I have a list with an order of insertion. I want to paginate the results using the same order. As you can see currently the output will be a different order.
following_companies_list_data = Company.query.filter(Company.id.in_(['2', '24', '1', '7', '373'])).paginate( page, per_page=10, error_out=False) companies = following_companies_list_data.items for i in companies: print i.id 7 24 373 2 1 related question
Solution based on this answer from related question
company_ids = ['2', '24', '1', '7', '373'] order_expressions = [(Company.id==i).desc() for i in company_ids] query = Company.query.filter(Company.id.in_(company_ids)).order_by(*order_expressions) following_companies_list_data = query.paginate(page, per_page=10, error_out=False) Also you can use idx function from intarray module
from sqlalchemy import func company_ids = ['2', '24', '1', '7', '373'] query = Company.query.filter(Company.id.in_(company_ids)).order_by(func.idx(company_ids, Company.id)) following_companies_list_data = query.paginate(page, per_page=10, error_out=False) I think the easiest way to do this is to paginate your list of IDs before even querying:
company_ids_page = company_ids[page * 10:(page + 1) * 10] q = Company.query.filter(Company.id.in_(company_ids_page)) Then, reorder companies based on the order of your ids:
companies_map = {c.id: c for c in q} companies = [companies_map[i] for i in company_ids_page] If you need the fancy features of Pagination objects you can probably create a similar class for lists.