Simple way to create matrix of random numbers

Question

I am trying to create a matrix of random numbers, but my solution is too long and looks ugly

random_matrix = [[random.random() for e in range(2)] for e in ra         


        

Answer 1

For creating an array of random numbers NumPy provides array creation using:

1. Real numbers

2. Integers

For creating array using random Real numbers: there are 2 options

1. random.rand (for uniform distribution of the generated random numbers )
2. random.randn (for normal distribution of the generated random numbers )

random.rand

import numpy as np 
arr = np.random.rand(row_size, column_size) 

random.randn

import numpy as np 
arr = np.random.randn(row_size, column_size) 

For creating array using random Integers:

import numpy as np
numpy.random.randint(low, high=None, size=None, dtype='l')

where

• low = Lowest (signed) integer to be drawn from the distribution
• high(optional)= If provided, one above the largest (signed) integer to be drawn from the distribution
• size(optional) = Output shape i.e. if the given shape is, e.g., (m, n, k), then m * n * k samples are drawn
• dtype(optional) = Desired dtype of the result.

eg:

The given example will produce an array of random integers between 0 and 4, its size will be 5*5 and have 25 integers

arr2 = np.random.randint(0,5,size = (5,5))

in order to create 5 by 5 matrix, it should be modified to

arr2 = np.random.randint(0,5,size = (5,5)), change the multiplication symbol* to a comma ,#

[[2 1 1 0 1][3 2 1 4 3][2 3 0 3 3][1 3 1 0 0][4 1 2 0 1]]

eg2:

The given example will produce an array of random integers between 0 and 1, its size will be 1*10 and will have 10 integers

arr3= np.random.randint(2, size = 10)

[0 0 0 0 1 1 0 0 1 1]