Comparing two arrays of objects, and exclude the elements who match values into new array in JS

问题:

here is my use case in JavaScript:

I have two arrays of objects which have properties that match (id & name).

var result1 = [     {id:1, name:'Sandra', type:'user', username:'sandra'},     {id:2, name:'John', type:'admin', username:'johnny2'},     {id:3, name:'Peter', type:'user', username:'pete'},     {id:4, name:'Bobby', type:'user', username:'be_bob'} ];  var result2 = [     {id:2, name:'John', email:'johnny@example.com'},     {id:4, name:'Bobby', email:'bobby@example.com'} ];  var props = ['id', 'name']; 

My goal is to have another array of objects containing only the elements which did not match. Like this:

var result = [     {id:1, name:'Sandra'},     {id:3, name:'Peter'} ]; 

I know that there is a way of doing this by going from result1 compare each object with the objects of result2, then compare their keys, and if did'n match, put the values in another object then push it in new array, but I wonder is there any more elegant way, like using lo-dash or underscore or something similar.

Thank you!

回答1:

Just using the Array iteration methods built into JS is fine for this:

var result1 = [     {id:1, name:'Sandra', type:'user', username:'sandra'},     {id:2, name:'John', type:'admin', username:'johnny2'},     {id:3, name:'Peter', type:'user', username:'pete'},     {id:4, name:'Bobby', type:'user', username:'be_bob'} ];  var result2 = [     {id:2, name:'John', email:'johnny@example.com'},     {id:4, name:'Bobby', email:'bobby@example.com'} ];  var props = ['id', 'name'];  var result = result1.filter(function(o1){     // filter out (!) items in result2     return !result2.some(function(o2){         return o1.id === o2.id;          // assumes unique id     }); }).map(function(o){     // use reduce to make objects with only the required properties     // and map to apply this to the filtered array as a whole     return props.reduce(function(newo, name){         newo[name] = o[name];         return newo;     }, {}); });  document.body.innerHTML = '
' + JSON.stringify(result, null, 4) +         '
';

If you are doing this a lot, then by all means look at external libraries to help you out, but it's worth learning the basics first, and the basics will serve you well here.

回答2:

The same result can be achieved using Lodash.

var result1 = [     {id:1, name:'Sandra', type:'user', username:'sandra'},     {id:2, name:'John', type:'admin', username:'johnny2'},     {id:3, name:'Peter', type:'user', username:'pete'},     {id:4, name:'Bobby', type:'user', username:'be_bob'} ];  var result2 = [     {id:2, name:'John', email:'johnny@example.com'},     {id:4, name:'Bobby', email:'bobby@example.com'} ];  var result3 = _(result1)          .differenceBy(result2, 'id', 'name')         .map(_.partial(_.pick, _, 'id', 'name'))         .value();  console.log(result3);

You can get the desired result applying a difference between both arrays using the properties "id" and "name" as a way to "link" elements between them. If any of those properties are different, the elements are considered different (improbably in your case because id seems to be unique).

Lastly, you have to map the result in order to "omit" the undesired properties of the object.

Hope it helps.

回答3:

I have searched a lot for a solution in which I can compare two array of objects with different attribute names (something like a left outer join). I came up with this solution. Here I used Lodash. I hope this will help you.

var Obj1 = [     {id:1, name:'Sandra'},     {id:2, name:'John'},    ];  var Obj2 = [     {_id:2, name:'John'},     {_id:4, name:'Bobby'} ];  var Obj3 = lodash.differenceWith(Obj1, Obj2, function (o1, o2) {     return o1['id'] === o2['_id'] });  console.log(Obj3); //  {id:1, name:'Sandra'} 

回答4:

Check out difference and xor in lodash.

回答5:

well, this using lodash or vanilla javascript it depends on the situation.

but for just return the array that contains the duplicates it can be achieved by the following, offcourse it was taken from @1983

var result = result1.filter(function (o1) {     return result2.some(function (o2) {         return o1.id === o2.id; // return the ones with equal id    }); }); // if you want to be more clever... let result = result1.filter(o1 => result2.some(o2 => o1.id === o2.id)); 

回答6:

Here is another solution using Lodash:

var _ = require('lodash');  var result1 = [     {id:1, name:'Sandra', type:'user', username:'sandra'},     {id:2, name:'John', type:'admin', username:'johnny2'},     {id:3, name:'Peter', type:'user', username:'pete'},     {id:4, name:'Bobby', type:'user', username:'be_bob'} ];  var result2 = [     {id:2, name:'John', email:'johnny@example.com'},     {id:4, name:'Bobby', email:'bobby@example.com'} ];  // filter all those that do not match var result = types1.filter(function(o1){     // if match found return false     return _.findIndex(types2, {'id': o1.id, 'name': o1.name}) !== -1 ? false : true; });  console.log(result); 

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