letter. It is probably impossible with yield. I mean, let me say, I have 100 of cells and I want to name them all differently. Cell 1 should be "A", Cell 2 should be "B".... Cell 27 should be

问题 I have an int array (b[]) with a random length and random integers. I want to leave integers lower than 9 to how they are, i want to change the numbers 9-35 to letters A-Z . and i want do put () around all numbers higher than 35 . So b[] = {1,10,36} would generate a String 1A(36) . My try: int b[] = {99, 2, 3, 4, 5, 10, 35, 24}; //sample input char[] hilfsarray = new char[b.length]; char[] alphabet = "ABCDEFGHIJKLMNOPQRSTUVW".toCharArray(); for (int k = 0; k < hilfsarray.length; k++) /

问题 I'm not really sure how to express it but I'm searching for unicode letters which are more than one visual latin letter. I found this in Word so far: DZ Dz dz NJ Lj LJ Nj nj Any others? 回答1: Sorry about the formatting because it's hard to map long characters to monospace fonts' letter widths. It would be better if it's in a picture but then there's no possibility to copy and zoom infinitely Digraphs +-------------+----------+-----------------------+-------------------------+ | Two Glyphs | Digraph |

问题 I wonder if this is possible in oracle to replace row number (we can use ROW_NUMBER() for example to get a digit) into alfabetical numbering Let's say to get something like NO | Name | Surname ================ A | John | Doe B | Will | Doe C | Jim | Wonder instead of NO | Name | Surname | ================= 1 | John | Doe 2 | Will | Doe 3 | Jim | Wonder I have an idea to create a variable like "ABCDEFG" and convert row number into correct SUBSTR , but this sounds a little unstable Temporary

问题 So I need to get a function that generates a list of letters that increase from a, and end in zzz. Should look like this: a b c ... aa ab ac ... zzx zzy zzz The code I currently have is this: for combo in product(ascii_lowercase, repeat=3): print(''.join(combo)) However, this does only increase with 3 letters, and the output is more like a ab abc abcd ... So, to recap: Function that letters increase, and when it goes past z, it returns to aa. Thanks! UPDATE: I am having the same output as

问题 I'm creating an "animated letter incrementer" that takes any given word and increments each letter of that word starting from A. Example: Word = Dog D - Increments from A to D [A, B, C, D] O - Increments from A to O [A, B, C, D, E, F, G, H, I, J, K, L, M, N, O] G - Increments from A to G [A, B, C, D, E, F, G] The effect I'd like to achieve is similar to this jQuery animated number counter, except I'll be incrementing letters instead of counting numbers. Also, each letter of the word should

问题 I'm creating an "animated letter incrementer" that takes any given word and increments each letter of that word starting from A. Example: Word = Dog D - Increments from A to D [A, B, C, D] O - Increments from A to O [A, B, C, D, E, F, G, H, I, J, K, L, M, N, O] G - Increments from A to G [A, B, C, D, E, F, G] The effect I'd like to achieve is similar to this jQuery animated number counter, except I'll be incrementing letters instead of counting numbers. Also, each letter of the word should

问题 According to my research and googling, Javascript seems to lack support for locale aware sorting and string comparisons. There is localeCompare(), but it has been reported of browser specific differencies and impossibility to explicitly set which locale is used (the OS locale is not always the one wanted). There is some intentions to add collation support inside ECMAScript, but before it, we are on our own. And depending how consistent the results are across browsers, may be we are on our own