partition

postgresql delete partition tables

巧了我就是萌 提交于 2021-02-19 08:58:10
问题 I'm new at Postgresql and do not exactly know how to manage partition tables. I have partition table based on day. Before inserting data, trigger checks date and put into corresponding child table. eg. 11.15.2014 - insert into table named 11-15-2014_log. 11.16.2014 - insert into table named 11-16-2014_log. Now I want to create function that will drop old child tables, for example, tables older than 90 days. Should I find and drop child table according its tablename (cause it consists date of

get latest data from hive table with multiple partition columns

风流意气都作罢 提交于 2021-02-19 05:36:06
问题 I have a hive table with below structure ID string, Value string, year int, month int, day int, hour int, minute int This table is refreshed every 15 mins and it is partitioned with year/month/day/hour/minute columns. Please find below samples on partitions. year=2019/month=12/day=29/hour=19/minute=15 year=2019/month=12/day=30/hour=00/minute=45 year=2019/month=12/day=30/hour=08/minute=45 year=2019/month=12/day=30/hour=09/minute=30 year=2019/month=12/day=30/hour=09/minute=45 I want to select

SQL to get 2 adjacent actions from the flag

百般思念 提交于 2021-02-11 12:50:26
问题 hope you are doing well! I have an dummy data as below. I want to get 2 adjacent actions from the flag by each user. Here's the chart to describe my thought. Here's what I want: How can I implement SQL(I use Google Bigquery)? Hope someone can light me up. Thanks a million! 回答1: You seem to want lag() . I would leave the "action sequence" as two separate columns: select user, prev_action, action, flag from (select t.*, lag(action) over (partition by user order by sequence) as prev_action from

Reading partition columns without partition column names

半城伤御伤魂 提交于 2021-02-08 03:36:05
问题 We have data stored in s3 partitioned in the following structure: bucket/directory/table/aaaa/bb/cc/dd/ where aaaa is the year, bb is the month, cc is the day and dd is the hour. As you can see, there are no partition keys in the path ( year=aaaa , month=bb , day=cc , hour=dd) . As a result, when I read the table into Spark, there is no year , month , day or hour columns. Is there anyway I can read the table into Spark and include the partitioned column without : changing the path names in s3

how to get names of partition in oracle while i input a date

本小妞迷上赌 提交于 2021-02-07 03:22:27
问题 I have a table with many partitions range. I need to get the name of all partition when I give a date. For eg: if I input date 20/09/2014, it should list all partitions before that given date. create or replace function get_part_name(p_date in date) return varchar2 is d date; retp varchar2(30); mind date:=to_date('4444-01-01','yyyy-mm-dd'); str varchar2(32000); cursor c is select high_value, partition_name p from user_tab_partitions where table_name='TEST'; begin for r in c loop str := r.high

how to get names of partition in oracle while i input a date

£可爱£侵袭症+ 提交于 2021-02-07 03:20:28
问题 I have a table with many partitions range. I need to get the name of all partition when I give a date. For eg: if I input date 20/09/2014, it should list all partitions before that given date. create or replace function get_part_name(p_date in date) return varchar2 is d date; retp varchar2(30); mind date:=to_date('4444-01-01','yyyy-mm-dd'); str varchar2(32000); cursor c is select high_value, partition_name p from user_tab_partitions where table_name='TEST'; begin for r in c loop str := r.high

How to move Amazon S3 objects into partitioned directories

帅比萌擦擦* 提交于 2021-01-29 04:04:24
问题 Take for example an s3 bucket with the following structure with files of the form francescototti_yyyy_mm_dd_hh.csv.gz: For example: francescototti_2019_05_01_00.csv.gz, francescototti_2019_05_01_01.csv.gz, francescototti_2019_05_01_02.csv.gz, ..... francescototti_2019_05_01_23.csv.gz, francescototti_2019_05_02_00.csv.gz Each hourly file is about 30 MB. I would like the final hive table to be partitioned by day stored as orc files. What is the best way to do this? I imagine a few ways,

How can I require node modules across disk partitions?

删除回忆录丶 提交于 2021-01-28 11:31:59
问题 Node.js Version : 14.15.0 OS : Raspbian Scope (install, code, runtime, meta, other?) : require I have a Node program that I run on Raspberry Pi 4. I've recently started using a OTA deployment system called Mender to push updates to my code on remote RPis. Mender creates a partition system that uses two 3.5GB partitions, one as the main and the other as a rollback in the event of a failed deployment. And it has a 3rd partition /data , that is around 20GB in my case, for things that need to be

All ways of partitioning a list into two non-empty lists

僤鯓⒐⒋嵵緔 提交于 2021-01-28 10:14:52
问题 [0.0, 1.0, 2.0, 3.0, 4.0] I have 5 numbers and two groups, left and right. Each number has two choices - it can go left or right. I need a list that contains all partitioning of the list [0,1,2,3,4] into two non empty parts. For example: [([0], [1,2,3,4]), ([0,1], [2,3,4]), ...,] Note that there are a total of (2^5 -2)/2 partitioning - order doesn't matter and I don't want repeats. Meaning I don't want something like this (if my list was [1,2,3,4]): [] [1, 2, 3, 4] [1] [2, 3, 4] [2] [1, 3, 4]

All ways of partitioning a list into two non-empty lists

孤街浪徒 提交于 2021-01-28 10:12:53
问题 [0.0, 1.0, 2.0, 3.0, 4.0] I have 5 numbers and two groups, left and right. Each number has two choices - it can go left or right. I need a list that contains all partitioning of the list [0,1,2,3,4] into two non empty parts. For example: [([0], [1,2,3,4]), ([0,1], [2,3,4]), ...,] Note that there are a total of (2^5 -2)/2 partitioning - order doesn't matter and I don't want repeats. Meaning I don't want something like this (if my list was [1,2,3,4]): [] [1, 2, 3, 4] [1] [2, 3, 4] [2] [1, 3, 4]