alias

Why would we use the class_alias function? For example: Class Test { public function __construct(){ echo "Class initialized"; } } class_alias("Test", "AnotherName"); $instance = new AnotherName(); # equivalent to $instance = new Test(); According to the manual , "The aliased class is exactly the same as the original class." What is this useful for? Surprisingly, nobody has mentioned the obvious reason why one would do this: the use keyword can only be used in the outmost scope, and is processed at compile-time, so you can't use Some\Class based on some condition, nor can it be block-scoped:

1.查找/var目录下不属于root、lp、gdm的所有文件 find /var ! ( -user root -o -user lp -o -user gdm ) 2、统计/etc/init.d/functions文件中每个单词的出现次数,并排序(用grep和sed两种方法分别实现) sed方法：cat /etc/init.d/functions | sed -r 's@[^[:alpha:]]+@\n@g'|sort |uniq -c|sort -n grep方法：cat /etc/init.d/functions |grep -o '[[:alpha:]]'|sort |uniq -c|sort -n 3、利用sed取出ifconfig命令中本机的IPv4地址 ifconfig | sed -n "2p" |sed -r "s/. inet (. ) netmask.*/\1/g" 4、总结yum的配置和使用，包括yum仓库的创建 yum groupinstall 组安装 yum remove 卸载 yum groupremove 组卸载 yum list 显示所有包 yum clean all 清除缓存 yum makecache 建立缓存 yum仓库目录/etc/yum.repos.d/ [base] name=base baseurl=http:// ftp://

We have a very old software has been created around 10 years ago and we don't have source code. The software uses two databases, DB01 and DB02 on the same SQL Server 2012 instance. There is SQL statements such as db01..table1 join db02..table2 , but the main issue is our processes don't allow us use db02 as a name of database. The question is: how we can create an alias of for database? I was trying to use CREATE SYNONYM CREATE SYNONYM [db02] FOR [db02_new_name]; but it doesn't work for database names. Please suggest how it can be solved without patching a binary files to correct SQL

I'm creating a view that is using data that comes from the same table twice. As a result, same column names appear twice. Thus, i need to give aliases to these columns. If i were to do it, i'd write it as: SELECT u.* as 'one_*', u2.* as 'two_*' FROM users u LEFT JOIN relationships r ON u.id=r.id_one LEFT JOIN users u2 ON r.id_two=u2.id But that doesn't work. Thanks for your help! EDIT: Here's the data i'm actually getting: | id | name | id | name | 1 john 2 alex Here's the data i'd like to get (while still using a SELECT u.*, u2.* ): | id | name | brother_id | brother_name | 1 john 2 alex You

Suppose that I've got the following libraries: add_library(myLib_static STATIC ${SRC_FILES}) add_library(myLib SHARED ${SRC_FILES}) # installing header files install(FILES ${H_FILES} DESTINATION ${INSTDIRHEADER}) # installing binaries install(TARGETS myLib_static DESTINATION ${INSTDIRBIN}) install(TARGETS myLib DESTINATION ${INSTDIRBIN}) If I execute the following command, both shared and static libraries will be installed: make install How can I have separate install commands for each of them? Something like this: make install-static make install-shared Update : Header files should also be

一、克隆虚拟机 把正在使用的虚拟机关机 init0 找到工具-管理-克隆 然后一直下一步 克隆完成过后开机修改一下IP地址 vi /etc/sysconfig/network-scripts/ifcfg-ens33 修改完成重启网络配置 systemctl restart network 然后修改hostname hostnamectl set-hostname yylinux02 二、远程登录 1、putty选择需要复制的地方右键可以直接复制 2、xshell默认不能直接复制，需要设置 点击上面菜单栏工具选项 最下面一个选项 找到键盘和鼠标 向右按钮选择paste这个选项然后点击确定就可以复制粘贴了 3、xsell可以直接在连接状态下打开另外一个 可以选择排列方式 左右排列还是上下排列 3 putty秘钥认证 秘钥和密码都是一种认证方式 秘钥算是1对字符串 相当于钥匙和锁 1个加密1个解密 可以在客户端也就是自己电脑放私钥 可以在服务端也就是服务器上放公钥 点开puttygen 然后点击Generate 然后生成随机的字符串 然后可以设置密码也可以为空，但是为了安全还是选择设置密码 然后选择save公钥还是私钥 公钥可以直接复制 save public key 是公钥 save private key是私钥 然后在服务器上面创建目录 mkdir /root/.ssh 绝对路径