Find max and second max salary for a employee table MySQL

Question

Suppose that you are given the following simple database table called Employee that has 2 columns named Employee ID and Salary:

  Employee
  Employee ID    S         


        

Answer 1

Max Salary:

select max(salary) from tbl_employee <br><br>

Second Max Salary:

select max(salary) from tbl_employee where salary < ( select max(salary) from tbl_employee);

Answer 2

The Best & Easiest solution:-

 SELECT
    max(salary)
FROM
    salary
WHERE
    salary < (
        SELECT
            max(salary)
        FROM
            salary
    );

Answer 3

If we want to find Employee that gets 3nd highest salary then execute this query

SELECT a.employeeid, 
       a.salary 
FROM  (SELECT employeeid, 
              salary, 
              Dense_rank() 
                OVER( 
                  ORDER BY salary) AS n 
       FROM   employee) AS a 
WHERE  n = 3 

What do you want

Answer 4

This solution will give all employee name and salary who have second highest salary

SELECT name, salary
FROM employee
WHERE salary = (
    SELECT 
        salary
    FROM employee AS emp
    ORDER BY salary DESC
    LIMIT 1,1
);

Answer 5

without nested query

select max(e.salary) as max_salary, max(e1.salary) as 2nd_max_salary 
from employee as e
left join employee as e1 on e.salary != e1.salary
group by e.salary desc limit 1;

Answer 6

try this

select max(salary) as first, 
       (select salary from employee order by salary desc limit 1, 1) as second 
from employee limit 1