Simple way to create matrix of random numbers

Question

I am trying to create a matrix of random numbers, but my solution is too long and looks ugly

random_matrix = [[random.random() for e in range(2)] for e in ra         


        

Answer 1

use np.random.randint() as np.random.random_integers() is deprecated

random_matrix = np.random.randint(min_val,max_val,(<num_rows>,<num_cols>))

Answer 2

random_matrix = [[random.random for j in range(collumns)] for i in range(rows)
for i in range(rows):
    print random_matrix[i]

Answer 3

When you say "a matrix of random numbers", you can use numpy as Pavel https://stackoverflow.com/a/15451997/6169225 mentioned above, in this case I'm assuming to you it is irrelevant what distribution these (pseudo) random numbers adhere to.

However, if you require a particular distribution (I imagine you are interested in the uniform distribution), numpy.random has very useful methods for you. For example, let's say you want a 3x2 matrix with a pseudo random uniform distribution bounded by [low,high]. You can do this like so:

numpy.random.uniform(low,high,(3,2))

Note, you can replace uniform by any number of distributions supported by this library.

Further reading: https://docs.scipy.org/doc/numpy/reference/routines.random.html

Answer 4

A simple way of creating an array of random integers is:

matrix = np.random.randint(maxVal, size=(rows, columns))

The following outputs a 2 by 3 matrix of random integers from 0 to 10:

a = np.random.randint(10, size=(2,3))

Answer 5

Take a look at numpy.random.rand:

Docstring: rand(d0, d1, ..., dn)

Random values in a given shape.

Create an array of the given shape and propagate it with random samples from a uniform distribution over [0, 1).

---

>>> import numpy as np
>>> np.random.rand(2,3)
array([[ 0.22568268,  0.0053246 ,  0.41282024],
       [ 0.68824936,  0.68086462,  0.6854153 ]])

Answer 6

numpy.random.rand(row, column) generates random numbers between 0 and 1, according to the specified (m,n) parameters given. So use it to create a (m,n) matrix and multiply the matrix for the range limit and sum it with the high limit.

Analyzing: If zero is generated just the low limit will be held, but if one is generated just the high limit will be held. In order words, generating the limits using rand numpy you can generate the extreme desired numbers.

import numpy as np

high = 10
low = 5
m,n = 2,2

a = (high - low)*np.random.rand(m,n) + low

Output:

a = array([[5.91580065, 8.1117106 ],
          [6.30986984, 5.720437  ]])