algorithm

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 6 years ago . Improve this question I need to find a way of drawing the inside of a closed 2D curve. This curve is actually created using a bicubic Bezier curve, but that's not important I believe. At the moment there should be no "holes" within the drawn shape. So it will just be totally filled in. It seems

问题 I had tried the following code to get most occurring element in an array. It is working well but the only problem is when there are two or more elements having the same number of occurrence and equal to most occurring element, it just shows the first element scanned. Please help me through this. #include <iostream> using namespace std; int main() { int i,j,a[5]; int popular = a[0]; int temp=0, tempCount, count=1; cout << "Enter the elements: " << endl; for(i=0;i<5;i++) cin >> a[i]; for (i=0;i

问题 I had tried the following code to get most occurring element in an array. It is working well but the only problem is when there are two or more elements having the same number of occurrence and equal to most occurring element, it just shows the first element scanned. Please help me through this. #include <iostream> using namespace std; int main() { int i,j,a[5]; int popular = a[0]; int temp=0, tempCount, count=1; cout << "Enter the elements: " << endl; for(i=0;i<5;i++) cin >> a[i]; for (i=0;i

问题 I had tried the following code to get most occurring element in an array. It is working well but the only problem is when there are two or more elements having the same number of occurrence and equal to most occurring element, it just shows the first element scanned. Please help me through this. #include <iostream> using namespace std; int main() { int i,j,a[5]; int popular = a[0]; int temp=0, tempCount, count=1; cout << "Enter the elements: " << endl; for(i=0;i<5;i++) cin >> a[i]; for (i=0;i

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 6 years ago . Improve this question I need to find a way of drawing the inside of a closed 2D curve. This curve is actually created using a bicubic Bezier curve, but that's not important I believe. At the moment there should be no "holes" within the drawn shape. So it will just be totally filled in. It seems

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 6 years ago . Improve this question I need to find a way of drawing the inside of a closed 2D curve. This curve is actually created using a bicubic Bezier curve, but that's not important I believe. At the moment there should be no "holes" within the drawn shape. So it will just be totally filled in. It seems

问题 I found that many people use x += x & -x , x -= x & -x to solve the interval tree problem. Can you explain what that equation means? void update(int m, int x) { m++; while (m < N) { t[m] = t[m] + x; m += m & -m; } } int query(int m) { int result= 0; m++; while (m > 0) { result = result + t[m]; m -= m & -m; } return result; } 回答1: Note: This answer (like the method itself) assumes signed integers are represented in two's complement form. The expression x & -x is a quick - but admittedly arcane

问题 Given a large array of positive integer "weights", e.g. [ 2145, 8371, 125, 10565, ... ] , and a positive integer "weight limit", e.g. 15000, I want to partition the weights into one or more smaller arrays, with the following criteria: I want to minimize the number of partitions. No single partition can add up to more than the weight limit. (Note that no single weight will exceed this limit.) I suspect this problem has a high complexity class. As answers, I'm interested in: Optimal solutions

问题 Given a large array of positive integer "weights", e.g. [ 2145, 8371, 125, 10565, ... ] , and a positive integer "weight limit", e.g. 15000, I want to partition the weights into one or more smaller arrays, with the following criteria: I want to minimize the number of partitions. No single partition can add up to more than the weight limit. (Note that no single weight will exceed this limit.) I suspect this problem has a high complexity class. As answers, I'm interested in: Optimal solutions

问题 I have been trying for some time solve a scheduling problem for a pool that I used to work at. This problem is as follows... There are X many lifeguards that work at the pool, and each has a specific number of hours they would like to work. We hope to keep the average number of hours away from each lifeguards desired number of hours as low as possible, and as fair as possible for all. Each lifeguard is also a college student, and thus will have a different schedule of availability. Each week