BAT/CMD file to remove drive letters using DISKPART

问题:

I am trying to write a batch file to remove drive letters that are assigned to partitions with no file system. I cannot use wmi since it is being used in a WinPE recovery environment.

DISKPART> list volume    Volume ###   Ltr  Label          Fs              Type         Size      Status     Info   ----------   ---  -----------   -----      ----------      -------   ---------  --------   Volume 0       K                              DVD-ROM         0 B   No Media   Volume 1       L                              DVD-ROM         0 B   No Media   Volume 2       C   Windows 7    NTFS        Partition        80 GB  Healthy      System   Volume 3       D                            Partition       500 GB  Healthy      System   Volume 4                                    Partition       500 GB  Healthy      System   Volume 5       E                            Partition       500 GB  Healthy      System  DISKPART> exit   For loop = 0 to 5 If Type[loop]="Partition" then     If Ltr[loop]<>"" then         If Fs[loop]="" then             SELECT VOLUME loop             REMOVE LETTER Ltr[loop]        End If     End If End If Next 

This is what I have so far...

@echo off  For /F "Tokens=1,2,3,4,5,6*" %%I In ('echo.list volume^|diskpart.exe^|findstr /I /R /C:"Volume [0-9]"') Do ( echo %%I %%J %%K %%L %%M %%N if "%%N"=="Partition" ( if NOT "%%K"=="" ( if "%%M"=="" ( echo mountvol %%K: /D ) ) ) ) 

The above does not work because the output is space delimited and some blank columns mess up the parsing.

Another attempt, I think this works, but it could be better

@echo off cd /d "%~dp0" for /f "skip=8 tokens=*" %%A in ('echo.list volume && echo.exit^|%windir%\system32\diskpart.exe') do ( echo.%%A ^^| find /I "       Partition" >nul && ( for /f "tokens=3 delims= " %%B in ("%%A") do (echo.mountvol %%B: /D) ) ) pause exit 

Do you know why the above needs 2 ^ before the | (pipe) ?

@echo off for /f "skip=9 tokens=*" %%A in ('echo.list volume^| diskpart') do ( echo."%%A"| find /I "       Partition" >nul && ( for /f "tokens=3 delims= " %%B in ("%%A") do (echo.mountvol %%B: /D & mountvol %%B: /D) ) ) pause exit 

The above seems to be working now, I had to put double quotes around the echo."%%A" and then I removed the 2 ^ before the pipe.

@echo off setlocal enableDelayedExpansion set "validDrives=;C;D;E;F;G;H;I;J;K;L;M;N;O;P;Q;R;S;T;U;V;W;X;Y;Z;" for /f "skip=9 tokens=*" %%A in ('echo.list volume^| diskpart') do ( echo."%%A"| find /I "       Partition" >nul && ( for /f "tokens=3 delims= " %%B in ("%%A") do ( if "!validDrives:;%%~B;=!" neq "!validDrives!" (echo.mountvol %%B: /D & mountvol %%B: /D) ) ) ) pause exit 

The above is my working script, I added some code to validate the drive letter.

If anybody can offer suggestions on how to improve this then please do!

Thanks

回答1:

I may have a much simpler solution for you. Just grab the whole line and use batch sub-strings to pull out the right pieces

@echo off setlocal ENABLEEXTENSIONS ENABLEDELAYEDEXPANSION     for /f "delims=" %%i in ('^         echo list volume ^|^         diskpart ^|^         findstr Volume ^|^         findstr /v ^         /c:"Volume ###  Ltr  Label        Fs     Type        Size     Status     Info"^        ') do (         set "line=%%i"         set letter=!line:~15,1!         set fs=!line:~32,7!         if not "       "=="!fs!" (             if not " "=="!letter!" (                 call :removeVol !letter!             )         )     ) endlocal exit /b  :removeVol     (         echo select volume %1         echo remove letter %1     ) | diskpart exit /b 

The for statement produces of listing of volumes without the column headers or separators.

The do statement does the sub-string operations.

Ensure that you have admin privilege for the diskpart command. I am a bit curious about your WinRE environment. Most of the ones I've worked in did have a minimal WMI instance running, as well as WSH which would make this code much cleaner.

文章来源: BAT/CMD file to remove drive letters using DISKPART