exponential-distribution

How to prove arrival rate follows Exponential Distributions?

≯℡__Kan透↙ 提交于 2021-02-11 15:21:42
问题 I'm studying Anylogic. I'm curious about something. Some people explain that arrival rate follows Exponential Distribution. I wanna know 'How can prove that?' Any kind guidance from you would be very helpful and much appreciated. Thank you so much. 回答1: The arrival rate doesn't follow an exponential distribution, it follows a poisson distribution, so there's nothing to prove on that regard. What follows an exponential distribution is the inter-arrival time between agents. To prove that this

Determine waiting times between plane arrivals python

谁说我不能喝 提交于 2021-02-11 14:46:21
问题 I'm writing a program, that takes 200 planes distributed with the poisson distribution over 12 hours and these planes need to land at an airfield that only has 1 runway. I use the reverse CDF method from the exponential distribution to determine the inter-arrival times. However, I can't seem to calculate the waiting time in the air. E.g. a plane arrives at 100 seconds, takes 75 seconds to land and is done at 175 seconds. Plane 2 arrives at 150 seconds and must wait 175-150 = 25 seconds. How

Random integers from an exponential distribution between min and max

[亡魂溺海] 提交于 2020-05-15 11:03:40
问题 I would like to generate random integers on an interval min to max. For a uniform distribution in numpy: numpy.random.randint(min,max,n) does exactly what I want. However, I would now like to give the distribution of random numbers an exponential bias. There are a number of suggestions for this e.g. Pseudorandom Number Generator - Exponential Distribution as well as the numpy function numpy.random.RandomState.exponential , but these do not address how to constrain the distribution to integers

Defining exponential distribution in R to estimate probabilities

泪湿孤枕 提交于 2020-01-24 12:44:27
问题 I have a bunch of random variables (X1,....,Xn) which are i.i.d. Exp(1/2) and represent the duration of time of a certain event. So this distribution has obviously an expected value of 2, but I am having problems defining it in R. I did some research and found something about a so-called Monte-Carlo Stimulation, but I don't seem to find what I am looking for in it. An example of what i want to estimate is: let's say we have 10 random variables (X1,..,X10) distributed as above, and we want to

Generate a exponential distribution with lambda´3

送分小仙女□ 提交于 2019-12-25 17:14:55
问题 I have an assignment and now got confused about exponential distribution. The instruction say "service time is exponential distributed with intensity lambda=3 ." First I thought generating this is just exp(3) , but using Matlab I am wondering if this is right interpretation of the text. Maybe I should use exprnd(3) instead? 回答1: If the service time distribution, S, is exponentially distributed with rate lambda = 3, then the average service time is 1/3. You'll see the Exponential distribution

Pseudorandom Number Generator - Exponential Distribution

牧云@^-^@ 提交于 2019-12-17 02:41:32
问题 I would like to generate some pseudorandom numbers and up until now I've been very content with the .Net library's Random.Next(int min, int max) function. PRNGs of this variety are supposed to be using a Uniform distribution, but I would very much like to generate some numbers using an Exponential Distribution. I'm programming in C#, although I'll accept pseudocode or C++, Java or the like. Any suggestions / code snippets / algorithms / thoughts? 回答1: Since you have access to a uniform random

How to generate random numbers with exponential distribution (with mean)?

心不动则不痛 提交于 2019-12-03 12:15:25
问题 I am trying to generate exponentially distributed random number with mean equal to 1. I know how to get random number for normal distribution with mean and standard deviation. We can get it by normal(mean, standard_deviation) , but I don't know how to get random number for exponential distribution. Can anyone help me with this? 回答1: With C++11 the standard actually guarantees that there is a RNG following the requirements of exponential-distribution available in the STL, and fittingly the

How to generate random numbers with exponential distribution (with mean)?

拈花ヽ惹草 提交于 2019-12-03 02:55:29
I am trying to generate exponentially distributed random number with mean equal to 1. I know how to get random number for normal distribution with mean and standard deviation. We can get it by normal(mean, standard_deviation) , but I don't know how to get random number for exponential distribution. Can anyone help me with this? With C++11 the standard actually guarantees that there is a RNG following the requirements of exponential-distribution available in the STL, and fittingly the object-type has a very descriptive name. The mean in an exponentially distributed random generator is

overlaying exponential distribution onto histogram

天涯浪子 提交于 2019-12-02 04:17:25
问题 How can i overlay an exponential distribution on a histogram of time intervals? The histogram looks like an exponential distribution. When I try to create the histogram in a similar way to superimposing a normal curve I get the following: Error in xy.coords(x, y) : 'x' and 'y' lengths differ I can create the histogram on its own which has an x axis from 0 to 70. And I can create an exponential distribution curve on its own but its x axis goes from 0 to 1. I am using hist(t) where t is a list

overlaying exponential distribution onto histogram

心不动则不痛 提交于 2019-12-02 02:40:02
How can i overlay an exponential distribution on a histogram of time intervals? The histogram looks like an exponential distribution. When I try to create the histogram in a similar way to superimposing a normal curve I get the following: Error in xy.coords(x, y) : 'x' and 'y' lengths differ I can create the histogram on its own which has an x axis from 0 to 70. And I can create an exponential distribution curve on its own but its x axis goes from 0 to 1. I am using hist(t) where t is a list of times in seconds for the histogram and curve(dexp(x,rate=0.09)) for the exponential distribution.