Find max and second max salary for a employee table MySQL

Question

Suppose that you are given the following simple database table called Employee that has 2 columns named Employee ID and Salary:

  Employee
  Employee ID    S         


        

Answer 1

with Common table expression

With cte as (
 SELECT 
   ROW_NUMBER() Over (Order By Salary Desc) RowNumber, 
   Max(Salary) Salary 
 FROM
     Employee
 Group By Salary
)

Select * from cte where RowNumber = 2

Answer 2

You can just run 2 queries as inner queries to return 2 columns:

select
  (SELECT MAX(Salary) FROM Employee) maxsalary,
  (SELECT MAX(Salary) FROM Employee
  WHERE Salary NOT IN (SELECT MAX(Salary) FROM Employee )) as [2nd_max_salary]

SQL Fiddle Demo

Answer 3

Not really a nice query but :

SELECT * from (
    SELECT max(Salary) from Employee
    ) as a
LEFT OUTER JOIN 
    (SELECT MAX(Salary) FROM Employee
        WHERE Salary NOT IN (SELECT MAX(Salary) FROM Employee )) as b
ON 1=1

Answer 4

select * from emp where sal =(select max(sal) from emp where eno in(select eno from emp where sal <(select max(sal)from emp )));

try the above code ....

if you want the third max record then add another nested query "select max(sal)from emp" inside the bracket of the last query and give less than operator in front of it.

Answer 5

Here change n value according your requirement:

SELECT top 1 amount 
FROM ( 
    SELECT DISTINCT top n amount 
    FROM payment 
    ORDER BY amount DESC ) AS temp 
ORDER BY amount

Answer 6

Try like this

SELECT (select max(Salary) from Employee) as MAXinmum),(max(salary) FROM Employee WHERE salary NOT IN (SELECT max(salary)) FROM Employee);

(Or)

Try this, n would be the nth item you would want to return

 SELECT DISTINCT(Salary) FROM table ORDER BY Salary DESC LIMIT n,1

In your case

 SELECT DISTINCT(column_name) FROM table_name ORDER BY column_name DESC limit 2,1;