问题
I have to get the list of all the unique key constraints and the indexes of a particular database. I am doing something like this:
SELECT * FROM sys.sysobjects WHERE type!='u' AND name LIKE <tablename>
Just wanted to confirm if this was the correct way, or is there a better way of doing the same thing?
回答1:
Since unique constraints are implemented under the covers as indexes, you can get all of this information directly from sys.indexes:
SELECT
[schema] = OBJECT_SCHEMA_NAME([object_id]),
[table] = OBJECT_NAME([object_id]),
[index] = name,
is_unique_constraint,
is_unique,
is_primary_key
FROM sys.indexes
-- WHERE [object_id] = OBJECT_ID('dbo.tablename');
To repeat for all databases (and presumably without the filter for a specific table):
DECLARE @sql NVARCHAR(MAX) = N'';
SELECT @sql += 'SELECT db = ' + name + ',
[schema] = OBJECT_SCHEMA_NAME([object_id]),
[table] = OBJECT_NAME([object_id]),
[index] = name,
is_unique_constraint,
is_unique,
is_primary_key
FROM ' + QUOTENAME(name) + '.sys.indexes;'
FROM sys.databases
WHERE database_id BETWEEN 4 AND 32766;
EXEC sp_executesql @sql;
回答2:
A unique constraint is represented in sys.objects by the type 'UQ'
select name from sys.objects where type='UQ'
To get the indexes
select i.name, o.name from sys.indexes i
inner join sys.objects o on i.object_id= o.object_id
回答3:
You can get the unique key constraints, and indexes from sys.indexes. Specifically, unique constraints:
select * from sys.indexes where is_unique_constraint = 1
回答4:
The other answers did not return complete lists for me. This query worked for me to return all unique indexes that are not primary keys or system tables:
select i.name as index_name, o.name as object_name
from sys.indexes i
join sys.objects o on i.object_id= o.object_id
where (i.is_unique_constraint = 1 OR i.is_unique = 1)
and i.is_primary_key = 0 and o.type_desc <> 'SYSTEM_TABLE'
来源:https://stackoverflow.com/questions/11941118/get-the-list-of-unique-constraints-and-indexes-in-a-database