2d

In Android I use a SurfaceView to display a simple 2D game. The bitmaps (.png) with alpha (representing the game objects) are drawn on the canvas. Now I would like to do a simple but accurate collision detection. Checking whether these bitmaps are overlapping is quite easy. But how do I check for collisions when these bitmaps have transparent areas? My challenge is detecting whether two balls collide or not. They fill up the whole bitmap in width and height both but in all four edges, there are transparent areas of course as it's a circle in a square. What is the easiest way to detect

This question already has an answer here: Add scrolling to a platformer in pygame 4 answers import pygame, sys from pygame.locals import * pygame.init() size = width, height = 480,320 screen = pygame.display.set_mode(size) r = 0 bif = pygame.image.load("map5.png") pygame.display.set_caption("Pygame 2D RPG !") x,y=0,0 movex, movey=0,0 character="boy.png" player=pygame.image.load(character).convert_alpha() while True: for event in pygame.event.get(): if event.type == pygame.QUIT: pygame.quit() sys.exit() if event.type==KEYDOWN: if event.key==K_a: movex=-1 elif event.key==K_d: movex=+1 elif event

I have the following 2d array int [][] array = {{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9}, {10, 11, 12, 13, 14, 15, 16, 17, 18, 19}, {20, 21, 22, 23, 24, 25, 26, 27, 28, 29}, {30, 31, 32, 33, 34, 35, 36, 37, 38, 39}, {40, 41, 42, 43, 44, 45, 46, 47, 48, 49}, {50, 51, 52, 53, 54, 55, 56, 57, 58, 59}, {60, 61, 62, 63, 64, 65, 66, 67, 68, 69}, {70, 71, 72, 73, 74, 75, 76, 77, 78, 79}, {80, 81, 82, 83, 84, 85, 86, 87, 88, 89}, {90, 91, 92, 93, 94, 95, 96, 97, 98, 99}}; I have this code to find the sum of all the values in the array. How can I modify it to add only the diagonal values starting at 0 (0+11+22

How can I obtain the vertices of a GeneralPath object? It seems like this should be possible, since the path is constructed from points (lineTo, curveTo, etc). I'm trying to create a double[][] of point data (an array of x/y coordinates). You can get the points back from the PathIterator . I'm not sure what your constraints are, but if your shape always has just one closed subpath and has only straight edges (no curves) then the following will work: static double[][] getPoints(Path2D path) { List<double[]> pointList = new ArrayList<double[]>(); double[] coords = new double[6]; int numSubPaths

Not sure how to approach this problem. Basically, I want a Pixel -> Tile representation of a 400x400 window. Each coordinate on the screen, e.g 120x300 should be part of a tile. My smallest sprite is 4 pixels, so we can say that 1 tile = 4 pixels. The player and enemy sprites are all 20 x 20, so each player/bad guy will occupy 5 tiles. Then I want to use this Map class to: Retrieve the x/y coordinates of a player/monster sprite by suppling the index/id of the tile. Knowing where the boundaries are, so it doesn't move the sprite beyond 400x400 , thus hiding it. Collision detection, knowing

I woud like to create a cross-platform drawing program. The one requirement for writing my app is that I have pixel level precision over the canvas. For instance, I want to write my own line drawing algorithm rather than rely on someone elses. I do not want any form of anti-aliasing (again, pixel level control is required.) I would like the users interactions on the screen to be quick and responsive (pending my ability to write fast algorithms.) Ideally, I would like to write this in Python, or perhaps Java as a second choice. The ability to easily make the final app cross-platform is a must.

I was wondering how I would go about mapping 2D screen coordinates to a 3D world (specifically the xz plane) knowing: -position of the camera -equation of the screen plane -equation of the xz plane All I want to do is have the land on the xz plane light up when I hover the mouse over it. Any help is greatly appreciated! Thanks! If your world is rotated and shifted such that the camera is at x=y=z=0 (world coordinates), the world z coordinate increases away from the viewer (into the screen), and the projection plane is parallel to the screen and is at z=d (world coordinate; d > 0 ), then you