Find max and second max salary for a employee table MySQL

Question

Suppose that you are given the following simple database table called Employee that has 2 columns named Employee ID and Salary:

  Employee
  Employee ID    S         


        

Answer 1

$q="select * from info order by salary desc limit 1,0"; // display highest 2 salary

or

$q="select * from info order by salary desc limit 1,0"; // display 2nd highest salary

Answer 2

select * from
  Employees where Sal >=
  (SELECT
    max(Sal)
FROM
    Employees
WHERE
    Sal < (
        SELECT
            max(Sal)
        FROM
            Employees; 
    ));

Answer 3

`select max(salary) as first, (select salary from employee order by salary desc limit 1, 1) as second from employee limit 1`

For max salary simply we can use max function, but second max salary we should use sub query. in sub query we can use where condition to check second max salary or simply we can use limit.

Answer 4

Try

SELECT 

   SUBSTRING( GROUP_CONCAT( Salary ), 1 , LOCATE(",", GROUP_CONCAT( Salary ) ) -1 ) AS max_salary,

   SUBSTRING( GROUP_CONCAT( Salary ), LOCATE(",", GROUP_CONCAT( Salary ) ) +1 ) AS second_max_salary

FROM 
   (
     SELECT Salary FROM `Employee` ORDER BY Salary DESC LIMIT 0,2
   ) a

Demo here

Answer 5

You can write SQL query in any of your favorite database e.g. MySQL, Microsoft SQL Server or Oracle. You can also use database specific feature e.g. TOP, LIMIT or ROW_NUMBER to write SQL query, but you must also provide a generic solution which should work on all database. In fact, there are several ways to find second highest salary and you must know a couple of them e.g. in MySQL without using the LIMIT keyword, in SQL Server without using TOP and in Oracle without using RANK and ROWNUM.

Generic SQL query:

SELECT
    MAX(salary)
FROM
    Employee
WHERE
    Salary NOT IN (
        SELECT
            Max(Salary)
        FROM
            Employee
    );

Another solution which uses sub query instead of NOT IN clause. It uses < operator.

SELECT
    MAX(Salary)
FROM
    Employee
WHERE
    Salary < (
        SELECT
            Max(Salary)
        FROM
            Employee
    );

Answer 6

This should work same :

SELECT MAX(salary) max_salary,
  (SELECT MAX(salary)
   FROM Employee
   WHERE salary NOT IN
       (SELECT MAX(salary)
        FROM Employee)) 2nd_max_salary
FROM Employee