mysqli bind_param() expected to be a reference, value given

问题:

Can't figure out, whats causing error Parameter 3 to mysqli_stmt::bind_param() expected to be a reference, value given in...

PDO $query = "INSERT INTO test (id,row1,row2,row3) VALUES (?,?,?,?)"; $params = array(1,"2","3","4"); $param_type = "isss"; $sql_stmt = mysqli_prepare ($mysqli, $query); call_user_func_array('mysqli_stmt_bind_param', array_merge(array($sql_stmt, $param_type), $params)); mysqli_stmt_execute($sql_stmt); 

Also tried OOP

OOP $insert_stmt = $mysqli->prepare($query); array_unshift($params, $param_type); call_user_func_array(array($insert_stmt, 'bind_param'), $params); $insert_stmt->execute(); 

But same error, only that now Parameter 2 is causing problem.

So, what's wrong with $params? I need $params to be an array of values.

回答1:

UPDATE

This answer is outdated. Please use the spread operator in newer PHP versions like answered by Stacky.

From php docu:

Care must be taken when using mysqli_stmt_bind_param() in conjunction with call_user_func_array(). Note that mysqli_stmt_bind_param() requires parameters to be passed by reference, whereas call_user_func_array() can accept as a parameter a list of variables that can represent references or values.

And on the page mysqli-stmt.bind-param you have different solutions:

For example:

call_user_func_array(array($stmt, 'bind_param'), refValues($params));  function refValues($arr){     if (strnatcmp(phpversion(),'5.3') >= 0) //Reference is required for PHP 5.3+     {         $refs = array();         foreach($arr as $key => $value)             $refs[$key] = &$arr[$key];         return $refs;     }     return $arr; } 

回答2:

Introduced in PHP 5.6, you can use the ... operator ("spread operator") to achieve the same result with less trouble:

mysqli_stmt_bind_param($sql_stmt, $param_type, ...$params); 

回答3:

Dunno why word 'PDO' in the code but that's the only right word in it. Use PDO, and face not a problem you have with mysqli prepared statements:

$query = "INSERT INTO test (id,row1,row2,row3) VALUES (?,?,?,?)"; $params = array(1,"2","3","4"); $stmt = $pdo->prepare($query); $stmt->execute($params); 

Just look at this clean and concise code and compare it with one you need with mysqli prepared statements.

文章来源: mysqli bind_param() expected to be a reference, value given